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a) 5 69 : 5 67 – 3 40 : 3 39 = 5 2 – 3 1 = 25 – 3 = 22
b) 155 – [ 2 . ( 30 + 5 – 26 ) . ( 24 : 3 )]
= 155 – [ 2 . 9 . 8 ] = 155 – 144 = 11
c) 37 . 143 + 37 . 57 + 1300
= (37 . 143 + 37.57) + 1300
= 37.(143+ 57) + 1300
= 37. 200 + 1300
= 7400 + 1300
8700.
569 : 567 - 340 : 339
= 1.0035273368606 - 1.0029498525073
= 0.0005774843533
Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
k nhé
Bài 1 :
\(a,569:569-340:339\)
=\(1-\frac{340}{339}\)
=\(-\frac{1}{339}\)
\(b,155-\left[2.\left(30+5-26\right).\left(24:2\right)\right]\)
=\(155-\left[2.9.12\right]\)
=\(155-216\)
=\(-61\)
\(c,37.143+37.57+1300\)
=\(37.\left(143+57\right)+1300\)
=\(37.200+1300\)
=\(7400+1300\)
=\(8700\)
Bài 2 :
\(95-5x=23+18:9\)
=>\(95-5x=23+2=25\)
=>\(5x=95-25=70\)
=>\(x=70:5=14\)
Vậy x ∈ {14}
\(a,\dfrac{3^{43}+3^4}{3^{39}+1}\)
\(=\dfrac{3^4\cdot\left(3^{39}+1\right)}{3^{39}+1}\)
\(=3^4\)
\(=81\)
\(A=\frac{2}{2.5}+\frac{2}{5.8}+\frac{2}{8.11}+...+\frac{2}{17.20}+\frac{2}{20.23}\)
\(\frac{3A}{2}=\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{17.20}+\frac{3}{20.23}\)
\(\frac{3A}{2}=\frac{5-2}{2.5}+\frac{8-5}{5.8}+\frac{11-8}{8.11}+...+\frac{20-17}{17.20}+\frac{23-20}{20.23}\)
\(\frac{3A}{2}=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{17}-\frac{1}{20}+\frac{1}{20}-\frac{1}{23}=\frac{1}{2}-\frac{1}{23}=\frac{21}{46}\)
\(A=\frac{21.2}{46.3}=\frac{7}{23}\)
26.66+34.66-280
= 66.(26+34)-280
=66.60 -280
= 3960-280
= 3680
= -0,1368920138
5,774843533*10-04