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29 tháng 7 2016
Mai: Hello.This is 528199.
Huong: Hello1.....Are you........My?
Mai: No.I'm her sister, Mai.2.......Who are you..........?
Huong: It's ,Huong.3.......Can you give ..........to My?
Mai: I'm sory. She is 4......going out........... at the moment.
Huong: When5.....is she going back..............?
Mai: 6........She will.............be back at 8 o'clock.
Huong: Thank you.7...........Can..........leave a message?
Mai: Yes,of course.
Huong: Please8........tell her phone me ................after 8.
Mai: Ok.I'll tell her. Goodbye.
Huong: Bye
29 tháng 7 2016
Mai: Hello.This is 528199.
Huong: Hello Are you My?
Mai: No.I'm her sister, Mai.Who are you ?
Huong: It's ,Huong.Can you give to My?
Mai: I'm sory. She is going out at the moment.
Huong: When is she going back ?
Mai: She will be back at 8 o'clock.
Huong: Thank you. Can leave a message?
Mai: Yes,of course.
Huong: Please tell her phone me after 8.
Mai: Ok.I'll tell her. Goodbye.
11 tháng 8 2016
-_-
Em hãy cho dạng đúng của tính từ so sánh trong ngoặc để hoàn thành đoạn hội thoại sau.
Interviewer : Excuse me. Can I ask you some questions about this health club ?
Kien : Yes, of course.
Interviewer : First of all. Why do you come to the health club ?
Kien : Because I feel fitting (fit)0 and healthily (healthy)1 and relaxing (relaxed)2.
Interviewer : Fine. And how can we make the health club better (good)3 than it is now ?
Kien : Hmm. We need the biggest (big)4 changing rooms. They're the worst (bad)5 part of the club. Yes, the changing rooms are the most important (important)6 thing for me.
Interviewer : I see. What about lowing (low)7 prices ?
Kien : Yes, this is the most expensive (expensive)8 club in the town. The Youth Club is larger (large)9 but it's cheaper (cheap)10. It is about 30,000 VND a month.
Interviewer : Good. Thank you very much.
11 tháng 8 2016
Em hãy cho dạng đúng của tính từ so sánh trong ngoặc để hoàn thành đoạn hội thoại sau.
Interviewer : Excuse me. Can I ask you some questions about this health club ?
Kien : Yes, of course.
Interviewer : First of all. Why do you come to the health club ?
Kien : Because I feel fitting and healthy and relaxing.
Interviewer : Fine. And how can we make the health club better than it is now ?
Kien : Hmm. We need the biggest changing rooms. They're the worst part of the club. Yes, the changing rooms are the most important thing for me.
Interviewer : I see. What about lowing prices ?
Kien : Yes, this is the most expensive club in the town. The Youth Club is larger but it's cheaper . It is about 30,000 VND a month.
Interviewer : Good. Thank you very much.
S
25 tháng 12 2016
2 More than £1,000 were raised for charity.
3 Loads of pictures were taken by the photographers
4 The show was put on the newspaper's front page.
5 All the clothes were designed by school children.
6 the whole evening was organised by the teenagers.
7 The music was written by a 16 year-old boy.
8 The lights were done by a 14 year-old girl
TD
25 tháng 12 2016
Rewrite the underlined sentences. Use the Past passive.
The school fashion show was a great success. 1 They invited 100 people and most of them came. 2 They raised more than £1,000 for charity. It really was a big event and there were even a few famous people there. 3 The photographers took loads of pictures and 4 the newspaper put the show on its front pages. The clothes were fantastic. 5 School children designed them all. It was amazing. In fact 6 the teenagers organized the whole evening. 7 A 16 year-old boy wrote the music and 8 a 14 year-old girl did the lights. It was wonderful to see what young people can do.
1 100 people were invited. (ex)
