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\(a,\dfrac{123123}{363363}=\dfrac{123123:3003}{363363:3003}=\dfrac{41}{121}\\ b,\dfrac{199619961996}{149714971497}=\dfrac{199619961996:100010001}{149714971497:100010001}=\dfrac{1996}{1497}=\dfrac{1996:499}{1497:499}=\dfrac{4}{3}\\ c,\dfrac{1818181818}{8181818181}=\dfrac{1818181818\times909090909}{8181818181\times909090909}=\dfrac{2}{9}\)
ta có 191919/292929= 19/29 nên phân số 191919/292929 rút gọn đc thành 19/29
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Rút gọn phân số:
a)1717/2323 = 17/23
b)123123/123123 = 1
c)262626/272727 = 26/27
d)42424242/43434343 = 42/43
a) \(\frac{5}{6}\)= \(\frac{15}{18}\); b) \(\frac{99}{100}\)< \(\frac{100}{99}\); c ) \(\frac{15}{17}\)> \(\frac{13}{18}\)vì \(\frac{15}{17}\)> \(\frac{15}{18}\)> \(\frac{13}{18}\);
d) \(\frac{222}{333}\)= \(\frac{2}{3}\)\(=1-\frac{1}{3}\); \(\frac{3333}{4444}\)= \(\frac{3}{4}\)= \(1-\frac{1}{4}\); vì \(\frac{1}{3}\)> \(\frac{1}{4}\)nên \(\frac{222}{333}\)< \(\frac{3333}{4444}\)
e) \(\frac{292929}{272727}\)= \(\frac{29}{27}\)= \(1+\frac{2}{17}\); \(\frac{347347}{345345}\)= \(\frac{347}{345}\)= \(1+\frac{2}{345}\)nên \(\frac{292929}{272727}\)> \(\frac{347347}{345345}\)
Lời giải:
$\frac{181818}{272727}=\frac{18}{27}=\frac{2}{3}=0,67$
\(\left(\frac{141414}{272727}+\frac{4044}{9099}\right)\times54\)
= \(\left(\frac{141414:10101}{272727:10101}+\frac{4044:1011}{9099:1011}\right)\times54\)
\(=\left(\frac{14}{27}+\frac{4}{9}\right)\times54\)
\(=\left(\frac{14}{27}+\frac{4\times3}{9\times3}\right)\times54\)
\(=\frac{14+12}{27}\times54\)
\(=\frac{26}{27}\times54\)
\(=\frac{1404}{27}=52\)
272727/292929=272727 : 10101/292929 : 10101
=27/29
1818181818/8181818181=1818181818 : 909090909/8181818181 : 909090909
= 2/9
CHÚC BẠN HỌC GIỎI
a)27/29