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14 tháng 4 2023
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
29 tháng 4 2019
A = ( -4/5 + 4/3 ) + (-5/4 + 14/5) - 7/3
= 8/15 + 31/20 - 7/3
= 25/12 - 7/3
= -1/4
B = 8/3 x 2/5 x 3/8 x 10x 19/92
= 16/15 x 15/4 x 19/92
= 4x19/92
= 19/23
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
22 tháng 9 2024
C = - \(\dfrac{5}{7}\) x \(\dfrac{2}{11}\) + \(\dfrac{-5}{7}\) x \(\dfrac{9}{14}\) + \(\dfrac{1}{57}\)
= - \(\dfrac{10}{77}\) - \(\dfrac{45}{98}\) + \(\dfrac{1}{57}\)
= - \(\dfrac{635}{1078}\) + \(\dfrac{1}{57}\)
= - \(\dfrac{36195}{61446}\) + \(\dfrac{1078}{61446}\)
= - \(\dfrac{35117}{61446}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
27 tháng 3 2024
a; \(\dfrac{9}{4}\) - \(\dfrac{-11}{4}\)
= \(\dfrac{9}{4}\) + \(\dfrac{11}{4}\)
= \(\dfrac{20}{4}\)
= 5
b; \(\dfrac{7}{8}\) - \(\dfrac{3}{-8}\) - \(\dfrac{1}{8}\)
= \(\dfrac{7}{8}\) + \(\dfrac{3}{8}\) - \(\dfrac{1}{8}\)
= \(\dfrac{7+3-1}{8}\)
= \(\dfrac{9}{8}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
27 tháng 3 2024
c; \(\dfrac{-5}{21}\) - \(\dfrac{25}{21}\) - \(\dfrac{-1}{21}\)
= \(\dfrac{-5}{21}\) - \(\dfrac{25}{21}\) + \(\dfrac{1}{21}\)
= \(\dfrac{-5-25+1}{21}\)
= \(\dfrac{-29}{21}\)
26 tháng 2 2018
A,-3/-7+5/19+-4/7
=(-3/-7+-4/7)+5/19
=-1/7+5/19=16/133
B,-13/24+-5/24+7/21
=-3/4+7/21=-5/12
C,-5/13+(-8/13+1)
=(-5/13+-8/13)+1
=-1+1=0
D,2/3+(3/8+-2/3)
=(2/3+-2/3)+3/8
=0+3/8=3/8
E,(-3/4+5/8)+-1/8
=-1/8+1/8=0
d: \(\left(\dfrac{2}{5}-\dfrac{2}{3}\right)-\dfrac{7}{5}=\dfrac{2}{5}-\dfrac{7}{5}-\dfrac{2}{3}=-1-\dfrac{2}{3}=-\dfrac{5}{3}\)
b: \(\dfrac{14}{13}+\left(-\dfrac{1}{13}-\dfrac{19}{20}\right)=\dfrac{14}{13}-\dfrac{1}{13}-\dfrac{19}{20}=1-\dfrac{19}{20}=\dfrac{1}{20}\)
f: \(\dfrac{7}{8}-\dfrac{3}{8}\left(1-\dfrac{2}{3}\right)\)
\(=\dfrac{7}{8}-\dfrac{3}{8}\cdot\dfrac{1}{3}\)
\(=\dfrac{7}{8}-\dfrac{1}{8}=\dfrac{6}{8}=\dfrac{3}{4}\)
\(d,\left(\dfrac{2}{5}-\dfrac{2}{3}\right)-\dfrac{7}{5}\)
\(=\dfrac{2}{5}-\dfrac{2}{3}-\dfrac{7}{5}\)
\(=\left(\dfrac{2}{5}-\dfrac{7}{5}\right)-\dfrac{2}{3}\)
\(=-1-\dfrac{2}{3}\)
\(=-\dfrac{3}{3}-\dfrac{2}{3}=-\dfrac{5}{3}\)
\(e,\dfrac{14}{13}+\left(-\dfrac{1}{13}-\dfrac{19}{20}\right)\)
\(=\dfrac{14}{13}+-\dfrac{1}{13}-\dfrac{19}{20}\)
\(=\left(\dfrac{14}{13}+-\dfrac{1}{13}\right)-\dfrac{19}{20}\)
\(=1-\dfrac{19}{20}\)
\(=\dfrac{1}{20}\)
\(f,\dfrac{7}{8}-\dfrac{3}{8}.\left(1-\dfrac{2}{3}\right)\)
\(=\dfrac{7}{8}-\dfrac{3}{8}.\dfrac{1}{3}\)
\(=\dfrac{7}{8}-\dfrac{1}{8}.1\)
\(=\dfrac{6}{8}=\dfrac{3}{4}\)