2 More than £1,000 was raised for charity.
3 Loads of pictures were taken by the photographers.
4 The show is putted on the newspaper’s front pages.
5 All the clothes were designed by school children.
6 The whole evening was organized by the teenagers
7 The music was written a 16 year-old boy
8 The lights was done by a 14 year-old girl.
TQ
1
LP
1
KN
21 tháng 10 2020
Ta có : 2x = 5y \(\Rightarrow\frac{x}{5}=\frac{y}{2}\Rightarrow\frac{x^2}{25}=\frac{y^2}{4}\)
Áp dụng t/c của dãy tỉ số bằng nhau, ta có :
\(\frac{x^2}{25}=\frac{y^2}{4}=\frac{x^2+y^2}{25+4}=\frac{133}{29}\)
Suy ra :
+) \(\frac{x^2}{25}=\frac{133}{29}\Leftrightarrow x^2=\frac{3325}{29}\Leftrightarrow x=\sqrt{\frac{3325}{29}}\approx10,7\)
+)\(\frac{y^2}{4}=\frac{133}{29}\Leftrightarrow y^2=\frac{532}{29}\Leftrightarrow y=\sqrt{\frac{532}{29}}\approx4,3\)
Vậy \(x\approx10,7;y\approx4,3\)
TL
12 tháng 3 2017
ta có :
\(\dfrac{bz-cy}{a}=\dfrac{cx-az}{b}=\dfrac{ay-bx}{c}=\dfrac{bxz-cyz}{ax}=\dfrac{cxy-azy}{by}=\dfrac{ayz-bxz}{cz}\)áp dụng tính chất dãy tỉ số bằng nhau, ta có:\(\dfrac{bzx-cyx}{ax}=\dfrac{cxy-azy}{by}=\dfrac{ayz-bxz}{cz}=\dfrac{bzx-cyx+cxy-azy+ayz-bxz}{ax+by+cz}=0\)
suy ra : bz-cy=0 \(\Rightarrow bz=cy\Rightarrow\dfrac{y}{b}=\dfrac{z}{c}\left(1\right)\)
cx-az=0\(\Rightarrow cx=az\Rightarrow\dfrac{x}{a}=\dfrac{z}{c}\left(2\right)\)
ay-bx=0\(\Rightarrow ay=bx\Rightarrow\dfrac{x}{a}=\dfrac{y}{b}\left(3\right)\)
từ (1), (2) và (3) suy ra: \(\dfrac{x}{a}=\dfrac{y}{b}=\dfrac{z}{c}\)
12 tháng 3 2017
Ta có: \(\dfrac{bz-cy}{a}\)= \(\dfrac{cx-az}{b}\)=\(\dfrac{ay-bx}{c}\)
\(\Rightarrow\dfrac{abz-acy}{a^2}=\dfrac{bcx-baz}{b^2}=\dfrac{cay-cbx}{c^2}\)(nhân cả tử và mẫu với mẫu của phân số)
\(=\dfrac{abz-acy+bcx-baz+cay-cbx}{a^2+b^2+c^2}\) (t/c của dãy tỉ số bằng nhau)
(đến đây ta thấy tử = 0 vì chúng là các số đối nhau, abz-baz; acy-cay; bcx-cbx)
\(=\dfrac{0}{a^2+b^2+c^2}\)
\(\Rightarrow\)\(\dfrac{bz-cy}{a}\)= 0 (mà để là một phân số thì mẫu phải khác 0) suy ra a khác 0 vậy bz-cy=0 \(\Rightarrow bz=cy\Rightarrow\dfrac{z}{c}=\dfrac{y}{b}\)(1)
tương tự \(\dfrac{cx-az}{b}\)=0 suy ra \(\dfrac{x}{a}=\dfrac{z}{c}\) từ 1 và 2 suy ra điều phải c/m\(\)
LM
31 tháng 10 2017
1,
a) 3,2x +(-12)x +2,7=-4,9 b)-5,6x+2,9x-3,86=-9,8
=>3,2x+(-12)x=-4,9-2,7 =>-5,6x+2,9x=-9,8+3,86
=>3,2x+(-12)x=-7,6 =>-5,6x+2,9x=-5,94
=>x[3,2+(-12)]=-7,6 =>x[(-5,6)+2,9]=-5,94
=>2x=-7,6=>x=-7,6:2=-3,8 =>-2,7x=-5,94=>x=(-5,94):(-2,7)=2,2
CL
12 tháng 10 2017
Gọi \(A=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+...+\dfrac{1}{x}=\dfrac{1023}{1024}\)
\(A=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+\dfrac{1}{2^4}+...+\dfrac{1}{x}=\dfrac{1023}{1024}\)
VẬy x là một lũy thừa của 2. Đặt x = 2y , ta có:
\(A=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+\dfrac{1}{2^4}+...+\dfrac{1}{2^y}\)
\(\Rightarrow2A=1+\dfrac{1}{2^2}+\dfrac{1}{2^3}+\dfrac{1}{2^4}+...+\dfrac{1}{2^{y-1}}\)
\(\Rightarrow2A-A=1+\dfrac{1}{2}-\dfrac{1}{2^2}+\dfrac{1}{2^3}-\dfrac{1}{2^4}+...+\dfrac{1}{2^{y-1}}-\left(\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+\dfrac{1}{2^4}+...+\dfrac{1}{2^8}\right)\)
\(=A-\dfrac{1}{2^y}\)
Vậy \(1-\dfrac{1}{2^y}=\dfrac{1023}{1024}\Leftrightarrow\dfrac{1}{2^y}=\dfrac{1}{1024}\Leftrightarrow2^y=1024\Rightarrow x=1024\)
Vậy x = 1024