Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) (x - 1) + (x + 2) + (x - 3) + (x + 4) + (x - 5) + (x + 6) = 21
x - 1 + x + 2 + x - 3 + x + 4 + x - 5 + x + 6 = 21
6x + 3 = 21
6x = 21 - 3
6x = 18
x = 18 : 6
x = 3
b) (x - 1) + (x + 3) + (x - 5) + (x + 7) + (x - 9) + (x + 11) = 186
x - 1 + x + 3 + x - 5 + x + 7 + x - 9 + x + 11 = 186
6x + 6 = 186
6x = 186 - 6
6x = 180
x = 180 : 6
x = 30
tính trừ bt nha bạn vế thương thì cũng tĩnh ra xong mới tính nha
a, \(x\) + \(\dfrac{1}{4}\) - \(\dfrac{3}{8}\) = \(\dfrac{7}{12}\)
\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{7}{12}\)
\(x\) = \(\dfrac{7}{12}\) + \(\dfrac{1}{8}\)
\(x\) = \(\dfrac{17}{24}\)
1> a) \(\frac{5}{7}x4:\frac{5}{9}=\frac{5}{7}:\frac{5}{9}x4=\frac{5}{7}x\frac{9}{5}x4=\frac{9}{7}x4=\frac{9x4}{7}=\frac{36}{7}\)
\(b,8x\frac{2}{3}:\frac{1}{2}=8x\frac{2}{3}x\frac{2}{1}=8x2x\frac{2}{3}=16x\frac{2}{3}=\frac{32}{3}\)
\(c,6:\frac{3}{5}-\frac{7}{6}x\frac{6}{7}=6x\frac{5}{3}-1=10-1=9\)
\(\frac{21}{5}x\frac{10}{11}+\frac{57}{11}=\frac{42}{11}+\frac{57}{11}=\frac{99}{11}=9\)
2) a) \(\frac{35}{9}:x=\frac{35}{6}\)
\(x=\frac{35}{9}:\frac{35}{6}\)
\(x=\frac{35}{9}x\frac{6}{35}\)
\(x=\frac{2}{3}\)
b) \(\left(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}\right)x10-X=0\)
\(\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.....+\frac{1}{5}-\frac{1}{6}\right)x10-X=0\)
\(\left(\frac{1}{1}-\frac{1}{6}\right)x10-X=10\)
\(\frac{5}{6}x10-X=0\)
\(X=\frac{5}{6}x10=\frac{25}{3}\)
Đúng nha !!!!
1/a/\(\frac{5}{7}\cdot4:\frac{5}{9}=\frac{20}{7}:\frac{5}{9}=\frac{20}{7}\cdot\frac{9}{5}=\frac{36}{7}\)
b/\(8\cdot\frac{2}{3}:\frac{1}{2}=\frac{16}{3}:\frac{1}{2}=\frac{16}{3}\cdot\frac{2}{1}=\frac{32}{3}\)
c/\(6:\frac{3}{5}-\frac{7}{6}\cdot\frac{6}{7}=6\cdot\frac{5}{3}-1=10-1=9\)
2/a/\(\frac{35}{9}:x=\frac{35}{6}\)
\(x=\frac{35}{9}:\frac{35}{6}=\frac{35}{9}\cdot\frac{6}{35}\)
\(x=\frac{2}{3}\)
b/\(\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}\right)\cdot10-x=0\)
\(\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\right)\cdot10-x=0\)
\(\left(\frac{30}{60}+\frac{10}{60}+\frac{5}{60}+\frac{2}{30}\right)\cdot10-x=0\)
\(\frac{47}{60}\cdot10-x=0\)
\(\frac{47}{6}-x=0\)
\(x=\frac{47}{6}-0\)
\(x=\frac{47}{6}\)
\(\frac{x}{\frac{1}{2}}+\frac{x}{\frac{1}{3}}+x=42\)
\(\Rightarrow\frac{x}{\frac{3}{6}}+\frac{x}{\frac{2}{6}}+\frac{x}{\frac{6}{6}}=42\)
\(\Rightarrow\frac{x}{\frac{3}{6}+\frac{2}{6}+\frac{6}{6}}=42\)
\(\Rightarrow\frac{x}{\frac{11}{6}}=42\)
\(\Rightarrow x=77\)
\(x.\frac{4}{7}+x.\frac{2}{3}+x.\frac{3}{7}=\frac{11}{5}\)
\(\Rightarrow x.\left(\frac{4}{7}+\frac{3}{7}+\frac{2}{3}\right)=\frac{11}{5}\)
\(\Rightarrow x.\frac{5}{3}=\frac{11}{5}\)
\(\Rightarrow x=\frac{33}{25}\)
\(\left(\frac{31}{5}-x\right):\frac{2}{3}=\frac{7}{6}\)
\(\Rightarrow\frac{31}{5}-x=\frac{7}{9}\)
\(\Rightarrow x=\frac{244}{45}\)
\(\frac{4}{3}+\left(x-\frac{3}{5}\right)=\frac{21}{2}\)
\(\Rightarrow\frac{4}{3}+x-\frac{3}{5}=\frac{21}{2}\)
\(\Rightarrow x+\frac{11}{5}=\frac{21}{2}\)
\(\Rightarrow x=\frac{83}{10}=8,3\)
a) \(x:\frac{5}{13}+\frac{2}{26}=1\)
\(x:\frac{5}{13}=1-\frac{2}{26}\)
\(x:\frac{5}{13}=\frac{12}{13}\)
\(x=\frac{12}{13}\times\frac{5}{13}\)
\(x=\frac{60}{169}\)
b) \(x\times\frac{3}{5}=\frac{7}{8}\)
\(x=\frac{7}{8}:\frac{3}{5}\)
\(x=\frac{35}{24}\)
c) \(x=\frac{3}{7}+\frac{4}{21}+\frac{5}{42}\)
\(x=\frac{3\times6}{7\times6}+\frac{4\times2}{21\times2}+\frac{5}{42}\)
\(x=\frac{18}{42}+\frac{8}{42}+\frac{5}{42}=\frac{31}{42}\)
a,
x.2/7.3/4=5/21
x.3/14=5/21
x=5/21:3/14
x=10/9
b,
x.1/2=1/3
x=1/3:1/2
x=2/3
c,
x:4/5=25/8:5/4
x:4/5=5/2
x=5/2.4/5=2
A, x= 5/25 : 3/4 : 2/7 = 14/15
B, x=1/3 : 1/2 = 2/3
C, x=(25/8 : 5/4)x4/5 = 5/2 x 4/5 = 2
x*2/7*3/4=5/21
x*3/14=5/21
x=5/21:3/14
x=10/9