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27 tháng 6 2018

\(x^2+6x+9=\left(x+3\right)^2\)

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\(x^2-x+\dfrac{1}{4}=\left(x-\dfrac{1}{2}\right)^2\)

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\(x^3+12x^2+48x+64=\left(x+4\right)^3\)

28 tháng 6 2018

1) \(\dfrac{\left(x+5\right)^2+\left(x-5\right)^2}{x^2+25}\)

\(=\dfrac{x^2+10x+25+x^2-10x+25}{x^2+25}\)

\(=\dfrac{2x^2+50}{x^2+25}\)

\(=\dfrac{2\left(x^2+25\right)}{x^2+25}=2\)

2) \(\left(x+3\right)\left(x^2-3x+9\right)-\left(54+x^3\right)\)

\(=x^3+3^3-54-x^3\)

\(=27-54=-27\)

3) \(\left(2x+y\right)^2-\left(y+3x\right)^2\)

\(=4x^2+4xy+y^2-y^2-6xy-9x^2\)

\(=-5x^2-2xy\)

4) \(\left(2x+1\right)^3-\left(2x-1\right)^3-24x^2\)

\(=8x^3+12x^2+6x+1-8x^3+12x^2-6x+1-24x^2\)

\(=2\)

14 tháng 8 2018

a) \(9x^2+6x+1=\left(3x+1\right)^2\)

b)\(x^2-x+\frac{1}{4}=\left(x-\frac{1}{2}\right)^2\)

c)\(x^2y^4-2xy^2+1=\left(xy^2-1\right)^2\)

d) \(x^2+\frac{2}{3}x+\frac{1}{9}=\left(x+\frac{1}{3}\right)^2\)

14 tháng 8 2018

a) 9x2 + 6x + 1 = ( 3x + 1 )2

b) x2 - x + 1/4 = ( x - 1/2)2

c) x2 . y4 - 2xy2 + 1 = ( xy2 - 1 ) 2

d) x2 + 2/3x + 1/9 = (x+1/3)2

19 tháng 8 2019

\(x^2-6x+9=\left(x-3\right)^2\)

\(\frac{1}{4}a^2+2ab+4b^2=\left(\frac{1}{2}a+b\right)^2\)

\(25+10x+x^2=\left(x+5\right)^2\)

\(\frac{1}{9}-\frac{2}{3}y^4+y^8=\left(y^4-\frac{1}{3}\right)^2\)

7 tháng 9 2018

1)\(25x^2y^4+30xy^2z+9z^2=\left(5xy^2+3z\right)^2\)

\(\dfrac{16}{9}x^2+4xyz^2+\dfrac{9}{4}y^2z^4=\left(\dfrac{4}{3}x+\dfrac{3}{2}yz^2\right)^2\)

2)

a)\(\dfrac{9}{25}x^2+\dfrac{12}{35}xy+\dfrac{4}{49}y^2=\left(\dfrac{3}{5}x+\dfrac{2}{7}y\right)^2=\left(\dfrac{3}{5}.5+\dfrac{2}{7}.\left(-7\right)\right)^2=\left(3-2\right)^2=1\)b)\(\dfrac{25}{16}u^4v^2+\dfrac{1}{5}u^2v^3+\dfrac{4}{625}v^4\)

\(=\left(\dfrac{5}{4}u^2v+\dfrac{2}{25}v^2\right)^2=\left(\dfrac{5}{4}.\dfrac{4}{25}.\left(-5\right)+\dfrac{2}{25}.\left(-5\right)^2\right)^2\)

\(=\left(-1+2\right)^2=1\)

14 tháng 8 2018

a) \(9x^2+6x+1=\left(3x\right)^2+2.3x.1+1^2=\left(3x+1\right)^2\)

b) \(x^2-x+\dfrac{1}{4}=x^2-2.\dfrac{1}{2}x+\left(\dfrac{1}{2}\right)^2=\left(x-0,5\right)^2\)

c) \(x^2y^4-2xy^2+1=\left(xy^2\right)^2-2.xy^2.1+1^2=\left(xy^2-1\right)^2\)

d) \(x^2+\dfrac{2}{3}x+\dfrac{1}{9}=x^2+2.x.\dfrac{1}{3}+\left(\dfrac{1}{3}\right)^2=\left(x+\dfrac{1}{3}\right)^2\)

14 tháng 8 2018

a) \(9x^2+6x+1\)

\(=\left(3x\right)^2+2.3x.1+1^2\)

