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1.
\(\left|2x-1\right|=-19-x\)
\(2x-1=\pm\left(-19-x\right)\)
TH1:
\(2x-1=-19-x\)
\(2x+x=-19-1\)
\(3x=-20\)
\(x=-\frac{20}{3}\)
TH2:
\(2x-1=19+x\)
\(2x-x=19-1\)
\(x=18\)
Vậy x = -20/3 hoặc x = 18
2.
\(\left|4-3x\right|=2x-10\)
\(4-3x=\pm\left(2x-10\right)\)
TH1:
\(4-3x=2x-10\)
\(-3x-2x=-10-4\)
\(-5x=-14\)
\(x=\frac{14}{5}\)
TH2:
\(4-3x=-2x+10\)
\(-3x+2x=10-4\)
\(x=-6\)
Vậy x = 14/5 hoặc x = -6
3.
\(\left|x\right|=3+2x\)
\(x=\pm\left(3+2x\right)\)
TH1:
\(x=3+2x\)
\(x-2x=3\)
\(x=-3\)
TH2:
\(x=-3-2x\)
\(x+2x=-3\)
\(3x=-3\)
\(x=-1\)
1) \(\left|2x-1\right|=-19-x\)
\(=>\orbr{\begin{cases}-19-x=2x-1\\-19-x=-\left(2x-1\right)\end{cases}=>\orbr{\begin{cases}-19+1=2x+x\\-19-x=-2x+1\end{cases}}}\)
\(=>\orbr{\begin{cases}-18=3x\\-x+2x=1+19\end{cases}=>\orbr{\begin{cases}x=-6\\x=20\end{cases}}}\)
2) \(\left|4-3x\right|=2x-10\)
\(=>\orbr{\begin{cases}2x-10=4-3x\\2x-10=-\left(4-3x\right)\end{cases}=>\orbr{\begin{cases}2x+3x=4+10\\2x-10=-4+3x\end{cases}}}\)
\(=>\orbr{\begin{cases}5x=14\\-10+4=3x-2x\end{cases}=>\orbr{\begin{cases}x=\frac{14}{5}\\x=-6\end{cases}}}\)
3) \(\left|x\right|=3+2x\)
\(=>\orbr{\begin{cases}3+2x=x\\3+2x=-x\end{cases}=>\orbr{\begin{cases}2x-x=-3\\2x+x=-3\end{cases}}}\)
\(=>\orbr{\begin{cases}x=-3\\3x=-3\end{cases}=>\orbr{\begin{cases}x=-3\\x=-1\end{cases}}}\)
Ủng hộ mk nha ^_-
Bài 1:
- \(\dfrac{11}{2}x\) + 1 = \(\dfrac{1}{3}x-\dfrac{1}{4}\)
- \(\dfrac{11}{2}\)\(x\) - \(\dfrac{1}{3}\)\(x\) = - \(\dfrac{1}{4}\) - 1
-(\(\dfrac{33}{6}\) + \(\dfrac{2}{6}\))\(x\) = - \(\dfrac{5}{4}\)
- \(\dfrac{35}{6}\)\(x\) = - \(\dfrac{5}{4}\)
\(x=-\dfrac{5}{4}\) : (- \(\dfrac{35}{6}\))
\(x\) = \(\dfrac{3}{14}\)
Vậy \(x=\dfrac{3}{14}\)
Bài 2: 2\(x\) - \(\dfrac{2}{3}\) - 7\(x\) = \(\dfrac{3}{2}\) - 1
2\(x\) - 7\(x\) = \(\dfrac{3}{2}\) - 1 + \(\dfrac{2}{3}\)
- 5\(x\) = \(\dfrac{9}{6}\) - \(\dfrac{6}{6}\) + \(\dfrac{4}{6}\)
- 5\(x\) = \(\dfrac{7}{6}\)
\(x\) = \(\dfrac{7}{6}\) : (- 5)
\(x\) = - \(\dfrac{7}{30}\)
Vậy \(x=-\dfrac{7}{30}\)
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
1) |2x-1|=-19-x<=> \(\left[\begin{array}{nghiempt}2x-1=-19-x\\2x-1=19+x\end{array}\right.\)=> x=-6 hoặc x=20
2) |4-3x|=2x-10<=>\(\left[\begin{array}{nghiempt}4-3x=2x-10\\4-3x=10-2x\end{array}\right.\)=> x= 14/6 hoặc x=-6
3) |x|=3+2x<=> \(\left[\begin{array}{nghiempt}x=-3-2x\\x=3+2x\end{array}\right.\)=> x=-1 hoặc x=-3
1) - Nếu 2x - 1 < 0 thì -2x + 1 = -19 - x => -x = -20 => x = 20
- Nếu 2x - 1 > 0 thì 2x - 1 = -19 - x => 3x = -18 => x = -6
2) - Nếu 4 - 3x < 0 thì -4 + 3x = 2x - 10 => 6 = -x => x = -6
- Nếu 4 - 3x > 0 thì 4 - 3x = 2x - 10 => 14 = 5x => x = \(\frac{14}{5}\)
3) - Nếu x < 0 thì -x = 3 + 2x => -3x = 3 => x = -1
- Nếu x > 0 thì x = 3 + 2x => -x = 3 => x = -3