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\(x^4+6x^3+7x^2-6x+1=x^4-2x^2+1+6x^3-6x+9x^2=\left(x^2-1\right)^2+6x\left(x^2-1\right)+9x^2=\left(x^2-1\right)^2+2.3x\left(x^2-1\right)+\left(3x\right)^2=\)
\(\left(x^2+3x-1\right)^2\)
\(x^4+6x^3+7x^2-6x+1=\left(x^2+ax+1\right)\left(x^2+bx+1\right)hoặc=\left(x^2+cx-1\right)\left(x^2+dx-1\right)\)
+\(x^4+6x^3+7x^2-6x+1=\left(x^2+ax+1\right)\left(x^2+bx+1\right)=x^4+\left(a+b\right)x^3+\left(ab+2\right)x^2+\left(a+b\right)x+1\)=> a+b=6 ; ab+2 =7 ; a+b =-6 loại
+\(x^4+6x^3+7x^2-6x+1=\left(x^2+cx-1\right)\left(x^2+dx-1\right)=x^4+\left(c+d\right)x^3+\left(cd-2\right)x^2-\left(c+d\right)x+1\)=>c+d =6 ; cd-2 =7 ; hay c+d =6 ; cd =9 => c =d =3
vậy \(x^4+6x^3+7x^2-6x+1=\left(x^2+3x-1\right)\left(x^2+3x-1\right)\)
Bạn tphaan tích tiếp nhé ( Bấm máy tính giải pt )
a) \(x^2-x\)
\(=x\left(x-1\right)\)
b) \(5x^2\left(x-2y\right)-15x\left(x-2y\right)\)
\(=\left(x-2y\right)\left(5x^2-15x\right)\)
\(=\left(x-2y\right).5x.\left(x-3\right)\)
c) \(3\left(x-y\right)-5x\left(y-x\right)\)
\(=3\left(x-y\right)+5x\left(x-y\right)\)
\(=\left(x-y\right)\left(3+5x\right)\)
a)\(x^2-x=x\left(x-1\right)\)
b)\(5x^2\left(x-2y\right)-15x\left(x-2y\right)=x.5x\left(x-2y\right)-3.5x\left(x-2y\right)=5x\left(x-2y\right)\left(x-3\right)\)
c)\(3\left(x-y\right)-5x\left(y-x\right)=3\left(x-y\right)+5x\left[-\left(y-x\right)\right]=3\left(x-y\right)+5x\left(x-y\right)=\left(x-y\right)\left(3+5x\right)\)
a) \(x^2+4x+3\)
\(=x^2+3x+x+3\)
\(=x\left(x+3\right)+\left(x+3\right)\)
\(=\left(x+1\right)\left(x+3\right)\)
a) \(3x^2-5x+2=3x^2-2x-3x+2=x\left(3x-2\right)-\left(3x-2\right)=\left(x-1\right)\left(3x-2\right)\)
b) \(2x^2+x-6=2x^2-3x+4x-6=x\left(2x-3\right)+2\left(2x-3\right)=\left(2x-3\right)\left(x+2\right)\)
c) \(x^2-5x-14=x^2+2x-7x-14=x\left(x+2\right)-7\left(x+2\right)=\left(x+2\right)\left(x-7\right)\)
d) \(15x^2+7x-2=15x^2-3x+10x-2=3x\left(5x-1\right)+2\left(5x-1\right)=\left(5x-1\right)\left(3x+2\right)\)
x3 + 3x2 + 4x2 + 12x + 3x + 9
= x2(x + 3) + 4x(x + 3) + 3(x + 3)
= (x + 3)(x2 +4x + 3)
=(x +3)(x2 + x + 3x + 3)
=(x + 3)2(x + 1)