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\(\frac{64\times50+44\times100}{27\times38+146\times19}\)
\(=\frac{32\times2\times50+44\times100}{27\times38+73\times2\times19}\)
\(=\frac{32\times100+44\times100}{27\times38+73\times38}\)
\(=\frac{\left(32+44\right)\times100}{\left(27+73\right)\times38}\)
\(=\frac{76\times100}{100\times38}\)
\(=\frac{38\times2\times100}{100\times38}\)
\(=2\)
đó là cách thuận tiện nhất
\(\frac{64\times50+44\times100}{27\times38+146\times19}\)
\(=\frac{32\times2\times50+44\times100}{27\times38+73\times2\times19}\)
\(=\frac{32\times100+44\times100}{27\times38+73\times38}\)
\(=\frac{\left(32+44\right)\times100}{\left(27+73\right)\times38}\)
\(=\frac{76\times100}{100\times38}\)
\(=\frac{76}{38}\)
\(=2\)
\(\frac{64\times50+44\times100}{27\times38+146\times19}\)
\(=\frac{64\times50+44\times50\times2}{27\times38+73\times2\times19}\)
\(=\frac{\left(64+44\right)\times50\times2}{27\times38+73\times38}\)
\(=\frac{108\times100}{\left(27+73\right)\times38}\)
\(=\frac{108\times100}{100\times38}\)
\(=\frac{108}{38}\)
\(=\frac{27}{8}\)
ĐỀ bài là : ???
ko có đề bài đồng nghĩa vs việc kết quả = 0
ĐÁP số : 0
\(b=\frac{637.527-189}{526.637+448}\)
\(b=\frac{637.\left(526+1\right)-189}{526.637+448}\)
\(b=\frac{637.526+\left(637-189\right)}{526.637+448}\)
\(b=\frac{637.526+448}{526.637+448}=1\)
Dấu . là nhân nha
\(\frac{64.50+44.100}{27.38+146.19}\)
= \(\frac{32.2.50+44.100}{27.38+73.2.19}\)
= \(\frac{32.100+44.100}{27.38+73.38}\)
= \(\frac{\left(32+44\right).100}{\left(27+73\right).38}\)
= \(\frac{76.100}{100.38}\)
= \(2\)
=13/12x14/13x15/14x16/15x...x2006/2005x2007/2006x2008/2007
=2008/12
=502/3
A = 1\(\dfrac{1}{12}\) \(\times\) 1\(\dfrac{1}{13}\) \(\times\) 1\(\dfrac{1}{14}\) \(\times\) 1\(\dfrac{1}{15}\) \(\times\) ... \(\times\) 1\(\dfrac{1}{2005}\) \(\times\) 1\(\dfrac{1}{2006}\) \(\times\) 1\(\dfrac{1}{2007}\)
A = ( 1 + \(\dfrac{1}{12}\)) \(\times\) ( 1 + \(\dfrac{1}{13}\)) \(\times\) ( 1 + \(\dfrac{1}{14}\)) \(\times\)...\(\times\) ( 1 + \(\dfrac{1}{2006}\))\(\times\)(1+\(\dfrac{1}{2007}\))
A = \(\dfrac{13}{12}\) \(\times\) \(\dfrac{14}{13}\) \(\times\) \(\dfrac{15}{14}\) \(\times\) ...\(\times\) \(\dfrac{2007}{2006}\) \(\times\) \(\dfrac{2008}{2007}\)
A = \(\dfrac{13\times14\times15\times...\times2007}{13\times14\times15\times...\times2007}\) \(\times\) \(\dfrac{2008}{12}\)
A = 1 \(\times\) \(\dfrac{502}{3}\)
A = \(\dfrac{502}{3}\)
a)\(\dfrac{15x14-1}{13x15+14}=\dfrac{15x\left(13+1\right)-1}{13x15+14}\\ =\dfrac{15x13+15-1}{15x13+14}=\dfrac{15x13+14}{15x13+14}=1\)
b) \(\dfrac{2017x2019-1}{2017x2018+2016}=\dfrac{2017x\left(2018+1\right)-1}{2017x2018+2016}\\ =\dfrac{2017x2018+2017-1}{2017x2018+2016}=\dfrac{2017x2018+2016}{2017x2018+2016}=1\)
c) \(\dfrac{637x527-189}{526x637+448}=\dfrac{637x\left(526+1\right)-189}{637x526+448}\\ =\dfrac{637x526+637-189}{637x526+448}=\dfrac{637x526+448}{637x526+448}=1\)
d) \(\dfrac{64x50+44x100}{27x38+146x19}=\dfrac{32x2x50+44x100}{27x38+73x2x19}\\ =\dfrac{32x100+44x100}{27x38+73x38}=\dfrac{100x\left(32+44\right)}{38x\left(27+73\right)}\\ =\dfrac{100x76}{38x100}=\dfrac{76}{38}=2\)