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A = \(\dfrac{20,2\times5,1-30,3\times3,4+14,58}{14,58\times460+7,29\times540\times2}\)
A = \(\dfrac{10,1\times2\times5,1-10,1\times3\times3,4+14,58}{14,5\times460+(7,29\times2)\times540}\)
A = \(\dfrac{10,1\times\left(2\times5,1-3\times3,4\right)+14,58}{14,58\times460+14,58\times540}\)
A = \(\dfrac{10,1\times\left(10,2-10,2\right)+14,58}{14,58\times\left(460+540\right)}\)
A = \(\dfrac{10,1\times0+14,58}{14,58\times1000}\)
A = \(\dfrac{14,58}{14,58\times1000}\)
A = \(\dfrac{1}{1000}\)
A = 0,001
\(\frac{20,2\times5,1-30,3\times3,4+14,58}{14,58\times460+7,29\times540\times2}\)
\(=\frac{10,1\times2\times5,1-10,1\times3\times3,4+14,58}{14,58\times460+14,58\times540}\)
\(=\frac{10,1\times\left(2\times5,1-3\times3,4\right)+14,58}{14,58\times\left(460+540\right)}\)
\(=\frac{10,1\times0+14,58}{14,58\times1000}\)
\(=\frac{14,58}{14580}\)\(=\frac{1458}{1458000}\)\(=\frac{1}{1000}\)
b)4y+(1/3+1/9+1/27)=56/81
4y+40/81=56/81
4y=56/81-40/81
4y=16/81
y=16/81:4
y=4/81
b) Tìm y:
( y + \(\frac{1}{3}\)) + ( y + \(\frac{1}{9}\)) + ( y + \(\frac{1}{27}\)) + ( y + \(\frac{1}{81}\)) = \(\frac{56}{81}\)
y + ( \(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)) = \(\frac{56}{81}\)
y + \(\frac{27+9+3+1}{81}\) = \(\frac{56}{81}\)
y + \(\frac{40}{81}\) = \(\frac{56}{81}\)
y = \(\frac{56}{81}-\frac{40}{81}\)
y = \(\frac{16}{81}\)
Tl roy, ủng hộ nha! :)
Bài 1
Câu a, xem lại đề bài
Câu b:
14,58 x 460 + 7,29 x 540 x 2
= 14,58 x 460 + (7,29 x 2) x 540
= 14,58 x 460 + 14,58 x 540
= 14,58 x (460 + 540)
= 14,58 x 1000
= 14580
Câu c: 8,9 : 0,25 + 8,9 : 0,2 + 8,9
= 8,9 x 4 + 8,9 x 5 + 8,9 x 1
= 8,9 x (4 + 5 + 1)
= 8,9 x (9 + 1)
= 8,9 x 10
= 890
48,18 -3 x ( x - 12,8 )= 14,58
=> 3 x ( x - 12,8 ) = 48,18 - 14,58 = 33,6
=> x - 12,8 = 33,6 : 3 = 11,2
=> x = 11,2 + 12,8 = 24
Vậy x = 24
\(\text{#Hok tốt!}\)
48,18 -3 x ( x - 12,8 )= 14,58
3 x ( x - 12,8 ) = 48,18 - 14,58 = 33,6
x - 12,8 = 33,6 : 3
x - 12,8 = 11,2
x = 11,2 + 12,8
x = 24