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6 tháng 8 2022
a: =>(3/2-2x):2/3=1/6
=>3/2-2x=1/6x2/3=2/18=1/9
=>2x=25/18
hay x=25/36
b: \(\Leftrightarrow2x-2x+\dfrac{5}{2}-2=x-\dfrac{1}{4}\)
=>x-1/4=1/2
=>x=3/4
c: \(\Leftrightarrow2x-\dfrac{2}{3}-\dfrac{1}{3}x+\dfrac{1}{4}x=0\)
=>23/12x=2/3
=>x=8/23
12 tháng 7 2019
a) \(\frac{x}{x+1}=\frac{1}{2}\)
=> 2x = x + 1
=> 2x - x = 1
=> x = 1
b) \(\frac{x}{2}=\frac{x}{3}\)
=> 3x = 2x
=> 3x - 2x = 0
=> x = 0
c) \(\frac{x+1}{2}=\frac{x+1}{2017}\)
=> \(2017\left(x+1\right)=2\left(x+1\right)\)
=> 2017x + 2017 = 2x + 2
=> 2017x - 2x = 2 - 2017
=> 2015x = -2015
=> x = -2015 : 2015
=> x = -1
i) \(\frac{3}{x}=\frac{x}{2017}\)
=> x2 = 2017.3
=> x2 = 6051
=> \(\orbr{\begin{cases}x=\sqrt{6051}\\x=-\sqrt{6051}\end{cases}}\)
còn lại tự lm
12 tháng 7 2019
\(a,\frac{x}{x+1}=\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{2}.\left(x+1\right)\)
\(\Rightarrow x=\frac{1}{2}x+\frac{1}{2}\)
\(\Rightarrow x-\frac{1}{2}x=\frac{1}{2}\)
\(\Rightarrow\frac{1}{2}x=\frac{1}{2}\)
\(\Rightarrow x=1\)
\(b,\frac{x}{2}=\frac{x}{3}\)
\(\Rightarrow x=\frac{x}{3}.2\)
\(\Rightarrow x=\frac{2x}{3}\)
\(\Rightarrow3x=2x\)
\(\Rightarrow x=0\)
\(c,\frac{x+1}{2}=\frac{x+1}{2017}\)
\(\Rightarrow x+1=\frac{x+1}{2017}.2\)
\(\Rightarrow x+1=\frac{2x+2}{2017}\)
\(\Rightarrow2017x+2017=2x+2\)
\(\Rightarrow2017x-2x=2-2017\)
\(\Rightarrow2015x=-2015\)
\(\Rightarrow x=-1\)
\(i,\frac{3}{x}=\frac{x}{2017}\)
\(\Rightarrow x=3:\frac{x}{2017}\)
\(\Rightarrow x=\frac{6051}{x}\)
\(\Rightarrow x^2=6051\)
\(\Rightarrow x=\sqrt{6051}\)
\(o,\frac{x}{3}=\frac{x+1}{2}\)
\(\Rightarrow x=\frac{x+1}{2}.3\)
\(\Rightarrow x=\frac{3x+3}{2}\)
\(\Rightarrow2x=3x+3\)
\(\Rightarrow-x=3\)
\(\Rightarrow x=-3\)
\(m,\frac{x+1}{2}=\frac{x+2}{3}\)
\(\Rightarrow x+1=\frac{x+2}{3}.2\)
\(\Rightarrow x+1=\frac{2x+4}{3}\)
\(\Rightarrow3x+3=2x+4\)
\(\Rightarrow x=1\)
\(p,\frac{x+1}{2}=x\)
\(\Rightarrow2x=x+1\)
\(\Rightarrow x=1\)
\(m,\frac{2}{x}=\frac{x}{8}\)
\(\Rightarrow x=2:\frac{x}{8}\)
\(\Rightarrow x=\frac{16}{x}\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x=4\)
\(Q,\frac{x^2}{2}=\frac{8}{x^2}\)
\(\Rightarrow x^2=\frac{8}{x^2}.2\)
\(\Rightarrow x^2=\frac{16}{x^2}\)
\(\Rightarrow x^4=16\)
\(\Rightarrow x=2\)
\(r,\frac{x^3}{2}=\frac{32}{x}\)
\(\Rightarrow x^3=\frac{32}{x}.2\)
\(\Rightarrow x^3=\frac{64}{x}\)
\(\Rightarrow x^4=64\)
\(\Rightarrow x=\sqrt[4]{64}\)
XU
5 tháng 1 2020
a, 2x(x-1) - 3x(x+1)
= 2x2 - 2x - 3x2 - 3x
= -x2 - 5x
b, (x-1)(x+2) - (x-2)(x+1)
= x2 + 2x - x - 2 - x2 - x + 2x + 2
= 2x
c, (x-1)2 - (x+2)2
= x2 - 2x + 1 - x2 - 4x + 4
= -6x + 5
d, (2x-1)(2x-1) - 4(x+1)2
= 4x2 - 2x - 2x + 1 - 4(x2 + 2x + 1)
= 4x2 - 2x - 2x + 1 - 4x2 - 8x - 4
= -12x - 3
Chúc bạn học tốt! 
