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a/\(\frac{1212}{1313}=\frac{12x101}{13x101}=\frac{12}{13}\)
Vậy \(\frac{12}{13}=\frac{1212}{1313}\)
b/Ta có:
\(\frac{4}{5}< 1\)
\(\frac{10}{9}>1\)
=>\(\frac{4}{5}< 1< \frac{10}{9}\Rightarrow\frac{4}{5}< \frac{10}{9}\)
c/\(\frac{17}{15}=1+\frac{2}{15}\)
\(\frac{31}{29}=1+\frac{2}{29}\)
Vì \(\frac{2}{15}>\frac{2}{29}\) nên \(\frac{17}{15}>\frac{31}{29}\)
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chú ý: dấu "=>" có nghĩa là "suy ra"
(1-3/2014)< (1-3/2017) => 2011/2014<2014/2017 13/27<13/26=1/2 27/53>27/54=1/2 Vì 13/27<1/2<27/53 nên 13/27<27/53 C)phần bù đơn vị 11/15<13/17
(1-3/2014)< (1-3/2017)
=> 2011/2014<2014/2017
13/27<13/26=1/2
27/53>27/54=1/2
Vì 13/27<1/2<27/53 nên 13/27<27/53
c)phần bù đơn vị 11/15<13/17
a) \(\dfrac{25}{37}\times\dfrac{18}{29}+\dfrac{18}{29}\times\dfrac{12}{37}\)
\(=\dfrac{18}{29}\times\left(\dfrac{25}{37}+\dfrac{12}{37}\right)\)
\(=\dfrac{18}{29}\times\dfrac{37}{37}\)
\(=\dfrac{18}{29}\times1\)
\(=\dfrac{18}{29}\)
b) \(\dfrac{31}{85}\times\dfrac{11}{19}+\dfrac{31}{85}\times\dfrac{12}{19}-\dfrac{42}{19}\times\dfrac{31}{85}\)
\(=\dfrac{31}{85}\times\left(\dfrac{11}{19}+\dfrac{12}{19}-\dfrac{42}{19}\right)\)
\(=\dfrac{31}{85}\times\dfrac{-19}{19}\)
\(=\dfrac{31}{85}\times-1\)
\(=-\dfrac{31}{85}\)
c) \(\dfrac{16}{53}:\dfrac{17}{9}-\dfrac{16}{53}:\dfrac{17}{8}\)
\(=\dfrac{16}{53}:\left(\dfrac{9}{17}-\dfrac{8}{17}\right)\)
\(=\dfrac{16}{53}:\dfrac{1}{17}\)
\(=\dfrac{16}{901}\)
c) \(\dfrac{1}{5}\times\dfrac{12}{31}\times\dfrac{4}{3}+\dfrac{19}{31}\times\dfrac{4}{15}\)
\(=\dfrac{4}{15}\times\dfrac{12}{31}+\dfrac{19}{31}\times\dfrac{4}{15}\)
\(=\dfrac{4}{15}\times\left(\dfrac{12}{31}+\dfrac{19}{31}\right)\)
\(=\dfrac{4}{15}\times\dfrac{31}{31}\)
\(=\dfrac{4}{15}\times1\)
\(=\dfrac{4}{15}\)
a: =18/29*(25/37+12/37)
=18/29
b: =31/85(11/19+12/19-42/19)
=-31/85
c; =16/53(9/17+8/17)=16/53
d: =4/15(12/31+19/31)=4/15
2000/2001<1
2001/2002<1
2002/2003<1
...
2015/2016<1
=>2000/2001+2001/2002+2002/2003+2003/2004+...+2015/2016<1+1+1+1+1+...+1=15
Vậy...
a. vì 11/16<1 ; 5/4 > 1
=> 11/16 < 5/4
b. vì 14<15
=> 13/14 > 13/15
c. có : 22/33=2/3 =26/39; 12/13=36/39
=> 12/13>22/33
\(\frac{17}{15}=\frac{493}{435};\frac{31}{29}=\frac{465}{435};493>465=>\frac{17}{15}>\frac{31}{29}\)
\(\frac{17}{15}\)>\(\frac{31}{29}\)