\(4x^4+y^4\)

b) \...">

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31 tháng 8 2018

a) \(4x^4+y^4\)

\(=\left(2x^2\right)^2+2.2x^2.y^2+\left(y^2\right)^2-2.2x^2.y^2\)

\(=\left(2x^2+y^2\right)^2-4x^2y^2\)

\(=\left(2x^2+y^2\right)^2-\left(2xy\right)^2\)

\(=\left(2x^2+y^2+2xy\right)\left(2x^2+y^2-2xy\right)\)

b) \(\left(x^2-3x-1\right)^2-12\left(x^2-3x-1\right)+27\)

\(=\left(x^2-3x-1\right)^2-2\left(x^2-3x-1\right).6+36-9\)

\(=\left(x^2-3x-1-6\right)^2-3^2\)

\(=\left(x^2-3x-7\right)^2-3^2\)

\(=\left(x^2-3x-7-3\right)\left(x^2-3x-7+3\right)\)

\(=\left(x^2-3x-10\right)\left(x^2-3x-4\right)\)

c) \(x^3-x^2-5x+125\)

\(=x^3+5x^2-6x^2-30x+25x+125\)

\(=x^2\left(x+5\right)-6x\left(x+5\right)+25\left(x+5\right)\)

\(=\left(x+5\right)\left(x^2-6x+25\right)\)

d) \(xy\left(x+y\right)+yz\left(y+z\right)+zx\left(z+x\right)+2xyz\)

\(=xy\left(x+y\right)+yz\left(y+z\right)+xyz+zx\left(z+x\right)+xyz\)

\(=xy\left(x+y\right)+yz\left(y+z+x\right)+zx\left(z+x+y\right)\)

\(=xy\left(x+y\right)+z\left(x+y+z\right)\left(y+x\right)\)

\(=\left(x+y\right)\left[xy+z\left(x+y+z\right)\right]\)

\(=\left(x+y\right)\left(xy+zx+yz+z^2\right)\)

\(=\left(x+y\right)\left[y\left(x+z\right)+z\left(x+z\right)\right]\)

\(=\left(x+y\right)\left(x+z\right)\left(y+z\right)\)

31 tháng 8 2018

a) ta có : \(4x^4+y^4=4x^4+4x^2y^2+y^2-\left(2xy\right)^2\)

\(=\left(2x^2+y^2\right)^2-\left(2xy\right)^2=\left(2x^2+y^2-2xy\right)\left(2x^2+y^2+2xy\right)\)

b) ta có : \(\left(x^3-3x-1\right)^2-12\left(x^2-3x-1\right)+27\)

\(=\left(x^2-3x-1\right)^2-3\left(x^2-3x-1\right)-9\left(x^2-3x-1\right)+27\)

\(=\left(x^2-3x-1\right)\left(x^2-3x-4\right)-9\left(x^2-3x-4\right)\)

\(=\left(x^2-3x-10\right)\left(x^2-3x-4\right)\)

c) ta có : \(x^3-x^2-5x+125=x^2+5x^2-6x^2-30x+25x+125\)

\(=x^2\left(x+5\right)-6x\left(x+5\right)+25\left(x+5\right)=\left(x^2-6x+25\right)\left(x+5\right)\)

d) ta có : \(xy\left(x+y\right)+yz\left(y+z\right)+zx\left(z+x\right)+2xyz\)

\(=x^2y+xy^2+y^2z+xyz+yz^2+z^2x+zx^2+xyz\)

\(=y\left(x^2+xy+yz+xz\right)+z\left(yz+zx+x^2+xy\right)\)

\(=\left(x+y\right)\left(x^2+xy+yz+xz\right)\)

31 tháng 8 2018

a)\(4x^4+y^4=\left(4x^4+y^4+4x^2y^2\right)-4x^2y^2\)

\(=\left(2x^2+y^2\right)^2-\left(2xy\right)^2\)

\(=\left(2x^2+y^2-2xy\right)\left(2x^2+y^2+2xy\right)\)

b)\(\left(x^2-3x-1\right)^2-12\left(x^2-3x-1\right)+27\)

Đặt x^2 - 3x - 1 = A

\(\Rightarrow A^2-12A+27=\left(A^2-12A+36\right)-9\)

\(=\left(A-6\right)^2-9=\left(A-6-3\right)\left(A-6+3\right)\)

\(=\left(A-9\right)\left(A-3\right)\)

Hay \(=\left(x^2-3x-1-9\right)\left(x^2-3x-1-3\right)\)

