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24 tháng 6 2018
ta có: 100334 = (102)334 = 10668
1000300= (103)300= 10900
=> 10668 < 10900
=> 100334 < 1000300
24 tháng 6 2018
Ta có:
100334 = ( 102)334= 10 668
1000300 = (103) 300= 10900
Ta có: 10668 < 10900
=> 100 334< 1000300
NH
0
14 tháng 1 2023
Bài 1:
a: Sửa đề: 1/3^200
1/2^300=(1/8)^100
1/3^200=(1/9)^100
mà 1/8>1/9
nên 1/2^300>1/3^200
b: 1/5^199>1/5^200=1/25^100
1/3^300=1/27^100
mà 25^100<27^100
nên 1/5^199>1/3^300
L
2
19 tháng 12 2021
^$@*&^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$%$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%$%$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$%%%%%%%%$%%$%$%$%$%%%%%%%%%%%%%%%%%%454%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%$%%%%%%%%%%%%$%$%%$$%$%$%$%$%$%$%$%$
14 tháng 6 2021
Bài 1:
a) \(\dfrac{-17}{36}\) và \(\dfrac{23}{-48}\)
\(\dfrac{-17}{36}=\dfrac{-17.4}{36.4}=\dfrac{-68}{144}\)
\(\dfrac{23}{-48}=\dfrac{-23}{48}=\dfrac{-23.3}{144.3}=\dfrac{-69}{144}\)
Vì \(\dfrac{-68}{144}>\dfrac{-69}{144}\) nên \(\dfrac{-17}{36}>\dfrac{23}{-48}\)
b) \(\dfrac{-1}{3}\) và \(\dfrac{2}{5}\)
Vì \(\dfrac{-1}{3}\) là số âm mà \(\dfrac{2}{5}\) là số dương nên \(\dfrac{-1}{3}< \dfrac{2}{5}\)
c) \(\dfrac{2}{7}\) và \(\dfrac{5}{4}\)
Vì \(\dfrac{2}{7}< 1\) mà \(\dfrac{5}{4}>1\) nên \(\dfrac{2}{7}< \dfrac{5}{4}\)
d) \(\dfrac{267}{-268}\) và \(\dfrac{-1347}{1343}\)
\(\dfrac{267}{-268}=\dfrac{-267}{268}=\dfrac{-267.449}{268.449}=\dfrac{-119883}{120332}\)
\(\dfrac{-1347}{1343}=\dfrac{-1347.89}{1343.89}=\dfrac{-119883}{119527}\)
Vì \(\dfrac{-119883}{120332}>\dfrac{-119883}{119527}\) nên \(\dfrac{267}{-268}>\dfrac{-1347}{1343}\)
14 tháng 6 2021
Bài 2:
\(\dfrac{5}{2}-\left(1\dfrac{3}{7}-0,4\right)=\dfrac{5}{2}-\dfrac{10}{7}-\dfrac{2}{5}=\dfrac{47}{70}\)
KD
3
23 tháng 8 2023
1) \(5^{199}< 5^{200}=25^{100}\)
\(3^{300}=27^{100}>25^{100}\)
\(\Rightarrow3^{300}>5^{199}\)
\(\Rightarrow\dfrac{1}{3^{300}}< \dfrac{1}{5^{199}}\)
2) a) \(107^{50}=\left(107^2\right)^{25}=11449^{25}\)
\(73^{75}=\left(73^3\right)^{25}=389017^{25}>11449^{25}\)
\(\Rightarrow107^{50}< 73^{75}\)
b) \(54^4< 5^{12}< 21^{12}\Rightarrow54^4< 21^{12}\)
LC
17 tháng 8 2015
\(\left(\frac{3}{8}\right)^5=\frac{243}{8^5}>\frac{125}{8^5}>\frac{125}{9^5}=\frac{125}{\left(3^2\right)^5}=\frac{125}{3^{10}}>\frac{125}{3^{15}}=\frac{5^3}{\left(3^5\right)^3}=\left(\frac{5}{243}\right)^3\)
=>\(\left(\frac{3}{8}\right)^5>\left(\frac{5}{243}\right)^3\)
Ta có :3<5
334<443
=>3334<5443
Bạn làm chưa chuẩn rồi!