\(^4\)+    2x  +    3 

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27 tháng 4 2020

Bài làm

   x4 + 2x + 2

= x4 - 2x3 + 2x + 4 - 2 + 2x

= x3( x + 2 ) + 2( x + 2 ) - ( 2x3 + 2 )

= ( 2x3 + 2 )( x + 2 ) - ( 2x3 + 2 )

= ( 2x3 + 2 )( x + 2 - 1 )

= ( 2x3 + 2 )( x + 1 )

27 tháng 10 2016

a, \(x^3-2x-4\) b, \(x^2+4x+3\) nhá

 

13 tháng 8 2017

Nghịch xíu :v

a, \(x^3-2x-4\)

\(=x^3-2x^2+2x^2-4x+2x-4\)

\(=x^2\left(x-2\right)-2x\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2-2x+2\right)\)

b, \(x^2+4x+3\)

\(=x^2+x+3x+3=x\left(x+1\right)+3\left(x+1\right)\)

\(=\left(x+1\right)\left(x+3\right)\)

Chúc bạn học tốt!!!

15 tháng 10 2016

a) \(x^4-2x^3+2x-1\)

\(=x^4-x^3-x^3+2x-2+1\)

\(=\left(x^4-x^3\right)+\left(2x-2\right)-\left(x^3-1\right)\)

\(=x^3\left(x-1\right)+2\left(x-1\right)-\left(x-1\right)\left(x^2+x+1\right)\)

\(=\left(x-1\right)\left(x^3+2-x^2-x-1\right)\)

\(=\left(x-1\right)\left(x^3-x^2-x+1\right)\)

\(=\left(x-1\right)\left[\left(x^3-x^2\right)-\left(x-1\right)\right]\)

\(=\left(x-1\right)\left[x^2\left(x-1\right)-\left(x-1\right)\right]\)

\(=\left(x-1\right)\left(x^2-1\right)\left(x-1\right)\)

\(=\left(x-1\right)^2\left(x-1\right)\left(x+1\right)\)

\(=\left(x-1\right)^3\left(x+1\right)\)

b) \(x^4+2x^3+2x^2+2x+1\)

\(=\left(x^4+2x^2+1\right)+\left(2x^3+2x\right)\)

\(=\left(x^2+1\right)^2+2x\left(x^2+1\right)\)

\(=\left(x^2+1\right)\left(x^2+1+2x\right)\)

\(=\left(x^2+1\right)\left(x+1\right)^2\)

8 tháng 8 2018

\(x^3+2x^2+2x+1=\left(x^3+1\right)+\left(2x^2+2x\right)\)

\(=\left(x+1\right)\left(x^2-x+1\right)+2x\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-x+1+2x\right)=\left(x+1\right)\left(x^2+x+1\right)\)

\(x^3-4x^2+12x-27=x^3-3x^2-x^2+3x+9x-27\)

\(=x^2\left(x-3\right)-x\left(x-3\right)+9\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2-x+9\right)\)

\(x^4+2x^3+2x^2+2x+1=x^4+x^2+2x^3+x^2+2x+1\)

\(=x^2\left(x^2+1\right)+2x\left(x^2+1\right)+\left(x^2+1\right)\)

\(=\left(x^2+1\right)\left(x^2+2x+1\right)\)

\(=\left(x^2+1\right)\left(x+1\right)^2\)

\(x^4-2x^3+2x-1=\left(x^4-1\right)-2x\left(x^2-1\right)\)

\(=\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)\)

\(=\left(x^2-1\right)\left(x^2+1-2x\right)=\left(x^2-1\right)\left(x-1\right)^2\)

8 tháng 8 2018

\(x^3+2x^2+2x+1=\left(x^3+x^2\right)+\left(x^2+x\right)+\left(x+1\right)\)

                                    \(=x^2.\left(x+1\right)+x.\left(x+1\right)+\left(x+1\right)\)

