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2.3x+2+4.3x+1=10.36
=>2.3.3x+1+4.3x+1=10.36
=>(6+4).3x+1=10.36
=>10.3x+1=10.36
=>3x+1=36
=>x+1=6
=>x=5
A) \(2.3^{x+2}+4.3^{x+1}=10.3^6\)
=> \(2.3.3^{x+1}+4.3^{x+1}=10.3^6\)
=> \(6.3^{x+1}+4.3^{x+1}=10.3^6\)
=> \(\left(6+4\right).3^{x+1}=10.3^6\)
=> \(10.3^{x+1}=10.3^6\)
=> \(3^{x+1}=3^6\)
=> \(x+1=6\)
=> \(x=6-1\)
=> \(x=5\)
Vậy \(x=5.\)
B) \(6.8^{x-1}+8^{x+1}=6.8^{19}+8^{21}\)
=> \(6.8^{x-1}+8^{x-1}.8^2=6.8^{19}+8^{19}.8^2\)
=> \(8^{x-1}.\left(6+8^2\right)=8^{19}.\left(6+8^2\right)\)
=> \(8^{x-1}=8^{19}\)
=> \(x-1=19\)
=> \(x=19+1\)
=> \(x=20\)
Vậy \(x=20.\)
Còn câu c) thì mình đang nghĩ nhé.
Chúc bạn học tốt!
2.3x+2+4.3x+1=10.36
2.3.3x+1+4.3x+1=10.36
6.3x+1+4.3x+1=10.36
10.3x+1=10.36
=>3x+1=36
=>x+1=6 =>x=5
Ai thấy đúng cho mình nha!
\(2.3^{x+2}+4.3^{x+1}=10.3^6\)
\(2.3^{x+2}+2^2.3^{x+1}=2.5.3^6\)
\(2.3^{x+1}\left(3+2\right)=2.5.3^6\)
\(2.3^{x+1}.5=2.5.3^6\)
\(\Rightarrow x+1=6\Rightarrow x=5\)
a, Ta có \(2.3^{x+2}+4.3^{x+1}=3^6.10\)
\(\Rightarrow2.3.3^{x+1}+4.3^{x+1}=3^6.10\)
\(\Rightarrow3^{x+1}.\left(6+4\right)=3^6.10\)
\(\Rightarrow3^{x+1}.10=3^6.10\)
\(\Rightarrow3^{x+1}=3^6\)
\(\Rightarrow x+1=6\)
\(\Rightarrow x=5\)
b,\(\left(\frac{1}{3}+\frac{1}{6}\right).2^{x+4}-2^x=2^{13}-2^{16}\)
\(\Rightarrow\frac{1}{2}.2^{x+4}-2^x=2^{13}.\left(1-2^3\right)\)
\(\Rightarrow2^{x+3}-2^x=2^{13}.\left(1-2^3\right)\)
\(\Rightarrow2^x.\left(2^3-1\right)=2^{13}.\left(1-2^3\right)\)
\(\Rightarrow2^x.\left(2^3-1\right)=-2^{13}.\left(2^3-1\right)\)
\(\Rightarrow2^x=2^{-13}\)
\(\Rightarrow x=-13\)
A ) 2 . 3x+2 + 4 . 33+1 = 36 . 10
2 . 3x . 9 + 4 . 3x . 3 = 729 .10
18 . 3x + 12 . 3x = 243 . 3 . 10
30 . 3x = 243 . 30
3x = 243
x = 5
a, => 2^x = (2^3)^4/(2^4)^3 = 2^12/2^12 = 1 = 2^0
=> x = 0
c, => 4^x = 4^10.(4-3) = 4^10
=> x=10
d, => 2^2.3^x-1 + 2.3^x.9 = 2^2.3^6+2.3^9
=> 2.3^x-1 . (2+3.9) = 2.3^6.(2+3^3)
=> 2.3^x-1 . 27 = 2.3^6 . 27
=> 3^x-1 = 3^6
=> x-1 = 6
=> x = 7
e, => 2^x.(1/3+1/6+2) = 2^11.(2+1/2)
=> 2^x. 5/2 = 2^11. 5/2
=> 2^x = 2^11
