Câu hỏi của Lê Viết Trung

Question

A, 4⁹. 36 + 64 / 16⁴. 100

B, 11 . 3²² . 3 - 9¹³ / ( 2 . 3¹⁴ )²

C, 45³ . 20⁴. 18 / 180

Vy Thị Hoàng Lan ( Toán Học ) · Accepted Answer

$A,\frac{4^9.36+64}{16^4.100}=\frac{\left(2^2\right)^9.2^2.3^2+2^6}{\left(2^4\right)^4.2^2.5^2}=\frac{2^{20}.3^2+2^6}{2^{18}.5^2}=\frac{2^6\left(2^{14}.3^2+1\right)}{2^{18}.5^2}=\frac{2^{14}.3^2+1}{2^{12}.5^2}=\frac{147457}{102400}$

B,

$\frac{11.3^{22}.3-9^{13}}{\left(2.3^{14}\right)^2}=\frac{11.3^{22}-\left(3^2\right)^{13}}{2^2.3^{28}}=\frac{11.3^{22}-3^{26}}{2^2.3^{28}}=\frac{3^{22}\left(11.1-3^4\right)}{2^2.3^{28}}=\frac{11-81}{2^2.3^6}=-\frac{70}{2916}=-\frac{35}{1456}$

c,

$\frac{45^3.20^4.18}{180^5}=\frac{\left(3^2.5\right)^3.\left(5.2^2\right)^4.2.3^2}{\left(2^2.3^2.5\right)^5}=\frac{3^6.5^3.5^4.2^8.2.3^2}{2^{10}.3^{10}.5^5}=\frac{3^8.2^{10}.5^7}{2^{10}.3^{10}.5^5}=\frac{5^2}{3^2}=\frac{25}{9}$

Câu trả lời:

$A,\frac{4^9.36+64}{16^4.100}=\frac{\left(2^2\right)^9.2^2.3^2+2^6}{\left(2^4\right)^4.2^2.5^2}=\frac{2^{20}.3^2+2^6}{2^{18}.5^2}=\frac{2^6\left(2^{14}.3^2+1\right)}{2^{18}.5^2}=\frac{2^{14}.3^2+1}{2^{12}.5^2}=\frac{147457}{102400}$

B,

$\frac{11.3^{22}.3-9^{13}}{\left(2.3^{14}\right)^2}=\frac{11.3^{22}-\left(3^2\right)^{13}}{2^2.3^{28}}=\frac{11.3^{22}-3^{26}}{2^2.3^{28}}=\frac{3^{22}\left(11.1-3^4\right)}{2^2.3^{28}}=\frac{11-81}{2^2.3^6}=-\frac{70}{2916}=-\frac{35}{1456}$

c,

$\frac{45^3.20^4.18}{180^5}=\frac{\left(3^2.5\right)^3.\left(5.2^2\right)^4.2.3^2}{\left(2^2.3^2.5\right)^5}=\frac{3^6.5^3.5^4.2^8.2.3^2}{2^{10}.3^{10}.5^5}=\frac{3^8.2^{10}.5^7}{2^{10}.3^{10}.5^5}=\frac{5^2}{3^2}=\frac{25}{9}$

Bui Huyen · Answer

$\frac{4^9\cdot36+64}{16^4\cdot100}=\frac{2^6\cdot147457}{2^{16}\cdot100}=\frac{147457}{2^{10}\cdot100}$

$\frac{11\cdot3^{22}\cdot3-9^{13}}{2^2\cdot3^{28}}=\frac{3^{23}\left(11-3^3\right)}{2^2\cdot3^{28}}=\frac{-16\cdot3^{23}}{2^2\cdot3^{28}}=\frac{-4}{243}$

$\frac{45^3\cdot20^4\cdot18}{180^5}=\frac{3^8\cdot2^9\cdot5^7}{2^{10}\cdot3^{10}\cdot5^5}=\frac{25}{18}$

Câu trả lời:

$\frac{4^9\cdot36+64}{16^4\cdot100}=\frac{2^6\cdot147457}{2^{16}\cdot100}=\frac{147457}{2^{10}\cdot100}$

$\frac{11\cdot3^{22}\cdot3-9^{13}}{2^2\cdot3^{28}}=\frac{3^{23}\left(11-3^3\right)}{2^2\cdot3^{28}}=\frac{-16\cdot3^{23}}{2^2\cdot3^{28}}=\frac{-4}{243}$

$\frac{45^3\cdot20^4\cdot18}{180^5}=\frac{3^8\cdot2^9\cdot5^7}{2^{10}\cdot3^{10}\cdot5^5}=\frac{25}{18}$

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