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a; \(\dfrac{a}{b}\) + \(\dfrac{5}{6}\) = 1 - \(\dfrac{1}{8}\)
\(\dfrac{a}{b}\) + \(\dfrac{5}{6}\) = \(\dfrac{7}{8}\)
\(\dfrac{a}{b}\) = \(\dfrac{7}{8}-\dfrac{5}{6}\)
\(\dfrac{a}{b}=\) \(\dfrac{21}{24}\) - \(\dfrac{20}{24}\)
\(\dfrac{a}{b}=\dfrac{1}{24}\)
b; \(\dfrac{5}{8}-\dfrac{a}{b}\) = \(\dfrac{1}{4}+\dfrac{1}{6}\)
\(\dfrac{5}{8}-\dfrac{a}{b}\) = \(\dfrac{3}{12}+\dfrac{2}{12}\)
\(\dfrac{5}{8}-\) \(\dfrac{a}{b}\) = \(\dfrac{5}{12}\)
\(\dfrac{a}{b}\) = \(\dfrac{5}{8}-\dfrac{5}{12}\)
\(\dfrac{a}{b}\) = \(\dfrac{15}{24}\) - \(\dfrac{10}{24}\)
\(\dfrac{a}{b}\) = \(\dfrac{5}{24}\)
c; \(\dfrac{5}{6}\) - \(\dfrac{1}{4}\) - \(\dfrac{a}{b}\) = \(\dfrac{1}{2}\)
\(\dfrac{10}{12}-\dfrac{3}{12}\) - \(\dfrac{a}{b}\) = \(\dfrac{1}{2}\)
\(\dfrac{7}{12}\) - \(\dfrac{a}{b}\) = \(\dfrac{1}{2}\)
\(\dfrac{a}{b}\) = \(\dfrac{7}{12}\) - \(\dfrac{1}{2}\)
\(\dfrac{a}{b}\) = \(\dfrac{7}{12}-\dfrac{6}{12}\)
\(\dfrac{a}{b}=\dfrac{1}{12}\)
Mình không bày bn cách giải, nhưng sẽ gợi ý:
2 bài tương tự nhau, mẫu gấp nhau 3 lần nhé
\(\frac{2}{3}\times\frac{4}{5}+\frac{4}{5}\times\frac{1}{2}+\frac{4}{5}\times\frac{1}{6}\)
\(=\left(\frac{2}{3}+\frac{1}{2}+\frac{1}{6}\right)\times\frac{4}{5}\)
\(=\frac{4}{3}\times\frac{4}{5}\)
\(=\frac{16}{15}\)
\(a.\frac{1}{5}+\frac{7}{3}+6+5\)
\(=\frac{30}{150}+\frac{350}{150}+\frac{25}{150}+\frac{30}{150}\)
\(=\frac{30+350+25+30}{150}\)
\(=\frac{435}{150}\)
\(b.\frac{9}{10}+\frac{7}{2}+\frac{1}{5}\)
\(=\frac{9}{10}+\frac{35}{10}+\frac{2}{10}\)
\(=\frac{9+35+2}{10}\)
\(=\frac{46}{10}\)
\(c.\frac{9}{2}-\frac{1}{5}\)
\(=\frac{45}{10}-\frac{2}{10}\)
\(=\frac{45-2}{10}\)
\(=\frac{43}{10}\)
\(d.\frac{7}{3}-\frac{5}{21}\)
\(=\frac{49}{21}-\frac{5}{21}\)
\(=\frac{49-5}{21}\)
\(=\frac{44}{21}\)
\(\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right)\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{99}\right)\)
\(=\frac{3}{2}\times\frac{4}{3}\times...\times\frac{100}{99}\)
\(=\frac{100}{2}=50\)