=> x = 11
Tk mk nha
c , d giải nốt:
c) 2x + 3/6 = 7x - 13/15
=> (2x + 3) . 15 = (7x - 13) x 6
=> 30x +45 = 42x - 78
=> 30x - 42x = -78 - 45
=> -12x = -123
=> x = 41/4
d) 2-x/4 = 3x - 1/ - 3
=> (2-x) . -3 = 4. (3x - 1)
=> -6 - (-3x) = 12x - 4
(-6) + 4 = 12x - - (-3x)
=> -2 = 9x
=> x = -2/9
1;Ta có\(5.3^x=5.3^4\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
2.Ta có \(9.5^x=6.5^6+3.5^6\)
\(\Rightarrow9.5^x=5^6.\left(6+3\right)\)
\(\Rightarrow9.5^x=9.5^6\)
\(\Rightarrow5^x=5^6\)\
\(\Rightarrow x=6\)
3, Ta có \(2.3^{x+2}+4.3^{x+1}=10.3^6\)
\(\Rightarrow3^{x+1}.\left(2.3+4\right)=10.3^6\)
\(\Rightarrow3^{x+1}.10=10.3^6\)
\(\Rightarrow3^{x+1}=3^6\)
\(\Rightarrow x+1=6\)
\(\Rightarrow x=5\)
a) 5.3x = 5.34
=> 3x=34
=> x=4
b) 9.5x=6.56+3.56
=> 9.5x = (6+3)56
=> 9.5x=9.56
=> 5x=56
=> x=6
c) 2.3x+2 + 4.3x+1 = 10.36
=> 2.3x+1.3 + 4.3x+1 = 10.36
=> 6.3x+1+4.3x+1=10.36
=> (6+4).3x+1=10.36
=> 10.3x+1=10.36
=> 3x+1=36
=> x+1=6
=> x=5
a) \(\Leftrightarrow2.\left(\frac{2.3^x}{3}+3^x.3^2\right)=2.3^6\left(2+3^3\right)\)
\(\Leftrightarrow2.\left(\frac{2.3^x+3.3^x.3^2}{3}\right)=2.3^6.29\)
\(\Leftrightarrow2.\left[\frac{3^x.\left(2+3.3^2\right)}{3}\right]=2.3^6.19\)
\(\Leftrightarrow2.3^{x-1}.29=2.3^6.29\Leftrightarrow3^{x-1}.29=\frac{2.3^6.29}{2}=3^6.29\Leftrightarrow3^{x-1}=\frac{3^6.29}{29}=3^6\)
\(\Leftrightarrow3^{x-1}=3^6\Leftrightarrow x-1=6\Leftrightarrow x=6+1=7\)
vậy x=7 . Chọn mình nha
mấy bài sao tương tự nếu ko biết thì nhắn tin mình chỉ típ nha
a) (2x - 3)2 = 16
=> (2x - 3)2 = 42
=> \(\orbr{\begin{cases}2x-3=4\\2x-3=-4\end{cases}}\)
=> \(\orbr{\begin{cases}2x=7\\2x=-1\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{1}{2}\end{cases}}\)
Vậy ...
b) 2.3x + 2 + 4. 3x + 1 = 10.36
=> 2.3x + 1. 3 + 4.3x + 1 = 10 . 36
=> 6.3x + 1 + 4.3x + 1 = 10.36
=> (6 + 4).3x + 1= 10.36
=> 10.3x + 1= 10.36
=> 3x + 1= 36
=> x + 1 = 6
=> x = 6 - 1
=> x = 5
\(a,\left(2x-3\right)^2=16\)
\(\Rightarrow\left(2x-3\right)^2=4^2\)
\(\Rightarrow2x-3=4\)
\(2x=4+3\)
\(2x=7\)
\(x=7:2\)
\(x=\frac{7}{2}\)