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\(\frac{x^4+x^3-x^2-2x-2}{x^4+2x^3-x^2-4x-2}=\frac{\left(x^4-x^2-2\right)+\left(x^3-2x\right)}{\left(x^4-x^2-2\right)+\left(2x^3-4x\right)}\)
\(=\frac{\left(x^2-2\right)\left(x^2+1\right)+x\left(x^2-2\right)}{\left(x^2-2\right)\left(x^2+1\right)+2x\left(x^2-2\right)}=\frac{\left(x^2-2\right)\left(x^2+x+1\right)}{\left(x^2-2\right)\left(x^2+2x+1\right)}\)
\(=\frac{x^2+x+1}{\left(x+1\right)^2}\)
\(F\left(x\right)=\frac{x^4+x^3-x^2-2x-2}{x^4+2x^3-x^2-4x-2}\)
\(=\frac{\left(x^4+x^3+x^2\right)-2x^2-2x-2}{\left(x^4+2x^3+x^2\right)-\left(2x^2+4x+2\right)}\)
\(=\frac{x^2\left(x^2+x+1\right)-2\left(x^2+x+1\right)}{x^2\left(x^2+2x+1\right)-2\left(x^2+2x+1\right)}=\frac{x^2+x+1}{x^2+2x+1}\)
a)3xy+x+15y+5
=(3xy+x)+(15y+5)
=x(3y+1)+5(3y+1)
=(x+y)(3y+1)
b)2x+2y+x2-y2
=tôi đang nghĩ
a, 3xy+x+15y+5
=x(3y+1)+5(3y+1)
=(3y+1)(x+5)
b, 2x+2y+x2-y2
=2(x+y)+(x-y)(x+y)
=(x+y)(2+x-y)
Ta có :
\(x^{20}+x+1\)
\(=\left(x^{20}-x^2\right)+\left(x^2+x+1\right)\)
Đặt \(x^2+x+1=A\)
\(\Rightarrow x^{20}+x+1=x^2\left(x^{18}-1\right)+A\)
\(=x^2\left(x^9+1\right)\left(x^9-1\right)+A\)
\(=\left(x^{11}+x^2\right)\left[\left(x^3\right)^3-1^3\right]+A\)
\(=\left(x^{11}+x^2\right)\left(x^6+1+x^3\right)\left(x^3-1\right)+A\)
\(=\left(x^{17}+x^{14}+x^{11}+x^8+x^5+x^2\right)\left(x-1\right)\left(x^2+x+1\right)+A\)
\(=A.\left(x^{18}-x^{17}+x^{15}-x^{14}+x^{12}-x^{11}+x^9-x^8+x^6-x^5+x^3-x^2\right)+A\)
\(=A.\left(x^{18}-x^{17}+x^{15}-x^{14}+x^{12}-x^{11}+x^9-x^8+x^6-x^5+x^3-x^2+1\right)\)
\(=\left(x^2+x+1\right)\left(x^{18}-x^{17}+x^{15}-x^{14}+x^{12}-x^{11}+x^9-x^8+x^6-x^5+x^3-x^2+1\right)\)
câu này gửi rồi mà tôi lm rồi đó Câu hỏi của nguyen thi diem quynh - Toán lớp 8 - Học toán với OnlineMath
a. 1+6x-6x2-x3
=(1-x3)+(6x-6x2)
=(1-x)(1+x+x2)+6x(1-x)
=(1-x)(1+x+x2+6x)
=(1-x)(1+7x+x2)
b. x3-2x-4
=x3-4x+2x-4
=x(x2-4)+2(x-2)
=x(x-2)(x+2)+2(x-2)
=(x2+2x+2)(x-2)
Ủng hộ mk nhak ^_-
10.x - 25 - x2
= 5.x - 25 + 5.x - x2
= 5.(x - 5) - x.(x - 5)
= (x - 5).(5 - x)
\(x^4+x^2y^2+y^4=\left(x^4+2x^2y^2+y^4\right)-x^2y^2\)\(=\left(x^2+y^2\right)^2-\left(xy\right)^2=\left(x^2+y^2+xy\right)\left(x^2+y^2-xy\right)\).
x3 - 3x2 - 9x - 5 = (x3 - 5x2) + (2x2 -10x) + (x - 5) = x2 (x - 5) + 2x(x - 5) + (x - 5) = (x - 5)(x2 + 2x + 1) = (x - 5)(x + 1)2
x^3-3x^2-9x-5
=x^3-5x^2+2x^2-10x+x-5
=x^2(x-5)+2x(x-5)+(x-5)
=(x-5)(x^2+2x+1)
=(x-5)(x+1)^2