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Lời giải:
Dễ tìm được \(A(0,5);B(1,4)\) là hai điểm cực trị của đồ thị \((C)\)
Xét điểm $I(a,b)$ sao cho \(\overrightarrow{IA}+\overrightarrow{IB}+\overrightarrow{IO}=\overrightarrow{0}\)
\(\Leftrightarrow(-a,5-b)+(1-a,4-b)+(-a,-b)=0\)
\(\Rightarrow \left\{\begin{matrix} a=\frac{1}{3}\\ b=3\end{matrix}\right.\Rightarrow \left\{\begin{matrix} \overrightarrow{IA}=(\frac{-1}{3},2)\\ \overrightarrow{IB}=(\frac{2}{3},1)\\ \overrightarrow{IO}=(\frac{-1}{3},-3)\end{matrix}\right.\)
Ta có:
\(P=(\overrightarrow{MI}+\overrightarrow{IO})(\overrightarrow{MI}+\overrightarrow{IA})+(\overrightarrow{MI}+\overrightarrow{IB})(\overrightarrow{MI}+\overrightarrow{IA})+(\overrightarrow{MI}+\overrightarrow {IO})(\overrightarrow{MI}+\overrightarrow{IB})\)
\(P=3MI^2+2\overrightarrow{MI}(\overrightarrow{IA}+\overrightarrow{IB}+\overrightarrow{IC})+\overrightarrow{IA}.\overrightarrow{IO}+\overrightarrow{IA}.\overrightarrow{IB}+\overrightarrow{IB}.\overrightarrow{IO}\)
\(P=3MI^2+\overrightarrow{IA}.\overrightarrow{IO}+\overrightarrow{IA}.\overrightarrow{IB}+\overrightarrow{IB}.\overrightarrow{IO}=3MI^2-\frac{22}{3}\)
Để P min thì \(MI_{\min}\) hay $I$ là hình chiếu của $M$ lên mp \(x+3y+7=0\)
Từ đây dễ dàng tìm được \(M(\frac{-13}{10};\frac{-19}{10})\)
9.
\(f\left(x\right)=F'\left(x\right)=3ax^2+2bx+c\)
\(\left\{{}\begin{matrix}f\left(1\right)=2\\f\left(2\right)=3\\f\left(3\right)=4\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}3a.1+2b.1+c=2\\3a.2^2+2b.2+c=3\\3a.3^2+2b.3+c=4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3a+2b+c=2\\12a+4b+c=3\\27a+6b+c=4\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a=0\\b=\frac{1}{2}\\c=1\end{matrix}\right.\)
\(\Rightarrow F\left(x\right)=\frac{1}{2}x^2+x+1\)
10.
\(F\left(x\right)=\int\frac{x-2}{x^3}dx=\int\left(\frac{1}{x^2}-\frac{2}{x^3}\right)dx=\int\left(x^{-2}-2x^{-3}\right)dx\)
\(=-1.x^{-1}+x^{-2}+C=-\frac{1}{x}+\frac{1}{x^2}+C\)
\(F\left(-1\right)=3\Leftrightarrow1+1+C=3\Rightarrow C=1\)
\(\Rightarrow F\left(x\right)=-\frac{1}{x}+\frac{1}{x^2}+1\)
4.
\(\int\left(x^3-\frac{3}{x^2}+2^x\right)dx=\frac{1}{4}x^4-\frac{3}{x}+\frac{2^x}{ln2}+C\)
5.
\(\int e^{2019x}dx=\frac{1}{2019}\int e^{2019x}d\left(2019x\right)=\frac{1}{2019}e^{2019x}+C\)
6.
\(\int sin2018x.dx=\frac{1}{2018}\int sin2018x.d\left(2018x\right)=-\frac{1}{2018}cos2018x+C\)
7.
\(\int\frac{x^2-x+1}{x-1}dx=\int\left(\frac{x\left(x-1\right)}{x-1}+\frac{1}{x-1}\right)dx=\int\left(x+\frac{1}{x-1}\right)dx=\frac{1}{2}x^2+ln\left|x-1\right|+C\)
8.
\(F\left(x\right)=\int\left(2x+1\right)^3dx=\frac{1}{2}\int\left(2x+1\right)^3d\left(2x+1\right)=\frac{1}{8}\left(2x+1\right)^4+C\)
\(F\left(\frac{1}{2}\right)=4\Leftrightarrow\frac{1}{8}\left(2.\frac{1}{2}+1\right)^4+C=4\Rightarrow C=2\)
\(\Rightarrow F\left(x\right)=\frac{1}{8}\left(2x+1\right)^4+2\Rightarrow F\left(\frac{3}{2}\right)=\frac{1}{8}4^4+2=34\)