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-4/12 + 18/45 - 6/9 - 21/35 + 6/30
= -1/3 + 2/5 - 2/3 - 3/5 + 1/5
= (2/5 - 3/5 + 1/5) - (1/3 + 2/3)
= 0 - 1
= -1
\(=-\frac{1}{3}+\frac{2}{5}-\frac{2}{3}-\frac{3}{5}+\frac{1}{5}\)
\(=\left(-\frac{1}{3}-\frac{2}{3}\right)+\left(\frac{2}{5}-\frac{3}{5}+\frac{1}{5}\right)\)
\(=-1+0\)
\(=-1\)
=.= hk tốt!!
\(-\frac{4}{12}+\frac{18}{45}-\frac{6}{9}-\frac{21}{35}+\frac{6}{30}\)
\(=\frac{-1}{3}+\frac{2}{5}-\frac{1}{3}-\frac{3}{5}+\frac{1}{5}\)
\(=0\)
\(A=\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}\)
\(A=\left(\frac{-5}{7}+\frac{-2}{7}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\frac{-1}{5}\)
\(A=-1+1+\frac{-1}{5}\)
\(A=\frac{-1}{5}\)
\(B=\frac{-4}{12}+\frac{18}{45}+\frac{-6}{9}+\frac{-21}{35}+\frac{6}{30}\)
\(B=\frac{-1}{3}+\frac{2}{5}+\frac{-2}{3}+\frac{-3}{5}+\frac{1}{5}\)
\(B=\left(\frac{-1}{3}+\frac{-2}{3}\right)+\left(\frac{2}{5}+\frac{-3}{5}+\frac{1}{5}\right)\)
\(B=-1+0\)
\(B=-1\)
FF = \(\frac{-4}{12}+\frac{18}{45}+\frac{-6}{9}+\frac{-21}{35}+\frac{6}{30}\)
F = \(\frac{-1}{3}+\frac{6}{15}+\frac{-2}{3}+\frac{-3}{5}+\frac{3}{15}\)
F = \((\frac{-1}{3}+\frac{-2}{3})+(\frac{6}{15}+\frac{3}{15})+\frac{-3}{5}\)
F = \(\frac{-3}{3}+\frac{9}{15}+\frac{-3}{5}\)
F = \(-1+\frac{3}{5}+\frac{-3}{5}\)
F =\(-1+0\)
F = \(-1\)
Vậy F = \(-1\)
\(B=-\frac{1}{3}+\frac{2}{5}-\frac{2}{3}-\frac{3}{5}+\frac{1}{5}\)
\(=\left(-\frac{1}{3}-\frac{2}{3}\right)+\left(\frac{2}{5}-\frac{3}{5}+\frac{1}{5}\right)\)
\(=-\frac{3}{3}+0\)
\(=-1\)
=.= hk tốt!!
B=\(\frac{-4}{12}+\frac{18}{45}+\frac{-6}{9}+\frac{-21}{35}+\frac{6}{30}\)
=\(\frac{-4}{4\cdot3}+\frac{2\cdot9}{5\cdot9}+\frac{\left(-2\right)\cdot3}{3\cdot3}+\frac{\left(-4\right)\cdot7}{5\cdot7}+\frac{6}{5\cdot6}\)
=\(\frac{-1}{3}+\frac{2}{5}+\frac{-2}{3}+\frac{-4}{5}+\frac{1}{5}\)
= \(\left(\frac{-1}{3}+\frac{-2}{3}\right)+\left(\frac{-4}{5}+\frac{2}{5}+\frac{1}{5}\right)\)
=\(\frac{-3}{3}+\frac{-1}{5}\)
= \(-1+\frac{-1}{5}\)=\(\frac{-5-1}{5}=\frac{-6}{5}\)
\(\dfrac{-4}{12}+\dfrac{18}{45}+\dfrac{-6}{9}+\dfrac{-21}{35}+\dfrac{6}{30}\)
\(=\dfrac{-1}{3}+\dfrac{2}{5}+\dfrac{-2}{3}+\dfrac{-3}{5}+\dfrac{1}{5}\)
\(=\left(\dfrac{-1}{3}+\dfrac{-2}{3}\right)+\left(\dfrac{2}{5}+\dfrac{-3}{5}+\dfrac{1}{5}\right)\)
\(=-1+0\)
\(=-1\)
\(\#PeaGea\)