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x - 128 = \(\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)\)
⇔ x - 128 = \(\left(\dfrac{104}{21}-5\right):\left(\dfrac{-1}{42}\right):\left(\dfrac{-1}{64}\right)\)
⇔ x - 128 = \(\left(\dfrac{-1}{21}\right):\left(\dfrac{-1}{42}\right):\left(\dfrac{-1}{64}\right)\)
⇔ x - 128 = -128
⇔ x = -128 + 128
⇔ x = 0
Vậy x = 0
\(x-128=\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)\)
\(\Rightarrow x-128=\left(-\dfrac{1}{21}\right):\left(-\dfrac{1}{42}\right):\left(-\dfrac{1}{64}\right)\)
\(\Rightarrow x-128=2:\left(-\dfrac{1}{64}\right)\)
\(\Rightarrow x-128=-128\)
\(\Rightarrow x=\left(-128\right)+128\)
\(\Rightarrow x=0\)
`(-3737)/(4141)=(-37xx101)/(41xx101)=(-37)/41`
Vì `37/41>34/41`
`=>(-37)/41<(-34)/41`
Hay `(-3737)/(4141)<(-34)/41`
\(\dfrac{-3737}{4141}=\dfrac{-37\cdot101}{41\cdot101}=\dfrac{-37}{41}\)
Mà \(\dfrac{-37}{41}< \dfrac{-34}{41}\) (vì \(-37< -34\))
Nên \(\dfrac{-3737}{4141}< \dfrac{-34}{41}\)