Question

[títtt]

rút gọn biểu thức

\(E=\left(a^{12}b^3\right):\left(a^4b^7\right)\)

\(E=\left(a.b^3\right)^4:a^6\)

\(F=\dfrac{\left(a^{\sqrt{3}-1}\right)^{\sqrt{3}+1}}{a^{\sqrt{5}-3}.a^{4-\sqrt{5}}}\)       (a>0)

Answer 1

[Nguyễn Việt Lâm]

\(E=a^{12-4}.b^{3-7}=\dfrac{a^8}{b^4}\)

\(E=a^{4-6}.b^{3.4}=\dfrac{b^{12}}{a^2}\)

\(F=\dfrac{a^{\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)}}{a^{\left(\sqrt{5}-3\right)+\left(4-\sqrt{5}\right)}}=\dfrac{a^2}{a^1}=a\)