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\(\left(\frac{2}{3}+\frac{1}{3}:\frac{3}{4}+\frac{5}{9}\right).y-3=25\%+\frac{7}{4}\)
\(\Rightarrow\left(\frac{2}{3}+\frac{4}{9}+\frac{5}{9}\right).y-3=\frac{1}{4}+\frac{7}{4}\)
\(\Rightarrow\left(\frac{2}{3}+1\right).y-3=2\)
\(\Rightarrow\frac{5}{3}.y-3=2\)
\(\Rightarrow y-3=2:\frac{5}{3}\)
\(\Rightarrow y-3=\frac{6}{5}\)
\(\Rightarrow y=\frac{6}{5}+3\)
\(\Rightarrow y=\frac{21}{5}\)
a; 5\(\dfrac{3}{4}\) : 3 + 2\(\dfrac{1}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) : 3 + \(\dfrac{9}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) x \(\dfrac{1}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{12}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{46}{24}\) + \(\dfrac{18}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{64}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{55}{24}\)
1.
\(a,\frac{1}{7}+\frac{3}{4}+\frac{2}{7}+\frac{4}{7}=\frac{1}{7}+\frac{2}{7}+\frac{4}{7}+\frac{3}{4}\)
\(=1+\frac{3}{4}=\frac{7}{4}.\)
\(b,\frac{4}{7}:\frac{2}{5}+\frac{3}{7}:\frac{2}{5}-\frac{7}{9}=\left(\frac{4}{7}+\frac{3}{7}\right):\frac{2}{5}-\frac{7}{9}\)
\(=1:\frac{2}{5}-\frac{7}{9}=\frac{5}{2}-\frac{7}{9}\)
\(=\frac{31}{18}.\)
a)3/4+(1/7+2/7+4/7)
=3/4+1
=7/4
b)2/5:(4/7+3/7)-7/9
=2/5:1-7/9
=2/5-7/9
=-17/45
a) \(\frac{7}{8}\) - \(\frac{1}{3}\) = \(\frac{21}{24}\) - \(\frac{8}{24}\) = \(\frac{13}{24}\)
\(\frac{8}{9}\) + \(\frac{2}{5}\) = \(\frac{40}{45}\) + \(\frac{18}{45}\) = \(\frac{58}{45}\)
\(\frac{3}{10}\) x \(\frac{1}{6}\) = \(\frac{3\times1}{10\times6}\) = \(\frac{3}{60}\) = \(\frac{1}{20}\)
\(\frac{8}{9}\) : \(\frac{3}{7}\) = \(\frac{8}{9}\) x \(\frac{7}{3}\) = \(\frac{56}{27}\)
b) Đổi hỗn số ra phân số rồi làm tương tự câu a)
a, \(\frac{1}{2}x\frac{2}{7}+\frac{3}{7}:2+\frac{1}{2}:\frac{7}{2}\)
= \(\frac{1}{2}x\frac{2}{7}+\frac{3}{7}x\frac{1}{2}+\frac{1}{2}x\frac{2}{7}\)
= \(\frac{1}{2}x\left(\frac{2}{7}+\frac{3}{7}+\frac{2}{7}\right)\)
= \(\frac{1}{2}x1\)
= \(\frac{1}{2}\)
\(a,\frac{1}{2}x\frac{2}{7}+\frac{3}{7}:2+\frac{1}{2}:\frac{7}{2}\)
\(=\frac{1}{2}x\frac{2}{7}+\frac{3}{7}x\frac{1}{2}+\frac{1}{2}x\frac{2}{7}\)
\(=\frac{1}{2}x\left(\frac{2}{7}+\frac{3}{7}+\frac{2}{7}\right)\)
\(=\frac{1}{2}x1\)
\(=\frac{1}{2}\)
\(b,\frac{3}{7}x\frac{3}{5}+\frac{3}{5}:7+\frac{3}{7}:\frac{5}{3}\)
\(=\frac{3}{7}x\frac{3}{5}+\frac{3}{5}x\frac{1}{7}+\frac{3}{7}x\frac{3}{5}\)
\(=\frac{3}{5}x\left(\frac{3}{7}+\frac{1}{7}+\frac{3}{7}\right)\)
\(=\frac{3}{5}x1\)
\(=\frac{3}{5}\)