\(x^3-2x+3\)                           ...">
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18 tháng 8 2017

x+ 7x - 6=x2 . x + 7x - 22 + 2 = (x2 - 22) + (x+7x)+2=(x-2) . (x+2) + 8x + 2

x3 - 5x + 8x - 4=x2 . x -5x + 8x -22 = (x2 - 22) . (x -5x + 8x )=(x-2) . (x+2) . 4x

x3 - 9x2 + 6x + 16=x2 . x - 9x2 + 6x + 16 = (x- 9x2) . (x+6x) + 16=(x-9x) . (x+9x) . 7x + 16

k mk nha

1: \(=x^3-8x^2-x^2+8x-2x+16\)

\(=\left(x-8\right)\left(x^2-x-2\right)=\left(x-8\right)\left(x-2\right)\left(x+1\right)\)

2: \(=x^3+2x^2-8x^2-16x+15x+30\)

\(=\left(x+2\right)\left(x^2-8x+15\right)\)

\(=\left(x+2\right)\left(x-3\right)\left(x-5\right)\)

3: \(=2x^3+x^2-2x^2-x+6x+3\)

\(=\left(2x+1\right)\left(x^2-x+3\right)\)

4: \(=64x^4+16x^2y^2+y^4-16x^2y^2\)

\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)

\(=\left(8x^2-4xy+y^2\right)\left(8x^2+4xy+y^2\right)\)

27 tháng 10 2017

Khó câu f với câu e

27 tháng 10 2017

f) x3-x2-x-2

= x3-2x2+x2-2x+x-2

= x2(x-2)+x(x-2)+(x-2)

= (x-2)(x2+x+1)

e)

x3-x2-4

= x3-2x2+x2-2x+2x-4

= x2(x-2)+x(x-2)+2(x-2)

= (x-2)(x2+x+2)

5 tháng 7 2017

a) \(x^3-5x^2+8x-4\)

= \(x^3-x^2-4x^2+4x+4x-4\)

= \(x^2\left(x-1\right)-4x\left(x-1\right)+4\left(x-1\right)\)

= \(\left(x-1\right)\left(x^2-4x+4\right)\)

= \(\left(x-1\right)\left(x-2\right)^2\)

b) \(x^3-9x^2+6x+16\)

= \(\left(x-8\right)\left(x-2\right)\left(x+1\right)\)

c) \(x^3+2x-3\)

= \(x^3-x^2+x^2-x+3x-3\)

= \(x^2\left(x-1\right)+x\left(x-1\right)+3\left(x-1\right)\)

= \(\left(x-1\right)\left(x^2+x+3\right)\)

d) \(2x^3-12x^2+17x-2\)

= \(2x^3-4x^2-8x^2+16x+x-2\)

= \(2x^2\left(x-2\right)-8x\left(x-2\right)+\left(x-2\right)\)

= \(\left(x-2\right)\left(2x^2-8x+1\right)\)

e) \(x^3-5x^2+3x+9\)

= \(x^3+x^2-6x^2-6x+9x+9\)

= \(x^2\left(x+1\right)-6x\left(x+1\right)+9\left(x+1\right)\)

= \(\left(x+1\right)\left(x^2-6x+9\right)=\left(x+1\right)\left(x-3\right)^2\)

f) \(x^3-8x^2+17x+10\)

Câu này có vẻ sai đề, nghiệm cực kì khủng bố @@

g) \(x^3-2x-4\)

= \(x^3-2x^2+2x^2-4x+2x-4\)

= \(x^2\left(x-2\right)+2x\left(x-2\right)+2\left(x-2\right)\)

= \(\left(x-2\right)\left(x^2+2x+2\right)\)

h) \(x^3+x^2+4\)

= \(x^3+2x^2-x^2+4\)

= \(x^2\left(x+2\right)-\left(x-2\right)\left(x+2\right)\)

= \(\left(x+2\right)\left(x^2-x+2\right)\)

i) \(x^3-7x+6\)

= \(\left(x+3\right)\left(x-2\right)\left(x-1\right)\)

20 tháng 10 2018

help me!!!

