Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot\left(7^8-7^6+7^0\right)\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot5647153\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-45177224\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300--45176678\right\}\)
\(=3^3\cdot5^3-20\cdot45176978\)
\(=3375-903539560\)
\(=-903536185\)
\(626500:\left\{50^2:\left[178-4\cdot\left(35-21:3\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot\left(35-7\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot28\right]\right\}\)
\(=626500:\left\{50^2:\left[178-112\right]\right\}\)
\(=626500:\left\{50^2:66\right\}\)
\(=626500:\frac{1250}{33}\)
\(=\frac{82698}{5}\)
CHUC BAN HOC TOT >.<
32 . 53 - 20{300 - [540 - 23 (78 : 76 + 70)]}
= 9 . 125 - 20{300 - [540 - 8(72 + 70)]}
= 9 . 125 - 20{300 - [540 - 8(49 + 1)]
= 9 . 125 - 20{300 - [540 - 8.50]
= 9 . 125 - 20{300 - [540 - 400]}
= 9 . 125 - 20{300 - 140}
= 9 . 125 - 20. 160
= 1125 - 3200 = -2075
\(=9\cdot125-20\cdot\left\{300-\left[540-8\cdot\left(7^2+1\right)\right]\right\}\)
\(=1125-20\cdot\left\{300-\left[540-8\cdot\left(49+1\right)\right]\right\}\)
\(=1125-20\cdot\left[300-\left(540-8\cdot50\right)\right]\)
\(=1125-20\cdot\left[300-\left(540-400\right)\right]\)
\(=1125-20\cdot\left(300-140\right)\)
\(=1125-20\cdot160\)
\(=1125-3200\)
\(=-2075\)
33.53-20.{300-[540-23(78:76.70)]}
=27.125-20.{300-[540-8.(49.1)]}
=27.125-20.{300-[540-392]}
=3375-20.{300-148}
=3375-20.152
=3375-3040
=335
tk mk nha. nếu đúng
\(a,\dfrac{2}{5}-\dfrac{3}{8}+\dfrac{7}{6}=\dfrac{16}{40}-\dfrac{15}{40}+\dfrac{7}{6}=\dfrac{1}{40}+\dfrac{7}{6}=\dfrac{3}{120}+\dfrac{140}{120}=\dfrac{143}{120}\)
\(b,\dfrac{2}{3}+\left[\dfrac{5}{7}+\left(-\dfrac{2}{3}\right)\right]=\dfrac{2}{3}+\dfrac{5}{7}+\left(-\dfrac{2}{3}\right)=\left[\dfrac{2}{3}+\left(-\dfrac{2}{3}\right)\right]+\dfrac{5}{7}=0+\dfrac{5}{7}=\dfrac{5}{7}\)
\(c,\dfrac{5}{13}+\left(-\dfrac{5}{7}\right)+\left(-\dfrac{20}{41}\right)+\dfrac{8}{13}+\left(-\dfrac{21}{41}\right)\)
\(=\left(\dfrac{5}{13}+\dfrac{8}{13}\right)-\dfrac{5}{7}-\dfrac{20}{41}-\dfrac{21}{41}=-\dfrac{5}{7}\)
a: =48/120-45/120+140/120
=143/120
b: =2/3-2/3+5/7=5/7
c: =5/13+8/13-5/7-20/41-21/41
=-5/7
1) 5 + (-4) = 1
2) (-8) + 2 = -6
3) 8 + (-2) = 6
4) 11 + (-3) = 8
5) (-11) + 2 = -9
6) (-7) + 3 = -4
7) (-5) + 5 = 0
8) 11 + (-12) = -1
9) (-18) + 20 = 2
10) (15) + (-12) = 3
11) (-17) + 17 = 0
12) 16 + (-2) = 14
13) (30) + (-14) = 16
14) (-19) + 20 = 1
15) (-18) + 15 = -3
16) (10) + (-6) = 4
17) (-28) + 14 = -14
18) 15 + (-30) = -15
19) (15) + (-4) = 11
20) (-21) + 11 = -10
21) 8 + (-22) = -14
22) (-15) + 4 = -11
23) (-3) + 2 = -1
24) 17 + (-14) = 3
25) 17 + (-14) = 3
\(-4872-\left(375-4872\right)+300\)
\(=-4872-375+4872+300\)
\(=-75\)
a) A = -6 . ( -8 + 5 - 4 ) : 3 - 7 . |-2| . 3
A = -6 . ( -3 - 4 ) : 3 - 7 . 2 . 3
A = -6 . ( -7 ) : 3 - 14 . 3
A = 42 : 3 - 42
A = 14 - 42
A = -28
Vậy A = -28
b) -4872 - ( 375 - 4872) + 300
= -4872 - 375 + 4872 + 300
= ( -4872 + 4872 ) - ( 375 - 300 )
= 0 - 75
= -75
c) 3 3 . 5 3 – 20 . { 300 – [ 540 – 2 3 ( 7 8 : 7 6 + 7 0 )]}
= 3 3 . 5 3 – 20 . {300 – [ 540 – 2 3 ( 7 2 + 1 )]
= 3 3 . 5 3 – 20 . [ 300 – (540 - 8 . 50)
= 27 . 125 – 20 . [300 – ( 540 - 400 )]
= 3375 – 20 . ( 300 – 140 )
= 3375 – 20 . 160
= 3375 – 3200
= 175