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a, a.a.a^2.a^4
=a^8
b, 4^3.2^4.2^5.16
=(2^2)^3.2^4.2^5.2^3
=2^6.2^4.2^5.2^3
=2^18
c, 5^2.5^3.125
=5^2.5^3.5^3
=5^8
d, 3^2.9.81
=3^2.3^2.3^4
=3^8
e, 2^3.2^3.18^2
=2^6.(2.3^2)^2
=2^6.2^2.3^4
=2^8.3^4
a)a.a.a^2.a^4 = a^2.a^2.a^4=a^8
b)4^3.2^4.2^5.16
=(2^2)^3.2^4.2^5.2^4
=2^6.2^4.2^4.2^4
=2^18
c)3^2.9.81
=3^2.3^2.3^4
=3^8
1) 56 63 . 3 . 2
23 . 32. 100.103
2) lay may tinh bam nha ban.
:-) k nha
1)
a) 5 . 5 . 5 . 5 . 5 . 5 = 56
b) 6 . 6 . 6 . 3 . 2 = 6 . 6 . 6 . 6 = 64
c) 2 . 2 . 2 . 3 . 3 = 23 . 32
d) 100 . 10 . 10 . 10 = 10 . 10 . 10 . 10 . 10 = 105
2)
a) 23 = 2 . 2 . 2 = 8
24 = 2 . 2 . 2 . 2 = 16
25 = 2 . 2 . 2 . 2 . 2 = 32
26 = 2 . 2 . 2 . 2 . 2 . 2 = 64
27 = 2 . 2 . 2 . 2 . 2 . 2 . 2 = 128
28 = 2 . 2 . 2 . 2 . 2 . 2 . 2 . 2 = 256
29 = 2 . 2 . 2 . 2 . 2 . 2 . 2 . 2 . 2 = 512
210 = 2 . 2 . 2 . 2 . 2. . 2 . 2 . 2 . 2 . 2 = 1024
b) 32 = 3 . 3 = 9
33 = 3 . 3 . 3. = 27
34 = 3 . 3 . 3 . 3 = 81
35 = 3 . 3 . 3 . 3 . 3 = 243
c) 42 = 4 . 4 = 16
43 = 4 . 4 . 4 = 64
44 = 4 . 4 . 4 . 4 = 256
d) 52 = 5 . 5 = 25
53 = 5 . 5 . 5 = 125
54 = 5 . 5 . 5 . 5 = 625
e) 62 = 6 . 6 = 36
63 = 6 . 6 . 6 = 216
64 = 6 . 6 . 6 . 6 = 1296
1,
a, \(11.11.11=11^3\)
b,\(55.5.5.13.13=55.5^2.13^2\)
c, \(3^7.3^{10}.3^2=3^{\left(7+10+2\right)}=3^{19}\)
d, \(2^5.2^6.2^7.2.2.2=2^5.2^6.2^7.2^3\)
e, \(2^9:2^3.2^4=2^6.2^4=2^{10}\)
2,
\(4^9:8^5=8\)
\(32^{10}:8^5=4^{10}.8^{10}:8^5=4^{10}.8^5\)
\(9^{15}:27^{10}=9^{15}:9^{10}.3^{10}=9^5.3^{10}\)( tự tính)
3,
Ta có:
\(7^{200}=7^{2.100}=\left(7^2\right)^{100}=49^{100}\)
\(2^{700}=2^{7.100}=\left(2^7\right)^{100}=128^{100}\)
Vì \(128^{100}>49^{100}\)nên \(2^{700}>7^{200}\)
\(3.3^2.3^3.3^4.....3^{50}\)
\(=3^{1+2+3+4+5+....+50}\)
Áp dụng công thức tính dãy số ta có
\(1+2+3+4+...+50=\frac{\left[\left(50-1\right):1+1\right].\left(50+1\right)}{2}=\frac{50.51}{2}=25.51=1275\)
\(\Rightarrow3^{1+2+3+4+...+50}=3^{1275}\)
\(3\cdot3\cdot3\cdot5\cdot5\cdot5=3^3\cdot5^3\)
a) \(3^5\cdot3^4=3^{5+4}=3^9\)
b) \(5^3\cdot5^5=5^{3+5}=5^8\)
c) \(2^5\cdot2=2^{5+1}=2^6\)
B1:
3.3.3.5.5.5
= 33.53
B2:
a) 35.34 = 35+4=39
b) 53.55 = 53+5 =58
c) 25.2 = 32 . 2 = 64
Ta có \(3.3^4.3=3^{1+4+1}=3^6\)
\(3.3.2^3.2.6=3.3.2^3.2.2.3=\left(3.3.3\right).\left(2^3.2.2\right)=3^3.2^5\)
\(2^3.2^4.2.8=2^3.2^4.2.2^4=2^{3+4+1+4}=2^{12}\)
\(a.a.a^2.a^3.a^4=a^{1+1+2+3+4}=a^{11}\)
\(x.y.x.y.x.y=x^3.y^3\)
\(3\cdot3^4\cdot3=3^6\)
\(3\cdot3\cdot2^3\cdot2\cdot6=3\cdot3\cdot2^3\cdot2\cdot3\cdot2=3^3\cdot2^5\)
\(2^3\cdot2^4\cdot2\cdot8=2^3\cdot2^4\cdot2\cdot2^3=2^{11}\)
\(a\cdot a\cdot a^2\cdot a^3\cdot a^4=a^{11}\)
\(x\cdot y\cdot x\cdot y\cdot x\cdot y=x^3y^3\)