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Bài 1:
a) b) c) sẽ có bạn giải cho em thôi vì nó dễ tính tay cũng đc
d) \(\frac{4}{2.5}+\frac{4}{5.8}+...+\frac{4}{23.26}\)
\(=\frac{4}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+...+\frac{3}{23.26}\right)\)
\(=\frac{4}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{23}-\frac{1}{26}\right)\)
\(=\frac{4}{3}.\left(\frac{1}{2}-\frac{1}{26}\right)\)
\(=\frac{4}{3}.\frac{6}{13}\)
\(=\frac{8}{13}\)
Bài 2:
a) b) c)
d)\(|\frac{5}{8}x+\frac{6}{7}|-\frac{4}{7}=\frac{10}{7}\)
\(\Leftrightarrow|\frac{5}{8}x+\frac{6}{7}|=2\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{5}{8}x+\frac{6}{7}=2\\\frac{5}{8}x+\frac{6}{7}=-2\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}\frac{5}{8}x=\frac{8}{7}\\\frac{5}{8}x=\frac{-20}{7}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{64}{35}\\x=\frac{-32}{7}\end{cases}}}\)
Vậy \(x\in\left\{\frac{64}{35};\frac{-32}{7}\right\}\)
Bài 1 :
a) \(\left(\frac{2}{5}-\frac{5}{8}\right):\frac{11}{30}+\frac{1}{8}\)
\(=\frac{-9}{40}:\frac{11}{30}+\frac{1}{8}\)
\(=\frac{-27}{44}+\frac{1}{8}\)
\(=\frac{-43}{88}\)
\(\text{ta có:}\frac{6}{a\left(a+7\right)}+1=\frac{\left(a+1\right)\left(a+6\right)}{a\left(a+7\right)}\text{ do đó:}A=\frac{2.7}{1.8}.\frac{3.8}{2.9}.....\frac{101.106}{100.107}\)
\(=\frac{2.3...101.\left(7.8....106\right)}{1....101.\left(8.9.....107\right)}=\frac{7}{107}\)
2/7 + 7/-5 + -2/32 = -41/35
4/3 + | 5\-6 | + | -7/-6 | = 4/3 + 5/6 + 7/6 = 10/3
hok tốt
.............
\(\frac{2}{7}+\frac{7}{-5}+\frac{-2}{35}\)
\(=\frac{2}{7}+\frac{-7}{5}+\frac{-2}{35}\)
\(=\frac{10}{35}+\frac{-49}{35}+\frac{-2}{35}\)
\(=\frac{-41}{35}\)
\(\frac{4}{3}+\left|\frac{5}{6}\right|+\left|\frac{-7}{-6}\right|\)
\(=\frac{4}{3}+\frac{5}{6}+\frac{7}{6}\)
\(=\frac{8}{6}+\frac{5}{6}+\frac{7}{6}\)
\(=\frac{20}{6}=\frac{10}{3}\)
a) ta có \(\frac{-5}{6}\)\(\times\)\(\frac{120}{25}\)< \(x\)<\(\frac{-7}{15}\)\(\times\)\(\frac{4}{9}\)\(\Rightarrow\)\(-4\)<\(x\)<\(-0,2074074074\)\(\Rightarrow\)\(-4\)<\(x\)<\(-0,2\)
mà \(x\)\(\in\)\(ℤ\)\(\Rightarrow\)\(x\)\(\in\)( -1;-2;-3)
b) ta có \(\left(\frac{-5}{3}\right)^3\)<\(x\)<\(\frac{-25}{35}\)\(\times\)\(\frac{-5}{6}\)\(\Rightarrow\)\(-4,62962963\)<\(x\)<\(0,5952380952\)
mà \(x\)\(\in\)\(ℤ\)\(\Rightarrow\)\(x\)\(\in\)(-4;-3;-2;-1;0)
ĐÚNG THÌ K CHO MK NHA
a)(1,5.x+3/7):1,5-1,5=1 b)(2+x+4/7+3/7):1,4-5/7=-2
1,5.x:1,5+3/7:3/2=1+1,5 (2+x+1):1,4-5/7=-2
x+ 3/7x 2/3=2,5 (3+x):1,4=-2+5
x+2/7=2,5 (3+x):1,4=3
x+2/7=5/2 3+x=3x1,4
x=5/2-2/7 3+x=4,2
x=31/14 x=4,2-3=1,2
a) \(\frac{2^{10}\left(2+3\right)}{\left(2^2\right)^5.5.2}=\frac{2^{10}.5}{2^{10}.5.2}=\frac{1}{2}\); b) \(=\frac{\left(3^2\right)^4.2-3^6}{3^6.34.3}=\frac{3^6\left(2.3^2-1\right)}{3^6.34.3}=\frac{3^6.17}{3^6.17.2.3}=\frac{1}{6}\)
-\(\left(\frac{-1}{5}+\frac{3}{12}\right)+\frac{-3}{4}=\frac{-1}{5}+\left(\frac{3}{12}+\frac{-3}{4}\right)\) =\(\frac{-1}{5}+\left(\frac{1}{4}+\frac{-3}{4}\right)=\frac{-1}{5}+\frac{2}{4}\)= \(\frac{-4}{20}+\frac{10}{20}=\frac{6}{20}=\frac{3}{10}\)
- \(\frac{1}{5}+\frac{14}{20}+\frac{6}{21}=\frac{1}{5}+\frac{7}{10}+\frac{2}{7}\)= \(\frac{14}{70}+\frac{49}{70}+\frac{20}{70}=\frac{83}{70}\)
\(B=-\frac{1}{3}+\frac{2}{5}-\frac{2}{3}-\frac{3}{5}+\frac{1}{5}\)
\(=\left(-\frac{1}{3}-\frac{2}{3}\right)+\left(\frac{2}{5}-\frac{3}{5}+\frac{1}{5}\right)\)
\(=-\frac{3}{3}+0\)
\(=-1\)
=.= hk tốt!!
B=\(\frac{-4}{12}+\frac{18}{45}+\frac{-6}{9}+\frac{-21}{35}+\frac{6}{30}\)
=\(\frac{-4}{4\cdot3}+\frac{2\cdot9}{5\cdot9}+\frac{\left(-2\right)\cdot3}{3\cdot3}+\frac{\left(-4\right)\cdot7}{5\cdot7}+\frac{6}{5\cdot6}\)
=\(\frac{-1}{3}+\frac{2}{5}+\frac{-2}{3}+\frac{-4}{5}+\frac{1}{5}\)
= \(\left(\frac{-1}{3}+\frac{-2}{3}\right)+\left(\frac{-4}{5}+\frac{2}{5}+\frac{1}{5}\right)\)
=\(\frac{-3}{3}+\frac{-1}{5}\)
= \(-1+\frac{-1}{5}\)=\(\frac{-5-1}{5}=\frac{-6}{5}\)