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a. |x - 5| + 5 = x
<=> |x - 5| = x - 5
<=> x - 5\(\ge\)0
<=> x\(\ge\)5
b. |x - 5| - 5 = -x
<=> |x - 5| = -x + 5
<=> |x - 5| = - (x - 5)
<=> x - 5\(\le\)0
<=> x\(\le\)5
c. |5 - x| + 5 = x
<=> |5 - x| = -(5-x)
<=> 5 - x \(\le\)0
<=> x\(\ge\)5
( x - 5 )4 = ( x - 5 )6
=> ( x - 5 )6 - ( x - 5 )4 = 0
=> ( x - 5 )4 . [ ( x - 5 )2 - 1 ] = 0
=> ( x - 5 )4 = 0 hoặc ( x - 5 )2 + 1 = 0
TH1 : ( x - 5 )4 = 0 => x - 5 = 0 => x = 5
TH2 : ( x - 5 )2 + 1 = 0
=> ( x - 5 )2 = 1
=> x - 5 = 1 hoặc -1
=> x = 6 hoặc 4
a, \(-5x-1-\dfrac{x}{2}+\dfrac{1}{3}=\dfrac{3}{2}x-5\Leftrightarrow-7x=-\dfrac{13}{3}\Leftrightarrow x=\dfrac{13}{21}\)
b, \(3x-\dfrac{3}{2}-5x-3=-x+\dfrac{1}{5}\Leftrightarrow-x=\dfrac{47}{10}\Leftrightarrow x=-\dfrac{47}{10}\)
a) 5^x-1 = 5^2 + 100
=> 5x-1 = 125 = 53
=> x - 1 = 3
=> x = 4.
b) x10 = x
=> x = {-1;0;1}
2.52.32 + {[2.53 - (5x + 4).5 : (23.3.5)]} = 455
=> 450 + {250 - (5x + 4).5 : 120} = 455
=> 250 - (5x + 4).5 : 120 = 5
=> (5x + 4).5 : 120 = 245
=> (5x + 4).5 = 245.120 = 29400
=> 5x + 4 = 29400 : 5 = 5880
=> 5x = 5876
=> x = 1175,2
`#040911`
\(5^x\cdot5^{x+1}\cdot5^{x+2}=5^9?\)
\(\Rightarrow5^{x+x+1+x+2}=5^9\\ \Rightarrow5^{3x+3}=5^9\\ \Rightarrow3x+3=9\\ \Rightarrow3x=6\\ \Rightarrow x=6\div3\\ \Rightarrow x=2\)
Vậy, `x=2.`
5x . 5x + 1 . 5x + 2 = 59
5x + x + 1 + x + 2 = 59
x + x + 1 + x + 2 = 9
3x + 3 = 9
3x = 9 - 3
x = 6 : 3
x = 2
Vậy x = 2