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Ta có:
\(\frac{5}{2^2.3}=\frac{5.2.11}{2^2.3.2.11}=\frac{110}{264}\)
\(\frac{7}{2^3.11}=\frac{7.3}{2^3.11.3}=\frac{21}{264}\)
Ta có:
\(\frac{5}{2^{2.}.3}=\frac{5.2.11}{2^2.3.2.11}=\frac{110}{264}\)
\(\frac{7}{2^3.11}=\frac{7.3}{2^3.11.3}=\frac{21}{264}\)
a)\(\dfrac{-36}{63};\dfrac{56}{63};\dfrac{-30}{63}\)
b)\(\dfrac{110}{264};\dfrac{21}{264}\)
\(a,\)
\(\frac{4}{9}=\frac{4.5}{9.5}=\frac{20}{45}\)
\(\frac{7}{15}=\frac{7.3}{15.3}=\frac{21}{45}\)
\(b,\)
\(\frac{5}{12}=\frac{5.45}{12.45}=\frac{225}{540}\)
\(\frac{7}{15}=\frac{7.36}{15.36}=\frac{252}{540}\)
\(\frac{4}{27}=\frac{4.20}{27.20}=\frac{80}{540}\)
\(\frac{9}{12}=\frac{45}{60};\frac{7}{15}=\frac{28}{60}\)
\(\frac{7}{10}=\frac{98}{140};\frac{3}{4}=\frac{105}{140};\frac{9}{14}=\frac{90}{140}\)
.
Mẫu số chung:\(2^3.3.11=264\)
Quy đồng
\(\frac{5}{2^2.3}=\frac{5.11.2}{2^3.3.11}\)
\(\frac{7}{2^3.11}=\frac{7.3}{2^3.11.3}\)
\(a,\frac{5\cdot6+5\cdot7}{5\cdot8+20}=\frac{\left(5\cdot6+5\cdot7\right)\div2}{\left(5.8+20\right)\div2}=\frac{13}{12}\)
\(\frac{8.9-4.15}{12.7-180}=\frac{12.6-12.5}{12.7-12.15}=\frac{1}{-8}=\frac{-1}{8}\)
\(Ta\)\(co\)\(\frac{13}{12}=\frac{13.2}{12.2}=\frac{26}{24}\)
\(\frac{-1}{8}=\frac{3\left(-1\right)}{3.8}=\frac{-3}{24}\)
Phần b bạn tính ra rồi làm tương tự phần a nha chúc bạn học giỏi!!!
a)MSC: 63. Ta có: \(\frac{-4}{7}\)=\(\frac{-4.9}{7.9}\)=\(\frac{-36}{63}\) ; \(\frac{8}{9}\)=\(\frac{8.7}{9.7}\)=\(\frac{56}{63}\) ; \(\frac{-10}{21}\)=\(\frac{-10.3}{21.3}\)=\(\frac{-30}{63}\)
b) \(\frac{5}{2^2.3}\)=\(\frac{5}{12}\);\(\frac{7}{2^3.11}\)=\(\frac{7}{88}\)
MSC: 264. Ta có: \(\frac{5}{12}\)=\(\frac{5.22}{12.22}\)=\(\frac{110}{264}\) ; \(\frac{7}{88}\)=\(\frac{7.3}{88.3}\)=\(\frac{21}{264}\)