Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(1,\frac{3}{5}\&\frac{1}{2}\)
\(+,\frac{3}{5}=\frac{3.2}{5.2}=\frac{6}{10}\)
\(+,\frac{1}{2}=\frac{1.5}{2.5}=\frac{5}{10}\)
\(2,\frac{4}{7}\&\frac{9}{14}\)
\(+,\frac{4}{7}=\frac{4.2}{7.2}=\frac{8}{14}\)
\(+,\frac{9}{14}=\frac{9}{14}\)
\(3,\frac{2}{3}\&\frac{3}{5}\)
\(+,\frac{2}{3}=\frac{2.5}{3.5}=\frac{10}{15}\)
\(+,\frac{3}{5}=\frac{3.3}{5.3}=\frac{9}{15}\)
Ta có:\(1-\frac{13}{7}=-\frac{6}{7}\)
\(1-\frac{7}{15}=\frac{8}{15}\)
Vì \(-\frac{6}{7}< \frac{8}{15}\)
\(\Rightarrow\frac{13}{7}< \frac{7}{15}\)
a: \(\dfrac{7}{8}=\dfrac{441}{504}\)
\(\dfrac{5}{14}=\dfrac{180}{504}\)
\(\dfrac{4}{63}=\dfrac{32}{504}\)
b: \(\dfrac{2}{5}=\dfrac{72}{180}\)
\(\dfrac{13}{45}=\dfrac{52}{180}\)
\(\dfrac{5}{12}=\dfrac{75}{180}\)
\(\frac{13}{27}>\frac{7}{15}\)
mình cx là fan OP nhé :)
{(1999x2001-1)/(1998+1999x2000)}x7/5
={[(1999x(2000+1)-1]/(1998+1999x2000)}...
={(1999x2000+1999-1)/(1998+1999x2000)}...
={(1999x2000+1998)/(1998+1999x2000)}x7...
=1x7/5
=7/5
a) \(\frac{1}{3},\frac{1}{5},\frac{1}{7}=\frac{35}{105},\frac{21}{105},\frac{15}{105}\)
b) \(\frac{5}{2},\frac{34}{7},\frac{3}{14}=\frac{70}{28},\frac{136}{28},\frac{6}{28}\)
\(\dfrac{7}{14}\)và \(\dfrac{2}{2}\) Ta có: \(\dfrac{2}{2}=\dfrac{2\times7}{2\times7}=\dfrac{14}{14}\)
7/14 giữ nguyên
2/2 = 14/14
MSC là : 14