26 tháng 10 2022

b: \(=x^4+x^2+36-2x^3+12x^2-12x+x^2-6x+9\)

\(=x^4-2x^3+14x^2-18x+45\)

\(=x^4+9x^2-2x^3-18x+5x^2+45\)

\(=\left(x^2+9\right)\left(x^2-2x+5\right)\)

d: \(=2x^4+2x^3+6x^2-x^3-x^2-3x+x^2+x+3\)

\(=\left(x^2+x+3\right)\left(2x^2-x+1\right)\)

e: \(=3x^4-3x^3-3x^2-2x^3+2x^2+2x+2x^2-2x-2\)

\(=\left(x^2-x-1\right)\left(3x^2-2x+1\right)\)

3 tháng 8 2017

a)\(\left(x+1\right)\left(x+2\right)\left(x+3\right)\)

b)\(\left(x-3\right)\left(x-7\right)\left(x+2\right)\)

c)\(\left(x-3\right)\left(x+3\right)\left(x+2\right)\left(x+1\right)\)

d)\(\left(x+5\right)\left(x-3\right)\left(x+1\right)\left(x+2\right)\)

11 tháng 10 2017

sao bn toàn trả lời tắt thế

23 tháng 8 2020

a) -x2 + 2x - 1

= -( x2 - 2x + 1 )

= -( x - 1 )2

b) 12y - 36 - y2

= -( y2 - 12y + 36 )

= -( y - 6 )2

c) -x3 + 9x2 - 27x + 27

= -( x3 - 9x2 + 27x - 27 )

= -( x - 3 )3

d) x3 - 6x2 + 9x 

= x( x2 - 6x + 9 )

= x( x - 3 )2

e) a3b - ab3 

= ab( a2 - b2 )

= ab( a - b )( a + b )

f) a2 + 2a + 1 - b2

= a2 + ab + a - ab - b2 - b + a + b + 1

= a( a + b + 1 ) - b( a + b + 1 ) + 1( a + b + 1 )

= ( a - b + 1 )( a + b + 1 )

23 tháng 8 2020

a)\(-x^2+2x-1\) 

\(=-\left(x^2-2x+1\right)\)  

\(=-\left(x-1\right)^2\) 

b) \(12y-36-y^2\)    

\(=-\left(y^2-12y+36\right)\)    

\(=-\left(y^2-2\cdot1\cdot6+6^2\right)\)      

\(=-\left(y-6\right)^2\)        

c) \(-x^3+9x^2-27x+27\)      

\(=-x^3+3x^2+6x^2-18x-9x+27\)      

\(=-x^2\left(x-3\right)+6x\left(x-3\right)-9\left(x-3\right)\)     

\(=\left(x-3\right)\left(-x^2+6x-9\right)\)   

\(=\left(x-3\right)\cdot-\left(x^2-6x+9\right)\)   

\(=\left(x-3\right)\cdot-\left(x^2-2\cdot x\cdot3+3^2\right)\) 

\(=-\left(x-3\right)\left(x-3\right)^2\)                                    

\(=\left(x-3\right)^3\)      

d) \(x^3-6x^2+9\)     

\(=x\left(x^2-6x+9\right)\)    

\(=x\left(x-3\right)^2\)    

e) \(a^3b-ab^3\)     

\(=ab\left(a^2-b^2\right)\)  

\(=ab\left(a-b\right)\left(a+b\right)\)     

f) \(a^2+2a+1-b^2\)    

\(=a^2+2\cdot a\cdot1+1^2-b^2\)    

\(=\left(a+1\right)^2-b^2\)      

\(=\left(a+1-b\right)\left(a+1+b\right)\)

27 tháng 8 2017

\(a,\)\(x^4-4x^3+4x^2=0\)

\(\Leftrightarrow x^2.\left(x^2-4x+4\right)=0\)

\(\Leftrightarrow x^2.\left(x^2-2.x.2+2^2\right)=0\)

\(\Leftrightarrow x^2.\left(x-2\right)^2=0\)

\(\Leftrightarrow\orbr{\begin{cases}x^2=0\\\left(x-2\right)^2=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)

\(b,\)\(x^2+5x+4=0\)

\(\Leftrightarrow x^2+x+4x+4=0\)

\(\Leftrightarrow x.\left(x+1\right)+4.\left(x+1\right)=0\)

\(\Leftrightarrow\left(x+1\right).\left(x+4\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+1=0\\x+4=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=-1\\x=-4\end{cases}}\)

\(c,\)\(9x-6x^2-3=0\)

\(\Leftrightarrow-3.\left(2x^2-3x+1\right)=0\)

\(\Leftrightarrow2x^2-3x+1=0\)

\(\Leftrightarrow2x^2-2x-x+1=0\)

\(\Leftrightarrow2x.\left(x-1\right)-\left(x-1\right)\)

\(\Leftrightarrow\left(x-1\right).\left(2x-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\2x-1=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=1\\2x=1\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=\frac{1}{2}\end{cases}}\)

\(d,\)\(2x^2+5x+2=0\)

\(\Leftrightarrow2x^2+4x+x+2=0\)

\(\Leftrightarrow2x.\left(x+2\right)+\left(x+2\right)=0\)

\(\Leftrightarrow\left(x+2\right).\left(2x+1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+2=0\\2x+1=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=-2\\2x=-1\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=-\frac{1}{2}\end{cases}}\)