\(=\left(x^2-3x-10\right)\left(x^2-3x-4\right)\)

\(=\left(x-5\right)\left(x+2\right)\left(x-4\right)\left(x+1\right)\)

c)\(x^3-x^2-5x+125\)

\(=\left(x^3+5^3\right)-\left(x^2+5x\right)\)

\(=\left(x+5\right)\left(x^2-5x+25\right)-x\left(x+5\right)\)

\(=\left(x+5\right)\left(x^2-5x+25-x\right)\)

\(=\left(x+5\right)\left(x^2-6x+25\right)\)

d)\(xy\left(x+y\right)+yz\left(y+z\right)+zx\left(z+x\right)+2xyz\)

\(=\left(x+y\right)\left(y+z\right)\left(x+z\right)\)

Mình có việc bận nên chỉ đưa được kết quả ý d)  thật lòng mong các bạn tự tham khảo và giải

2 tháng 7 2021

a) xy(x + y) + yz(y + z) + xz(z + x) + 3xyz

= xy(X + y + z)  + yz(x + y + z) + xz(X + y + z)

= (x + y +z)(xy + yz+ xz)

b) xy(x + y) - yz(y + z) - xz(z - x)

= x2y + xy2 - y2z - yz2 - xz2 + x2z

= x2(y + z) - yz(y + z) + x(y2 - z2)

= x2(y + z) - yz(y + z) + x(y + z)(y - z)

= (y + z)(x2 - yz + xy - xz)

= (y + z)[x(x + y) - z(x + y)]

= (y + z)(x + y)(x - z)

c) x(y2 - z2) + y(z2 - x2) + z(x2 - y2)

 = x(y - z)(y + z) + yz2 - yx2 + x2z - y2z

= x(y - z)(y + z) - yz(y - z) - x2(y - z)

= (y - z)((xy + xz - yz - x2)

= (y - z)[x(y - x) - z(y - x)]

= (y - z)(x - z)(y -x) 

2 tháng 9 2018

\(yz\left(y+z\right)+zx\left(z-x\right)-xy\left(x+y\right)\)

\(=yz\left(y+z\right)+zx\left(z-x\right)-xy\left[\left(y+z\right)-\left(z-x\right)\right]\)

\(=yz\left(y+z\right)+zx\left(z-x\right)-xy\left(y+z\right)+xy\left(z-x\right)\)

\(=y\left(y+z\right)\left(z-x\right)+x\left(z-x\right)\left(z-y\right)\)

\(=\left(z-x\right)\left(yz-xy+xz-xy\right)\)

22 tháng 6 2018

b  \(x^8y^8+x^4y^4+1=x^8y^8+2x^4y^4+1-x^4y^4=\left(x^4y^4\right)^2+2x^4y^4+1-\left(x^2y^2\right)^2\)

\(=\left(x^4y^4+1\right)^2-\left(x^2y^2\right)^2=\left(x^4y^4-x^2y^2+1\right)\left(x^4y^4+x^2y^2+1\right)\)

c  \(x^2y+xy^2+xz^2+x^2z+y^2z+yz^2+2xyz=\left(x^2y+x^2z+xyz+xy^2\right)+\left(xz^2+yz^2+xyz+y^2z\right)\)

\(=x\left(xy+xz+yz+y^2\right)+z\left(xz+yz+xy+y^2\right)=\left(x+z\right)\left(xy+xz+yz+y^2\right)\)

\(=\left(x+z\right)\left(x\left(y+z\right)+y\left(y+z\right)\right)=\left(x+z\right)\left(x+y\right)\left(y+z\right)\)

a  \(3xyz+x\left(y^2+z^2\right)+y\left(x^2+z^2\right)+z\left(x^2+y^2\right)=3xyz+xy^2+xz^2+x^2y+yz^2+x^2z+y^2z\)

\(=\left(x^2y+x^2z+xyz\right)+\left(xy^2+xyz+y^2z\right)+\left(xyz+xz^2+yz^2\right)\)

\(=x\left(xy+xz+yz\right)+y\left(xy+xz+yz\right)+z\left(xy+xz+yz\right)=\left(x+y+z\right)\left(xy+xz+yz\right)\)

13 tháng 2 2019

@Thục Trinh giải đi

13 tháng 2 2019

1.

\(3x^2-16x+5\\ =3x^2-x-15x+5\\ =x\left(3x-1\right)-5\left(3x-1\right)\\ =\left(x-5\right)\left(3x-1\right)\)

2.

