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h: =>7x-21-15+5x=11x-5
=>12x-36=11x-5
hay x=31
l: (x+3)(x-4)=0
=>x+3=0 hoặc x-4=0
=>x=-3 hoặc x=4
i: =>5x-30-2x-6=12
=>3x-36=12
hay x=16
m: =>119+27x=8x52
=>27x=297
hay x=11
a)\(-7-25+27+5=\left(27-7\right)+\left(5-25\right)\)
\(=20-20=0\)
b)\(-8+16-\left(-8\right)=-8+16+8=\left(8-8\right)+16=16\)
c)\(1+1-\left(-8\right)=1+1+8=10\)(Vì số nào mũ 0 cũng bằng 1(ngoại trừ số 0))
d)\(65.23+65.35-35.65+35.23\)
\(=\left(65.35-65.35\right)+23.\left(65+35\right)\)
\(=0+23.100=2300\)
f) \(8+\left[1800-\left(64-54\right)^3\right].8-5\)
\(=8+\left(1800-10^3\right).8-5\)
\(=8+800.8-5=6403\)
h)\(-123-46+46+123=\left(123-123\right)+\left(46-46\right)\)
\(=0+0=0\) (phá ngoặc ra thôi nhé)
a) Ta có: \(14-\left(5-8\right)^3+\left(-3\right)\cdot5\)
\(=14+27-15=26\)
b) Ta có: \(-7\cdot15+7\cdot\left(-35\right)+\left(-1\right)^{2019}\)
\(=-7\left(15+35\right)-1=-350-1=-351\)
c) Ta có: \(-18\cdot32+\left(-18\right)\cdot45+77\cdot\left(-32\right)-77\cdot50\)
\(=-18\left(32+45\right)+77\left(-32-50\right)\)
\(=-18\cdot77+77\cdot\left(-82\right)=77\left(-18-82\right)=77\cdot\left(-100\right)=-7700\)
d) Ta có: \(104-4\cdot\left[-5\cdot8+\left(7-10\right)^3\right]\)
\(=104-4\left[-40-27\right]=104-4\cdot\left(-67\right)=104+268=372\)
\(3,1+5^2+5^4+...+5^{26}\)
\(=\left(1+5^2\right)+\left(5^4+5^6\right)+...+\left(5^{24}+5^{26}\right)\)
\(=\left(1+5^2\right)+5^4\left(1+5^2\right)+...+5^{24}\left(1+5^2\right)\)
\(=26+5^4.26+...+5^{24}.26\)
\(=26\left(5^4+...+5^{24}\right)\)
Vì \(26⋮26\)
\(\Rightarrow26\left(5^4+...+5^{24}\right)⋮26\)
\(\Rightarrow1+5^2+5^4+...+5^{26}⋮26\)
\(4,1+2^2+2^4+...+2^{100}\)
\(=\left(1+2^2+2^4\right)+...+\left(2^{98}+2^{99}+2^{100}\right)\)
\(=\left(1+2^2+2^4\right)+....+2^{98}\left(1+2^2+2^4\right)\)
\(=21+2^6.21...+2^{98}.21\)
\(=21\left(2^6+...+2^{98}\right)\)
Có : \(21\left(2^6+...+2^{98}\right)⋮21\)
\(\Rightarrow1+2^2+2^4+...+2^{100}⋮21\)
a) -105 - 5.x = (-5)^2
=>-105 - 5.x = 25
=> 5.x = -105 - 25
=> 5.x = -130
=> x = -130: 5
=> x = -26
c) 400 -4.|5-x| = (-6)^2
=>400- 4.|5-x| = 36
=> 4.|5-x| = 400-36
=> 4.|5-x| = 364
=> |5-x| = 364:4
=> |5-x| = 91
=> \(\left[\begin{matrix}5-x=91\\5-x=-91\end{matrix}\right.\)
=> \(\left[\begin{matrix}x=5-91\\x=5-\left(-91\right)\end{matrix}\right.\)
=> \(\left[\begin{matrix}x=-86\\x=96\end{matrix}\right.\)
câu 1 ƯCLN(17,23)=1
câu 3: -100+l-200l+(-42)
=-100+200+(-42)=100+(-42)=58
câu 4: 20=2^2.5; 24=2^3.3
=>ƯCLN (20,24)=4
câu 5 : 3 phần tử
câu 9: -32
câu 10 :16
Bài làm
| 23 + ( -18 ) | - | -5 | + ( 20190 )
= | 5 | - 5 + 1
= 5 - 5 + 1
= 1
# Chúc bạn học tốt #
Bài làm
| 23 + ( -18 ) | - | 5 | + ( -20190 )
= | 5 | - | 5 | + ( -1 )
= 5 - 5 + ( -1 )
= 0 + ( -1 )
= -1
# Chúc bạn học tốt #