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Bài 2:
a: 2/6x5/3=10/18=5/9
b: 11/9x5/10=55/90=11/18
c: 3/9x6/8=1/3x3/4=1/4
d: 4/9x12/16=48/144=1/3
e: 25/15x6/7=5/3x6/7=30/21=10/7
f: 6/10x15/20=90/200=9/20
Bài 1
4/5 x 6/7= 24/35
2/9 x 1/2= 2/18= 1/9
1/2 x 8/3= 8/6= 4/3
7/9 x 6/5= 42/45= 14/15
8/7 x 5/9= 40/63
10/11 x 22/15= 220/165= 4/3
Bài 2
2/6 x 5/3= 1/3 x 5/3=5/9
11/9 x 5/10= 11/9 x 1/2= 11/18
3/9 x 6/8= 1/3 x 3/4 =3/12= 1/4
4/9 x 12/16= 4/9 x 3/4= 12/36= 1/3
25/15 x 6/7= 5/3 x 6/7= 30/21= 10/7
6/10 x 15/20= 3/5 x 3/4= 9/20
a)=2/3-1/3= 1/3
b)=7/5-3/5= 4/5
c)=3/2-1/2= 2/2=1
d)=11/4-3/4= 8/4= 2
\(\frac{3}{4}+\frac{1}{6}=\frac{9+2}{12}=\frac{11}{12}\)
\(\frac{11}{12}-\frac{3}{4}=\frac{11-9}{12}=\frac{2}{12}=\frac{1}{6}\)
\(\frac{11}{12}-\frac{1}{6}=\frac{11-2}{12}=\frac{9}{12}=\frac{3}{4}\)
\(\frac{1}{6}+\frac{3}{4}=\frac{2+9}{12}=\frac{11}{12}\)
a) \(\frac{2}{3}-\frac{3}{9}=\frac{2}{3}-\frac{1}{3}=\frac{2-1}{3}=\frac{1}{3}\)
b) \(\frac{7}{5}-\frac{15}{25}=\frac{7}{5}-\frac{3}{5}=\frac{7-3}{5}=\frac{4}{5}\)
c) \(\frac{3}{2}-\frac{4}{8}=\frac{3}{2}-\frac{1}{2}=\frac{3-1}{2}=\frac{2}{2}=1\)
d) \(\frac{11}{4}-\frac{6}{8}=\frac{11}{4}-\frac{3}{4}=\frac{11-3}{4}=\frac{8}{4}=2\)
\(\dfrac{3}{5}+\dfrac{1}{2}-\dfrac{7}{10}=\dfrac{6}{10}+\dfrac{5}{10}-\dfrac{7}{10}=\dfrac{11}{10}-\dfrac{7}{10}=\dfrac{4}{10}=\dfrac{2}{5}\)
\(\dfrac{4}{7}:\dfrac{8}{11}=\dfrac{4}{7}\times\dfrac{11}{8}=\dfrac{44}{56}=\dfrac{11}{14}\)
1/3 + 1/5 - 1/4 = 17/60
7/8 - (1/4 + 2/5) = 9/40
5/11 - (3/5 - 6/11) = 2/5
\(\dfrac{15}{35}+\dfrac{7}{10}=\dfrac{3}{7}+\dfrac{7}{10}=\dfrac{30}{70}+\dfrac{49}{70}=\dfrac{79}{70}\)
\(\dfrac{27}{72}+\dfrac{11}{24}=\dfrac{3}{8}+\dfrac{11}{24}=\dfrac{9}{24}+\dfrac{11}{24}=\dfrac{20}{24}=\dfrac{5}{6}\)
\(\dfrac{6}{12}+\dfrac{7}{6}=\dfrac{1}{2}+\dfrac{7}{6}=\dfrac{3}{6}+\dfrac{7}{6}=\dfrac{10}{6}=\dfrac{5}{3}\)
a) \(\dfrac{5}{6}-\dfrac{2}{14}\)
\(=\dfrac{5}{6}-\dfrac{1}{7}\)
\(=\dfrac{35}{42}-\dfrac{6}{42}\)
\(=\dfrac{29}{42}\)
b) \(\dfrac{5}{20}-\dfrac{1}{6}\)
\(=\dfrac{1}{4}-\dfrac{1}{6}\)
\(=\dfrac{3}{12}-\dfrac{2}{12}\)
\(=\dfrac{1}{12}\)
c) \(\dfrac{5}{9}-\dfrac{3}{12}\)
\(=\dfrac{5}{9}-\dfrac{1}{4}\)
\(=\dfrac{20}{36}-\dfrac{9}{36}\)
\(=\dfrac{11}{36}\)
d) \(8-\dfrac{4}{6}\)
\(=\dfrac{48}{6}-\dfrac{4}{6}\)
\(=\dfrac{44}{6}=\dfrac{22}{3}\).
a) \(3-\frac{6}{8}-\frac{2}{4}\)
\(=\frac{18}{8}-\frac{6}{8}-\frac{4}{8}\)
\(=\frac{18-6-4}{8}\)
\(=\frac{8}{8}=1\)
b) \(\frac{5}{6}-\frac{1}{2}+2\)
\(=\frac{5}{6}-\frac{3}{6}+\frac{12}{6}\)
\(=\frac{5-3+12}{6}\)
\(=\frac{14}{6}=\frac{7}{3}\)
\(a.3+\frac{6}{8}-\frac{2}{4}\\ =\frac{3}{1}+\frac{6}{8}-\frac{2}{4}\\ =\frac{24}{8}+\frac{6}{8}-\frac{4}{8}\\ =\frac{24+6-4}{8}\\ =\frac{26}{8}\\ =\frac{13}{4}\)
\(b.\frac{5}{6}-\frac{1}{2}+2\\ =\frac{5}{6}-\frac{1}{2}+\frac{2}{1}\\ =\frac{5}{6}-\frac{3}{6}+\frac{12}{6}\\ =\frac{5-3+12}{6}\\ =\frac{14}{6}\\ =\frac{7}{3}\)
1, Rút gọn rồi tính
a) \(\frac{4}{5}+\frac{3}{15}\)
= \(\frac{4}{5}+\frac{1}{5}\)
= \(\frac{5}{5}\)
= \(1\)
b) \(\frac{2}{3}+\frac{32}{24}\)
= \(\frac{2}{3}+\frac{4}{3}\)
= \(\frac{6}{3}\)
= \(2\)
c) \(\frac{5}{6}+\frac{15}{18}\)
= \(\frac{5}{6}+\frac{5}{6}\)
= \(\frac{10}{6}\)
= \(\frac{5}{3}\)
2, Tính rồi rút gọn
a) \(\frac{8}{15}+\frac{2}{3}\)
= \(\frac{8}{15}+\frac{10}{15}\)
= \(\frac{18}{15}\)
= \(\frac{6}{5}\)
b) \(\frac{3}{7}+\frac{4}{8}\)
= \(\frac{24}{56}+\frac{28}{56}\)
= \(\frac{52}{56}\)
= \(\frac{13}{14}\)
11 4 - 6 8 = 11 4 - 3 4 = 8 4 = 2