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A - 4 = 22 +23 + 24 +...+ 210 2(A-4)= 23 + 24 + 25 +...+ 210 2(A-4)-(A-4)=(23 + 24 + 25 +...+ 211 ) - ( 22 +23 + 24 +...+ 210 ) A - 4 = 211 - 22 A = 211 k mình và kết bạn nha.
A=\(4+2^2+2^3+2^4+...+2^{10}\)
A-4=\(2^2+2^3+2^4+....+2^{10}\)
2(A-4)=\(2^3+2^4+2^5+...+2^{11}\)
2(A-4)-(A-4)=\(\left(2^3+2^4+2^5+...+2^{11}\right)-\left(2^2+2^3+2^4+...+2^{10}\right)\)
A-4=\(2^{11}-2^2\)
A=\(2^{11}-2^2+4\)
A=\(2^{11}\)
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Ta có \(3.3^4.3=3^{1+4+1}=3^6\)
\(3.3.2^3.2.6=3.3.2^3.2.2.3=\left(3.3.3\right).\left(2^3.2.2\right)=3^3.2^5\)
\(2^3.2^4.2.8=2^3.2^4.2.2^4=2^{3+4+1+4}=2^{12}\)
\(a.a.a^2.a^3.a^4=a^{1+1+2+3+4}=a^{11}\)
\(x.y.x.y.x.y=x^3.y^3\)
\(3\cdot3^4\cdot3=3^6\)
\(3\cdot3\cdot2^3\cdot2\cdot6=3\cdot3\cdot2^3\cdot2\cdot3\cdot2=3^3\cdot2^5\)
\(2^3\cdot2^4\cdot2\cdot8=2^3\cdot2^4\cdot2\cdot2^3=2^{11}\)
\(a\cdot a\cdot a^2\cdot a^3\cdot a^4=a^{11}\)
\(x\cdot y\cdot x\cdot y\cdot x\cdot y=x^3y^3\)
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\(3\cdot3\cdot3\cdot5\cdot5\cdot5=3^3\cdot5^3\)
a) \(3^5\cdot3^4=3^{5+4}=3^9\)
b) \(5^3\cdot5^5=5^{3+5}=5^8\)
c) \(2^5\cdot2=2^{5+1}=2^6\)
B1:
3.3.3.5.5.5
= 33.53
B2:
a) 35.34 = 35+4=39
b) 53.55 = 53+5 =58
c) 25.2 = 32 . 2 = 64
![](https://rs.olm.vn/images/avt/0.png?1311)
a, a.a.a^2.a^4
=a^8
b, 4^3.2^4.2^5.16
=(2^2)^3.2^4.2^5.2^3
=2^6.2^4.2^5.2^3
=2^18
c, 5^2.5^3.125
=5^2.5^3.5^3
=5^8
d, 3^2.9.81
=3^2.3^2.3^4
=3^8
e, 2^3.2^3.18^2
=2^6.(2.3^2)^2
=2^6.2^2.3^4
=2^8.3^4
a)a.a.a^2.a^4 = a^2.a^2.a^4=a^8
b)4^3.2^4.2^5.16
=(2^2)^3.2^4.2^5.2^4
=2^6.2^4.2^4.2^4
=2^18
c)3^2.9.81
=3^2.3^2.3^4
=3^8
![](https://rs.olm.vn/images/avt/0.png?1311)
M=4+22+23+24+...+220
22+22+23+24+...+220
=>2M=23+23+24+25+...+221
=>2M-M=(23+23+24+25+...+221)-(22+22+23+24+...+220)
=>M=221+23-22-22
=221
M = 4 + 22 + 23 + 24 + ... + 220
2M = 8 + 23 + 24 + ..... + 221
2M - M = (23 - 23) + .... + (220 - 220) + 221 + (8 - 4 - 22)
M = 221
M là lũy thừa của 2 với số mũ là 21
=> ĐPCM
Giải theo trong SGK.
22.33.52.2.3.5.2.3.2.5
=25.35.54