Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Mình biết nè ! ^v^
\(8^{12}=\left(8^3\right)^4=512^4\)
\(12^8=\left(12^2\right)^4=144^4\)
\(512^4>144^4\)
\(=>8^{12}>12^8\)
\(8^{12}=\left(8^3\right)^4=512^4\)
\(12^8=\left(12^2\right)^4=144^4\)
Vì \(512^4>144^4\)
\(\Rightarrow8^{12}>12^8\)
Ta có: \(8^{12}=\left(8^6\right)^2=262144^2\)
\(12^8=\left(12^4\right)^2=20736^2\)
Vì \(20736^2< 262144^2\) => \(12^8< 8^{12}\)
Vậy \(12^8< 8^{12}\)
1,-(4+7)=(-4-7)
2,-(12-25)=(-12+25)
3,-(-8+7)=(8-7)
4,+(-15-4)=(-15-4)
5,+(23-12)=(23-12).
\(\dfrac{-12}{310}\text{ }và\text{ }\dfrac{8}{-36}\\ Có:310=2\cdot5\cdot31\\ 36=2^2\cdot3^2\\ \Rightarrow BCNN_{\left(310;36\right)}=2^2\cdot3^2\cdot5\cdot31=5580\\ \Rightarrow\dfrac{-12}{310}=\dfrac{-216}{5580}\\ \dfrac{8}{-36}=\dfrac{1240}{-5580}\\ mà\text{ }\dfrac{-216}{5580}>\dfrac{1240}{-5580}\\ Vậy\text{ }\dfrac{-12}{310}>\dfrac{8}{-36}\)
\(25^{12}=\left(5^2\right)^{12}=5^{24}\)
\(125^8=\left(5^3\right)^8=5^{24}\)
Do \(5^{24}=5^{24}\)
\(\Rightarrow25^{12}=125^8\)
Ta có : 4912 = 724 = 3438
Vì 10 < 343
=> 108 < 3438
Vậy 108 < 4912
a) \(\dfrac{7}{12}< \dfrac{7+1}{12+1}< \dfrac{78}{13}\Rightarrow\dfrac{7}{12}< \dfrac{8}{13}\)
b) \(-4,25=-\dfrac{425}{100}=-\dfrac{17}{4}=-\dfrac{34}{8}< -\dfrac{28}{8}\Rightarrow-4,25< -\dfrac{28}{8}\)
c) \(-0,33>-0,5=-\dfrac{1}{2}=-\dfrac{19}{38}\Rightarrow-0,33>-\dfrac{19}{38}\)
d) \(\dfrac{11}{13}< \dfrac{11+2}{13+2}=\dfrac{13}{15}\Rightarrow\dfrac{11}{13}< \dfrac{13}{15}\Rightarrow-\dfrac{11}{13}>-\dfrac{13}{15}\)
Trl :
\(8^{12}\)=\(12^8\)
HokT~
trl
812 =128
hok tot
nha