Question

[Nguyen Le Trung]

So sánh: \(A=\frac{10^8+2}{10^8-1}\) và \(B=\frac{10^8}{10^8-3}\)

Answer 1

[Đinh Tuấn Việt]

\(A=\frac{10^8+2}{10^8-1}=\frac{10^8-1+3}{10^8-1}=1+\frac{3}{10^8-1}\)

\(B=\frac{10^8}{10^8-3}=\frac{10^8-3+3}{10^8-3}=1+\frac{3}{10^8-3}\)

Vì \(\frac{3}{10^8-1}

Answer 2

[✓ ℍɠŞ_ŦƦùM $₦G ✓]

\(\frac{10^8+2}{10^8-1}=1+\frac{3}{10^8-1}