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a)
\(13x+3=16\\ 13x=16-3\\ 13x=13\\ x=13:13\\ x=1\)
b)
\(2x-138=24:23\\ 2x-138=\dfrac{24}{23}\\ 2x=\dfrac{24}{23}+138\\ 2x=\dfrac{3198}{23}\\ x=\dfrac{3198}{23}:2\\ x=\dfrac{1599}{23}\)
@ Nguyễn Quốc Đạt em bị nhầm đề bài nhé
2\(x\) - 138 = 24 : 23
2\(x\) - 138 = 2
2\(x\) = 2 + 138
2\(x\) = 140
\(x\) = 140 : 2
\(x\) = 70
\(a,x=1\)
\(b,x=3\)
\(c,x=0\)
\(d,x=0,1,2,3,4,....\)
\(e,x=2,4\)
a)x=1
b)x=3
c)x=0
d)0,1,2,3...
e)x=2,4
ai k mình mình k lại cho
( x + 4 ) 2 - 23 = 77
( x + 4 ) 2 = 77 + 23
( x + 4 ) 2 = 100
( x + 4 ) 2 = 102
=> x + 4 = 10
x = 10 - 4
x = 6
Vậy x = 6
(x+4)2-23=77
(x+4)2-23=77-23
(x+4)2 =54
(x+4)2 =54:2
(x+4) =27
x=27-4
x=23
x +(x+1)+(x+2)+......+(x+99)=99
x + x.99 + (1+2+3+...+99) = 99
x.100 + 4950 = 99
x.100 = 99 - 4950
x = - 4851 : 100
x = - 48,51
ta có x +(x+1)+(x+2)+......+(x+99)=99
100x + (1+2+3+...+99)=99
100x + 4950 = 99
100x = -4851
= -48,51
(x + x +.....+ x) +(1 + 2 +....+ 100)
100x + 5050=5750
100x=5750-5050=700
x=700:100=7
Vậy x = 7
(x+1)+(x+2)+(x+3)+.....+(x+100)=x+1+x+2+x+3+...+x+100=1+2+3+...100+100x=5050+100x=5750
100x=5750-5050=700
x=700/100=7
x=7
(x+1)+(x+2)+(x+3)+........+(x+99)=X+1+X+2+X+3+X+4+...+X+98+X+99=(X+X+X+...+X+X)+(1+2+3+4+...+98+99)
(CÓ 99 SỐ X )
= 99X+4950
x+(-23)=(-100)+77
x+(-23)=-(100-77)
x+(-23)=-23
x =-23-(-23)
x =0
x + ( -23) = (-100) + 77
<=> x = (-100) + 77 + 23
<=> x = 0 (t/m)
\(x+\left(x+1\right)+\left(x+12\right)+\left(x+23\right)+\left(x+77\right)+\left(x+88\right)+\left(x+99\right)=370\)
\(\Leftrightarrow x+x+1+x+12+x+23+x+77+x+88+x+99=370\)
\(\Leftrightarrow7x+\left(1+12+23+77+88+99\right)=370\)
\(\Leftrightarrow7x+\left(1+99\right)+\left(12+88\right)+\left(23+77\right)=370\)
\(\Leftrightarrow7x+100+100+100=370\)
\(\Leftrightarrow7x+300=370\)
\(\Leftrightarrow7x=70\)
\(\Leftrightarrow x=10\)
Vậy \(x=10\)
\(x+x+x+x+x+x+x+1+99+12+88+23+77=370\)
\(7x+100+100+100=370\)
\(7x+300=370\)
\(7x=70\)
\(x=10\)