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\(3\cdot15\cdot4+12\cdot19+6\cdot66\cdot2\)
\(=\left(3\cdot4\right)\cdot15+12\cdot19+\left(6\cdot2\right)\cdot66\)
\(=12\cdot15+12\cdot19+12\cdot66\)
\(=12\cdot\left(15+19+66\right)\)
\(=12\cdot100\)
\(=1200\)
\(3.15.4+1.19+6.66.2\)
= ( 3. 4 ) . 15 + 12 .19 - (6.2) . 66
= 12 . 15 + 12 . 19 + 12 . 66
= 12.(15 + 19 + 66)
= 2 . 100
= 1200
quy đồng mẫu số : 3/8 = 9/24 1/6=4/24
15/24 -9/24-4/24=2/24
\(\frac{15}{24}\)- \(\frac{3}{8}\)-\(\frac{1}{6}\)=\(\frac{15}{24}\)-\(\frac{9}{24}\)-\(\frac{4}{24}\)
= \(\frac{15-9-4}{24}\)= \(\frac{2}{24}\)=\(\frac{1}{12}\)
đề bài của bạn ghi j kì vậy sao lại A(2^10+2^9+2^8+2^7):15 là a nhân vs 2^10+2^9+2^8+2^7 ak
5/7-4/19+2/7-15/19-1999/2006=(5/7+2/7)-(4/19+15/19)-1999/2006
=1-1-1999/2006=0-1999/2006=-1999/2006
( 4 . 315 + 5 . 315 ) : 316
= 315.( 4 + 5) : 316
= 315.32:316
= 31=3
\(=\left[3^{15}\left(4+5\right)\right]:3^{16}=\left(3^{15}.3^2\right):3^{16}=3^{17}:3^{16}=3\)
1/10 + 1/20 + 3/30 + 4/40 + 5/50 + 6/60 + 7/70 + 8/80 + 9/90 ( có 9 phân số )
= 1/10 + 1/10 + 1/10 + 1/10 + 1/10 + 1/10 + 1/10 + 1/10 + 1/10 ( có 9 phân số 1/10 )
= 1/10 x 9
= 9/10
\(177:\left[2.\left(4^2-9\right)+3^2.\left(15-10\right)\right]\)
\(=177:\left[2.\left(16-9\right)+3^2.5\right]\)
\(=177:\left[2.7+9.5\right]\)
\(=177:\left[14+45\right]\)
\(=177:59=3\)
\(\frac{11^{26}}{11^{23}}-\frac{3^5}{\left(1^{2020}+2^3\right)-60}\)
\(=11^3-\frac{243}{\left(1+8\right)-60}\)
\(=1331-\frac{243}{-51}=1331-\frac{-81}{17}\)
\(=1331+\frac{81}{17}\)
\(=\frac{22708}{17}\)
1+2-3-4+5+6-7-8+...+111-112+113+114+115
=1+(2-3-4+5)+(6-7-8+9)+....................................+(110-111-112+113)+114+115
=230
= 3/2 + 2/3 + 2/4 + 2/5
= (6/4 + 2/4) + (2/3 + 2/5)
= 8/4 + 16/ 15
= 46/15
\(\dfrac{3}{4}\) + \(\dfrac{1}{3}\) = \(\dfrac{9}{12}\) + \(\dfrac{4}{12}\) = \(\dfrac{13}{12}\)
\(\dfrac{4}{5}\) + \(\dfrac{9}{15}\) : \(\dfrac{1}{15}\)
=\(\dfrac{4}{5}\) + 9
= \(\dfrac{4}{5}\) + \(\dfrac{45}{5}\)
= \(\dfrac{49}{5}\)