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Vì \(\left|x-y\right|\ge0;\left|y+\frac{9}{25}\right|\ge0\Rightarrow\left|x-y\right|+\left|y+\frac{9}{25}\right|\ge0\)
Mà \(\left|x-y\right|+\left|y+\frac{9}{25}\right|=0\)
\(\Rightarrow\left|x-y\right|=0;\left|y+\frac{9}{25}\right|=0\)
\(\left|y+\frac{9}{25}\right|=0\Rightarrow y=\frac{-9}{25}\)
\(\Rightarrow\left|x-y\right|=\left|x-\frac{-9}{25}\right|=0\Rightarrow x=\frac{-9}{25}\)
A= (2^20.3^6.5^6):(5^6.2^9.3^3.2^11)
A= 3^3
A= 27
Bạn thấy đúng thì
a. x-36:18=12-15 b.(3x-2^4).7^3=2.7^4 3x-16=14 x-36 =-3 3x-2^4 =2.7^4:7^3 3x =16+14 x =-3+36 3x-16 =2.7^4-3 3x =30 x =33 3x-16 =2.7 3x =30:3 =10
a)
x-36:18=12-15
<=> x-2=-3
<=> x= -1
Vậy x= -1
b)
(3x- 2^4).7^3=2.7^4
<=> 3x-2^4= 2.7^4:7^3
<=> 3x-16= 2.7
<=> 3x-16= 14
<=> 3x= 30
<=> x=10
Vậy x=10
( x - 1 ) + 1 . ( x + 1 ) : 2 = 780
x . ( x + 1 ) = 1560
x^2 = 1559
=> x = 39
Đúng thì tk nhá , mơn nhìu !!!
~ HOK TỐT ~
\(\left(x-\frac{2}{3}\right)^2=\frac{5}{6}\)
\(\Leftrightarrow x-\frac{2}{3}=\sqrt{\frac{5}{6}}\)
\(\Leftrightarrow x=\frac{4+\sqrt{30}}{6}\)
Đề \(A=\frac{1.98+2.97+3.96+...+98.1}{1.2+2.3+3.4+...+98.99}\) chứ bn!
Bài làm
ta có: 1.98 +2.97 + 3.96 + 98.1
= 1 + (1+2) + ( 1+2+3) +...+ ( 1+2+3+...+ 98)
\(=\frac{1.2}{2}+\frac{2.3}{2}+\frac{3.4}{2}+...+\frac{98.99}{2}\)
\(=\frac{1.2+2.3+3.4+...+98.99}{2}\)
\(\Rightarrow A=\frac{1.98+2.99+3.96+...+98.1}{1.2+2.3+3.4+...+98.99}\)
\(A=\frac{\left(1.2+2.3+3.4+...+98.99\right).\frac{1}{2}}{1.2+2.3+3.4+...+98.99}\)
\(A=\frac{1}{2}\left(đpcm\right)\)
\(\frac{-15}{6}.\frac{8}{-25}\)
\(=\frac{\left(-15\right).8}{6\left(-25\right)}=\frac{-3.4}{3.\left(-5\right)}=\frac{-4}{-5}=\frac{4}{5}\)
-15/6×8/25
120/150
4/5