\(3x^3-14x^2+4x+3\\ =\left(3x^3+x^2\right)-\left(15x^2+5x\right)+\left(9x+3\right)\\ =x^2\left(3x+1\right)-5x\left(3x+1\right)+3\left(3x+1\right)\\ =\left(x^2-5x+3\right)\left(3x+1\right)\)

3. \(x^8+x^7+1\\ =\left(x^8-x^2\right)+\left(x^7-x\right)+\left(x^2+x+1\right)\\ =x^2\left(x^6-1\right)+x\left(x^6-1\right)+\left(x^2+x+1\right)\\ =x^2\left(x^3+1\right)\left(x^3-1\right)+x\left(x^3+1\right)\left(x^3-1\right)+\left(x^2+x+1\right)\\ =x^2\left(x^3+1\right)\left(x-1\right)\left(x^2+x+1\right)+x\left(x^3+1\right)\left(x+1\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)\\ =\left(x^2+x+1\right)[x^2\left(x^3+1\right)\left(x-1\right)+x\left(x^3+1\right)\left(x-1\right)+1]\\ =\left(x^2+x+1\right)\left(x^6-x^5+x^3-x^2+x^5-x^4+x^2-x+1\right)\\ =\left(x^2+x+1\right)\left(x^6-x^4+x^3-x+1\right)\)4.

\(64x^4+y^4\\ =\left(64x^4+16x^2y^2+y^4\right)-16x^2y^2\\ =\left(8x^2+y^2\right)^2-16x^2y^2\\ =\left(8x^2+y^2-4xy\right)\left(8x^2+y+4xy\right)\)

5.

\(\left(x+a\right)\left(x+2a\right)\left(x+3a\right)\left(x+4a\right)+a^4\\ =\left(x+a\right)\left(x+4a\right)\left(x+2a\right)\left(x+3a\right)+a^4\\ =\left(x^2+5ax+4a^2\right)\left(x^2+5ax+6a^2\right)+a^4\\=\left(x^2+5ax+4a^2\right)\left(x^2+5ax+4a^2+2a^2\right)+a^4\\=\left(x^2+5ax+4a^2\right)+2a^2\left(x^2+5ax+4a^2\right)+a^4\\ =\left(x^2+5ax+5a^2\right)^2\)

23 tháng 8 2019

k) \(x^3-x+3x^2+3xt^2+y^3-y\)

\(=\left(x^3+3x^2y+3xy^2+y^3\right)-\left(x+y\right)\)

\(=\left(x+y\right)^3-\left(x+y\right)\)

\(=\left(x+y\right)\left[\left(x+y\right)^2-1\right]\)

\(=\left(x+y\right)\left(x+y+1\right)\left(x+y-1\right)\)

23 tháng 8 2019

h) \(a^3-a^2x-ay+xy\)

\(=a^2\left(a-x\right)-y\left(a-x\right)\)

\(=\left(a^2-y\right)\left(a-x\right)\)

24 tháng 2 2020

a)\(\left(4x^3-xy^2+y^3\right)\left(x^2y+2xy^2-2y^3\right)\)

\(=x^2y\left(4x^3-xy^2+y^3\right)+2xy^2\left(4x^3-xy^2+y^3\right)\)

\(-2y^3\left(4x^3-xy^2+y^3\right)\)

\(=4x^5y-x^3y^3+x^2y^4+8x^4y^2-2x^2y^4+2xy^5\)

\(-8x^3y^3+2xy^5-2y^6\)

\(=-2y^6+4x^5y+\left(2xy^5+2xy^5\right)+8x^4y^2+\left(x^2y^4-2x^2y^4\right)\)

\(-\left(x^3y^3+8x^3y^3\right)\)

\(=-2y^6+4x^5y+4xy^5+8x^4y^2-x^2y^4-9x^3y^3\)

24 tháng 2 2020

b) 

(!)  \(2\left(x+y\right)^2-7\left(x+y\right)+5\)

\(=2\left(x+y\right)^2-2\left(x+y\right)-5\left(x+y\right)+5\)

\(=2\left(x+y\right)\left(x+y-1\right)-5\left(x+y-1\right)\)

\(=\left(2x+2y-5\right)\left(x+y-1\right)\)

(!!) \(\left(x+y+z\right)^2-x^2-y^2-z^2\)

\(=\left(x^2+y^2+z^2+2xy+2yz+2zx\right)-x^2-y^2-z^2\)

\(=2\left(xy+yz+zx\right)\)