\(=\left(3x+1\right)^2\)

26 tháng 7 2017

a) x2 +4x+4 = ( x + 2 )2

b) 16x2 - 8xy + y2 = ( 4x - y )2

c)9a2 +16b2 - 24ab = ( 3a - 4y ) 2

d) x2 - x + \(\dfrac{1}{4}\)= ( x - \(\dfrac{1}{2}\))2

e) y2 + \(\dfrac{1}{2}y\) + \(\dfrac{1}{16}\) = ( y + \(\dfrac{1}{4}\))2

6 tháng 9 2018

\(25x^2y^4+30xy^2z+9z^2=\left(5xy^2\right)^2+2.5xy^2.3z+\left(3z\right)^2=\left(5xy^2+3z\right)^2\)

\(\frac{16}{9}x^2+4xyz^2+\frac{9}{4}y^2z^4=\left(\frac{4}{3}x\right)^2+2.\frac{4}{3}x.\frac{3}{2}yz^2+\left(\frac{3}{2}yz^2\right)^2=\left(\frac{4}{3}x+\frac{3}{2}yz^2\right)^2\)

\(\frac{9}{25}x^2+\frac{12}{35}xy+\frac{4}{49}y^2=\left(\frac{3}{5}x\right)^2+2.\frac{3}{5}x.\frac{2}{7}y+\left(\frac{2}{7}y\right)^2=\left(\frac{3}{5}x+\frac{2}{7}y\right)^2\)( tự thay vào tính nhé )

\(\frac{25}{16}u^4y^2+\frac{1}{5}u^2+y^3+\frac{4}{625}y^4=\left(\frac{5}{4}u^2y\right)^2+2.\frac{5}{4}u^2y.\frac{2}{25}.y^2+\left(\frac{2}{25}y^2\right)^2=\left(\frac{5}{4}u^2y+\frac{2}{25}y^2\right)^2\)( tự thay vào tính nhé )

Tham khảo nhé~

19 tháng 4 2017

a) x2 + 2x + 1 = x2 + 2.x.1+ 12 = ( x + 1)2

b) 9x2 + y2 + 6xy = (3x)2 + 2.3.x.y + y2 = (3x + y)2

c) 25a2 + 4b2 – 20ab = (5a)2 – 2.5.a.2b. + (2b)2 = (5a – 2b)2

Hoặc 25a2 + 4b2 – 20ab = (2b)2 – 2.2b.5a. + (5a)2 = (2b – 5a)2

d) x2 – x + \(\dfrac{1}{4}\) = x2 – 2.x. \(\dfrac{1}{2}\) + ( \(\dfrac{1}{2}\))22 = ( x - \(\dfrac{1}{2}\) )2

Hoặc x2 – x + \(\dfrac{1}{4}\) = \(\dfrac{1}{4}\) - x + x2 = (\(\dfrac{1}{2}\))2 – 2. \(\dfrac{1}{2}\).x + x2 = (\(\dfrac{1}{2}\) - x)2

19 tháng 4 2017

a) x2 + 2x + 1 = x2+ 2 . x . 1 + 12

= (x + 1)2

b) 9x2 + y2+ 6xy = (3x)2 + 2 . 3 . x . y + y2 = (3x + y)2

c) 25a2 + 4b2– 20ab = (5a)2 – 2 . 5a . 2b + (2b)2 = (5a – 2b)2

Hoặc 25a2 + 4b2 – 20ab = (2b)2 – 2 . 2b . 5a + (5a)2 = (2b – 5a)2

d) x2 – x + 1414 = x2 – 2 . x . 1212 + (12)2(12)2= (x−12)2(x−12)2

Hoặc x2 – x + 1414 = 1414 - x + x2 = (12)2(12)2 - 2 . 1212 . x + x2 = (12−x)2



bài 1:

a) x2 + 10x + 26 + y2 + 2y

= (x2 + 10x + 25) + (y2 + 2y + 1)

= (x + 5)2 + (y + 1)2

b) z2 - 6z + 5 - t2 - 4t

= (z - 3)2 - (t + 2)2

c) x2 - 2xy + 2y2 + 2y + 1

= (x2 - 2xy + y2) + (y2 + 2y + 1)

= (x - y)2 + (y + 1)2

d) 4x2 - 12x - y2 + 2y + 1

= (4x2 - 12x ) - (y2 + 2y + 1)

= ......................................

ok mk nhé!! 4545454654654765765767587876968345232513546546575675767867876876877687975675