                                   \(=\left(x+1\right).\left(x^2+x+1\right)\)

\(x^3-4x^2+12x-27\)

\(=\left(x^3-x^2\right)-\left(3x^2-3x\right)+\left(9x-27\right)\)

\(=x^2.\left(x-1\right)-3x.\left(x-1\right)+9.\left(x-3\right)\)

\(=\left(x-1\right).\left(x^2-3x\right)+9.\left(x-3\right)\)

\(=x.\left(x-1\right).\left(x-3\right)+9.\left(x-3\right)\)

\(=\left(x-3\right)\left[x.\left(x-1\right)+9\right]\)

2 tháng 7 2019

\(x^4+2x^3-16x^2-2x+15\)

\(=x^4+5x^3-3x^3-15x^2-x^2-5x+3x+15\)

\(=x^3\left(x+5\right)-3x^2\left(x+5\right)-x\left(x+5\right)+3\left(x+5\right)\)

\(=\left(x+5\right)\left(x^3-3x^2-x+3\right)\)

\(=\left(x+5\right)\left[x^2\left(x-3\right)-\left(x-3\right)\right]\)

\(=\left(x+5\right)\left(x-3\right)\left(x^2-1\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(x-3\right)\left(x+5\right)\)

2 tháng 7 2017

=x3(x+2)-13x2+12x-26x+24

=x3(x+2)-x(13x-12)-2(13x-12)

=x3(x+2)-(13x-12)(x+2)

=(x+2)(x3-x-12x+12)

(x+2)[(x2-1)-12(x-1)]

=(x+2)[x(x-1)(x+1)-12(x-1)]

=(x+2)(x-1)[x(x+1)-12]

=(x+2)(x-1)(x2+x-12)

=(x+2)(x-1)(x2-3x+4x-12)

=(x+2)(x-1)[x(x-3)+4(x+3)]

=(x+2)(x-1)(x-3)(x+4)

2 tháng 7 2017

trong bài làm của mk có hàng k có dấu "=" chỗ đó có dâu"=" nha!

6 tháng 10 2018

      \(x^6-x^4+2x^3+2x^2\)

\(=x^2\left(x^4-x^2+2x+2\right)\)

\(=x^2\left[x^4-2x^3+x^2+2x^3-4x^2+2x+2x^2-4x+2\right]\)

\(=x^2\left[x^2\left(x^2-2x+1\right)+2x\left(x^2-2x+1\right)+2\left(x^2-2x+1\right)\right]\)

\(=x^2\left(x^2-2x+1\right)\left(x^2+2x+2\right)\)

\(=x^2\left(x-1\right)^2\left(x^2+2x+2\right)\)

28 tháng 6 2018

\(x^3-2x-4=x^3-4x+2x-4=x\left(x-2\right)\left(x+2\right)+2\left(x-2\right)=\left(x-2\right)\left(x^2+2x+2\right)\)

\(x^4+2x^3-4x-4=\left(x^4+2x^3+x^2\right)-\left(x^2+4x+4\right)\)

\(=\left(x^2+x\right)^2-\left(x+2\right)^2=\left(x^2+x+x+2\right)\left(x^2+x-x-2\right)\)

\(=\left(x^2-2\right)\left(x^2+2x+2\right)\)

\(x^2-2x-4y^2-4y=\left(x^2-2x+1\right)-\left(4y^2-4y+1\right)\)

\(=\left(x-1\right)^2-\left(2y-1\right)^2=\left(x-1+2y-1\right)\left(x-1-2y+1\right)\)

\(=\left(x-2y\right)\left(x+2y-2\right)\)

19 tháng 8 2017

a)45+x3-5x2-9x

(45-9x)+(x3-5x2)

9(5-x)+x2(x-5)

(9-x2)(5-x)

(3-x)(3+x)(5-x)

b)x4-2x3-2x2-2x-3

x3(x-2)-2x(x-2)-3

(x-2)(x3-2x)-3

x