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38.162/124.83
= 38.(24)2/(22.3)4.(23)3
= 38.28/28.34.29
=34/29
=81/512
\(\frac{3^8\cdot16^2}{12^4\cdot8^3}\)
\(=\frac{3^8\cdot2^8}{3^4\cdot2^8\cdot2^9}\)
\(=\frac{81}{512}\)
15^3+5.15^2-5^3 / 18^3+6.18^2-6^3
=3375+5.225-125 /5832+6.324-216
=3375+1125-125 /5832+1944-216
=4500-125 /7826-216
=4375 /7610
=875 /1522
mk ko bt viết phần nên viết phần bằng dấu gạch / nhé.mk cx ko bt đúng hay sai đâu nhé
\(\frac{-1}{12}-\left(2\frac{5}{8}-\frac{1}{3}\right)\)
\(=\frac{-1}{12}-\left(\frac{21}{8}-\frac{1}{3}\right)\)
\(=\frac{-1}{12}-\left(\frac{63}{24}-\frac{8}{24}\right)\)
\(=\frac{-1}{12}-\frac{55}{24}\)
\(=\frac{-2}{24}-\frac{55}{24}\)
\(=\frac{-19}{8}\)
\(\frac{28^{15}\cdot3^{17}}{84^{16}}\)
\(=\frac{4^{15}\cdot7^{15}\cdot3^{17}}{4^{16}\cdot7^{16}\cdot3^{16}}\)
\(=\frac{4\cdot1\cdot3}{1\cdot7\cdot1}\)
\(\frac{12}{7}\)
a, \(\left(\frac{1}{5}-\frac{1}{4}\right)^2=\left(\frac{-1}{20}\right)^2=\frac{1}{400}\)
b, \(\left(\frac{5}{3}+\frac{1}{2}\right):\frac{-13}{5}+1\frac{5}{6}\)
=> \(\frac{13}{6}:\frac{-13}{5}+\frac{11}{6}\)
=> \(\frac{13}{6}.\frac{5}{-13}+\frac{11}{6}\)
=> \(\frac{-5}{6}+\frac{11}{6}=\frac{6}{6}=1\)
c, \(\left(\frac{3}{17}\right)^4.\left(\frac{-17}{6}\right)^4\)
=> \(\left(\frac{3}{17}.\frac{-17}{6}\right)^4=\left(\frac{-1}{2}\right)^4=\frac{1}{16}\)
\(\frac{36^4.36^3}{6^{12}}=\frac{36^{4+3}}{\left(6^2\right)^6}=\frac{36^7}{36^6}=36.\)
=36^7/6^12
=(6^2)^7/6^12
=6^14/6^12
=6^2=36