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Đáp án cần chọn là: B
5 11 .7 12 + 5 11 .7 11 5 12 .7 12 + 9.5 11 .7 11 = 5 11 .7 11 ( 7 + 1 ) 5 11 .7 11 ( 5.7 + 9 ) = 8 44 = 2 11 .
Do đó a = 2,b = 11 nên a + b = 13
\(C=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2020}}\\ 2C=1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2019}}\\ 2C-C=\left(1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2019}}\right)-\left(\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2020}}\right)\\ C=1-\dfrac{1}{2^{2020}}=\dfrac{2^{2020}-1}{2^{2020}}\)
Giải:
C=1/2 + 1/2^2 + 1/2^3 + ... + 1/2^2020
2C=1 + 1/2 + 1/2^2 + ... +1/2^2019
2C-C=(1+1/2+1/2^2+...+1/2^2019)-(1/2+1/2^2+1/2^3+...+1/2^2020)
C=1-1/2^2020
Chúc bạn học tốt!
`a) (243756000)/(-487512000)=243756000/(-2.243756000)=1/(-2)=(-1)/2`
`b) (3.16-3.14)/(-12)=(3.2)/(3.(-4))=2/(-4)=(-1)/2`
`c) (-8.4+8.3)/(8.6-8.4)=(-8)/(8.2)=(-1.8)/(2.8)=(-1)/2`
`d) (-15)/(-90)=(-15.1)/(-15.6)=1/6`
a) `(-63)/72 = (-63:9)/(72:9)=(-7)/8`
b) `20/(-140) = (20:20)/(-140:20) = 1/(-7)=(-1)/7`
c) `(3.10)/(5.24) =(3.2.5)/(5.2 .3.4)=1/4`
d) `(6.5-6.2)/(6+3)=18/9=2`
a: \(=\dfrac{20\left(1-12\right)}{30\left(-1-10\right)}=\dfrac{2}{3}\)
b: \(=\dfrac{11^9\cdot3^{18}}{3^{18}\cdot11^{11}}=\dfrac{1}{121}\)
a: \(=\dfrac{20\left(1-12\right)}{30\left(-1-10\right)}=\dfrac{20}{30}=\dfrac{2}{3}\)
b: \(=\dfrac{11^9\cdot3^{18}}{3^{10}\cdot11^{11}\cdot3^8}=\dfrac{1}{121}\)
a: \(\left(a-b-c\right)-\left(-c+b+a\right)-\left(a-b\right)\)
\(=a-b-c+c-b-a-a+b\)
\(=-a-b\)
b: \(a\left(b+c\right)-a\left(b+d\right)-\left(1+ac-ad\right)\)
\(=ab+ac-ab-ad-1-ac+ad\)
=-1
\(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{11}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^2}{3}=\frac{4}{3}\)
còn câu b cậu ạ