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=\(\frac{36.950+36.726+36.324}{\left(29+1\right).15:2-152}\)
=\(\frac{36.\left(950+726+324\right)}{73}\)
=\(\frac{36.2000}{73}\)
=\(\frac{72000}{73}\)
\(\frac{36\times950+18\times726\times2+3\times324\times12}{1+3+5+7+9+....+27+29+31-152}\)
\(=\frac{36\times950+\left(18\times2\right)\times726+324\times\left(12\times3\right)}{\left(31+1\right)\times16\div2-152}\)
\(=\frac{36\times950+36\times726+324\times36}{256-152}\)
\(=\frac{36\times\left(950+726+324\right)}{104}\)
\(=\frac{36\times2000}{104}=\frac{72000}{104}=\frac{9000}{13}\)
0,6 × 7 + 1,2 × 45 + 1,8
= 0,6 × 7 + 0,6 × 2 × 45 + 0,6 × 3
= 0.6 × 7 + 0,6 × 90 + 0,6 × 3
= 0,6 × ( 7 + 90 + 3 )
= 0,6 × 100
= 60
(\(\dfrac{2}{3}\) + \(\dfrac{8}{9}\) + \(\dfrac{26}{27}\) + \(\dfrac{80}{81}\) + \(\dfrac{242}{243}\)) : y = 5
Đăt A = \(\dfrac{2}{3}\) + \(\dfrac{8}{9}\) + \(\dfrac{26}{27}\) + \(\dfrac{80}{81}\) + \(\dfrac{242}{243}\)
3A = 2 + \(\dfrac{8}{3}\) + \(\dfrac{26}{9}\) + \(\dfrac{80}{27}\) + \(\dfrac{242}{81}\)
3A - A = 2 + \(\dfrac{8}{3}\) + \(\dfrac{26}{9}\) + \(\dfrac{80}{27}\) + \(\dfrac{242}{81}\) - \(\dfrac{2}{3}\)-\(\dfrac{8}{9}\)-\(\dfrac{26}{27}\)-\(\dfrac{80}{81}\)-\(\dfrac{242}{243}\)
A x (3 - 1) = 2 - \(\dfrac{242}{243}\)+ (\(\dfrac{8}{3}\) - \(\dfrac{2}{3}\))+(\(\dfrac{26}{9}\) - \(\dfrac{8}{9}\))+(\(\dfrac{80}{27}\)-\(\dfrac{26}{27}\))+(\(\dfrac{242}{81}\)-\(\dfrac{80}{81}\))-\(\dfrac{242}{243}\)
A x 2 = 2 - \(\dfrac{242}{243}\) + 2 + 2 + 2 + 2
A x 2 = (2 + 2 + 2 +2 + 2) - \(\dfrac{242}{243}\)
A x 2 = 2x5 - \(\dfrac{242}{243}\)
A x 2 = 10 - \(\dfrac{242}{243}\)
A x 2 = \(\dfrac{2188}{243}\)
A = \(\dfrac{2188}{243}\) : 2
A = \(\dfrac{1094}{243}\)
\(\dfrac{1094}{243}\) : y = 5
y = \(\dfrac{1094}{243}\) : 5
y = \(\dfrac{1094}{1215}\)
(4,329 : 0,001 - 43,2 x 100) x 150 + 2018 + 2019 : 10000
= (4,329 x 1000 - 4320) x 150 + 2018 + 2019 : 10000
= (4329 - 4320) x 150 + 2018 + 2019 : 10000
= 9 x 150 + 2018 + 0,2019
= 1350 + 2018 + 0,2019
= 3368 + 0,2019
= 3368,2019
A = \(\dfrac{36\times950+18\times726\times2+3\times324\times12}{1+3+5+7+...+27+29+31-152}\)
A = \(\dfrac{36\times950+36\times726+36\times324}{1+3+5+7+...+27+29+31-152}\)
MS = 1 + 3 + 5 +...+ 27 + 29 + 31 - 152
Xét dãy số: 1; 3; 5;...;27; 29; 31 là dãy số cách đều với khoảng cách là:
3 - 1 = 2
Số số hạng của dãy số là:
(31 - 1): 2 + 1 = 16
MS = (31 + 1) x 16 : 2 - 152 = 104
A = \(\dfrac{36\times\left(950+726+324\right)}{104}\)
A = \(\dfrac{36\times2000}{104}\)
A = \(\dfrac{9000}{13}\)