KL
5 tháng 1 2020
a) 2x . (x-1) - 3x . (x+1)
= 2x2 - 2x - 3x2 - 3x
= - x2 - 5x
= - x (x +5)
b) (x - 1) . (x + 2) - (x - 2) . (x + 1)
= x2 + 2x - x - 2 - x2 + x - 2x - 2
= - 4
c) (x - 1)2 - (x + 2)2
= (x - 1 -x -2) (x + 1 + x + 2)
= - 3 (2x + 3)
d) (2x - 1) . (2x - 1) - 4 (x + 1)2
=
19 tháng 6 2017
1, \(\left(x+7\right)\left(3x-1\right)=49-x^2\)
\(\Leftrightarrow\left(x+7\right)\left(3x-1\right)=\left(7-x\right)\left(7+x\right)\)
\(\Leftrightarrow3x-1=7-x\)
\(\Leftrightarrow4x=8\Leftrightarrow x=2\)
Vậy x = 2
2, \(\left(2x+1\right)^2-\left(x-1\right)^2=0\)
\(\Leftrightarrow\left(2x+1-x+1\right)\left(2x+1+x-1\right)=0\)
\(\Leftrightarrow\left(x+2\right)2x=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=0\\2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=0\end{matrix}\right.\)
Vậy x = -2 hoặc x = 0
3, \(\left(1-2x\right)^2-\left(x+3\right)^2+3\left(x+1\right)\left(1-x\right)=8\)
\(\Leftrightarrow\left(1-2x-x-3\right)\left(1-2x+x+3\right)+3\left(x-x^2+1-x\right)=8\)
\(\Leftrightarrow\left(-2-3x\right)\left(4-x\right)-3x^2+3=8\)
\(\Leftrightarrow-8+2x-12x+3x^2-3x^2=5\)
\(\Leftrightarrow-10x=13\)
\(\Leftrightarrow x=-1,3\)
Vậy x = -1,3
4, \(\left(x-3\right)^2-\left(x+3\right)^2=24\)
\(\Leftrightarrow\left(x-3-x-3\right)\left(x-3+x+3\right)=24\)
\(\Leftrightarrow-6.2x=24\)
\(\Leftrightarrow x=-2\)
Vậy x = -2
12 tháng 7 2019
\(a,\frac{1}{3}+\frac{1}{2}:x=\frac{1}{5}\)
\(\Leftrightarrow\frac{1}{2}:x=\frac{1}{5}-\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{2}:x=\frac{3}{15}-\frac{5}{15}\)
\(\Leftrightarrow\frac{1}{2}:x=\frac{-2}{15}\)
\(\Leftrightarrow x=\frac{1}{2}:\frac{-15}{2}=\frac{-15}{4}\)
12 tháng 7 2019
\(b,\frac{1}{3}x+\frac{2}{5}\left[x+1\right]=0\)
\(\Leftrightarrow\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\)
\(\Leftrightarrow\frac{11}{15}x=-\frac{2}{5}\Leftrightarrow x=\frac{-2}{5}:\frac{11}{15}=\frac{-2}{5}\cdot\frac{15}{11}=\frac{-2}{1}\cdot\frac{3}{11}=\frac{-6}{11}\)
NT
1
12 tháng 7 2018
\(4\left(x-1\right)-2\left(x-2\right)=3\)
\(\Leftrightarrow\) \(4x-4-2x+4=3\)
\(\Leftrightarrow\) \(2x=4\)
10 tháng 6 2021
bài 1 .
a. 3 x(5x2 – 2x -1) = 15x3 – 6x2 – 3x
b. (x2+2xy -3)(-xy) = – x3y – 2x2y2 + 3xy
c. 1/2 x2y ( 2x3 – 2/5 xy2 -1 )= x5y – 1/5 x3y3 – 1/2 x2y
bài 2 .
a) 2x^3-3x-5x^3-x^2+x^2=-3x-3x^3
b) 3x^2-6x-5x+5x^2-8x^2+24=-11x+24
c) 3x^3-3/2x^2-x^3-x/2+x/2+2=2x^3-3/2x^2+2
bài 3 .
?????????? bài 3 thì tui ko biết
10 tháng 6 2021
Bài 3 :
\(P=5x\left(x^2-3\right)+x^2\left(7-5x\right)-7x^2\)
\(=5x^3-15x+7x^2-5x^3-7x^2=-15x\)
Thay x = -5 vào biểu thức trên ta được
\(-15.\left(-5\right)=75\)
Vậy x = -5 thì P = 75
vì 12 = 1
=> x - 2 = 1
x = 1 + 2
x = 3
(x-2)2=1
(x-2)2=12
=>x-2=1
=> x=1+2
=> x= 3