
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a; -2\(x\) - 3.(\(x-17\)) = 34 - 2.( - \(x\) + 25)
- 2\(x\) - 3\(x\) + 51 = 34 + 2\(x\) - 50
2\(x\) + 2\(x\) + 3\(x\) = - 34 + 50 + 51
7\(x\) = 67
\(x\) = 67 : 7
\(x\) = \(\dfrac{67}{7}\)
Vậy \(x\) = \(\dfrac{67}{7}\)
b; 17\(x\) + 3.(- 16\(x\) - 37) = 2\(x\) + 43 - 4\(x\)
17\(x\) - 48\(x\) - 111 = 2\(x\) - 4\(x\) + 43
- 31\(x\) - 2\(x\) + 4\(x\) = 111 + 43
- \(x\) x (31 + 2 - 4) = 154
- \(x\) x (33 - 4) = 154
- \(x\) x 29 = 154
- \(x\) = 154 : (-29)
\(x\) = - \(\dfrac{154}{29}\)
Vậy \(x=-\dfrac{154}{29}\)

a, 95-13(2x-1)=30
<=> 13(2x-1)=65
<=> 2x-1=5
<=> 2x=6
<=> x=3
Vậy..
b, x^2 -4 =21
<=> x^2=25
<=> x^2=5^2
=> x=5 hoặc x=-5
Vậy...
c, 136- (3x-1)^3=12^2
<=> (3x-1)^3=-8
<=> (3x-1)^3=(-2)^3
=> 3x-1=-2
<=> 3x=-1
<=> x= -1/3
Vậy...
a) 95 - 13(2x - 1) = 30
13(2x - 1) = 95 - 30
13(2x - 1) = 65
2x - 1 = 65 : 13
2x - 1 = 5
2x = 5 + 1
2x = 6
x = 6 : 2
x = 3
b) x2 - 4 = 21
x2 = 21 + 4
x2 = 25
Vì 52 = 25 => x = 5
c) 136 - (3x - 1)3 = 122
3x - 1 = 122 - 136
3x - 1 = 8
3x = 8 : 1
3x = 8
x = 8 : 3
x = \(\frac{8}{3}\)

a) (x - 1) ( x + 3) = 0
=> x - 1 = 0 => x = 1
=> x + 3 = 0 => x = -3
b) (x - 1) ( x2 + 2) = 0
=> x - 1 = 0 => x = 1
=> x2 + 2 = 0 => x2 = -2 => x ko có giá trị nào thỏa mãn
c) /2x - 5/ = 13
=> 2x - 5 = 13 => 2x = 18 => x = 9
2x - 5 = -13 => 2x = -8 => x = -4
d) tự làm nha!!
t i c k nhé!! 4564567567837656786795764

a, ( x + 1 ) + ( x + 2 ) + ... + ( x + 199 ) = 0
x + 1 + x + 2 + ... + x + 199 = 0
( x + x + ... + x ) + ( 1 + 2 + ... + 199 ) = 0
199x + 19900 = 0
199x = 0 - 19900
199x = -19900
x = -19900 : 199
x = -100
Vậy ...
b, ( x - 30 ) + ( x - 29 ) + ( x - 28 ) = 11
x - 30 + x - 29 + x - 28 = 11
( x + x + x ) - ( 30 + 29 + 28 ) = 11
3x - 87 = 11
3x = 11 + 87
3x = 98
x = \(\frac{98}{3}\)
Vậy ...

13^x . 3 + 4 . 13 = 7
13^x . 13 . (3 + 4) = 7
13^x + 1 . 7 = 7
13^x + 1 = 7/7
13^x+1 = 1
Suy ra x = -1.

Bài 1:
a) (2^9 . 3 + 2^9 . 5) : 2^12
= [2^9 . (3 + 5)] : 2^12
= [2^9 . 8] : 2^12
= [2^9 . 2^3] : 2^12
= 2^12 : 2^12
= 1
b) 13^2 - (5^2 . 4 + 2^2 . 15)
= 13^2 - (5^2 . 4 + 4 . 15)
= 13^2 - [4 . (5^2 + 15)]
= 13^2 - [4 . (25 + 15)]
= 13^2 - [4 . 40]
= 13^2 - 160
= 13^2 - 40^2
= -27^2
= 729
Bài 2:
a) 30 . (2^2 . 15 - x) = 30
2^2 . 15 - x = 30 : 30
2^2 . 15 - x = 1
4 . 15 = 1 + x
60 = 1 + x
=> x = 60 - 1
x = 59
Bài 2:
b) 2^4 . 38 - 2^4 . x = 16
16 . (38 - x) = 16
38 - x = 16 : 16
38 - x = 1
x = 38 - 1
x = 37
c) (7 . x - 11^3) = 2^5 . 5^2 + 200
(7 . x - 11^3) = 2^5 . 5^2 + 5^2 . 2^3
(7 . x - 11^3) = 5^2 . (2^5 + 2^3)
(7 . x - 11^3) = 25 . 40
(7 . x - 1331) = 1000
7 . x = 1000 + 1331
7 . x = 2331
x = 2331 : 7
x = 333.


Bài 2 :
a, \(2^x+2^{x+4}=272\)
\(2^x+2^x.2^4=272\)
\(2^x.\left(1+2^4\right)=272\)
\(2^x.17=272\)
\(2^x=272:17\)
\(2^x=16=2^4\)
\(\Rightarrow x=4\)
1: Bài này hơi khó đó
\(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{1}{x\times\left(x+1\right)\div2}=\frac{2}{9}\)
\(\Rightarrow\frac{1}{6\times\left(6+1\right)\div2}+\frac{1}{7\times\left(7+1\right)\div2}+...+\frac{1}{x\times\left(x+1\right)\div2}=\frac{2}{9}\)
\(\Rightarrow\frac{1}{6\times7\div2}+\frac{1}{7\times8\div2}+...+\frac{1}{x\times\left(x+1\right)\div2}\)
\(\Rightarrow\frac{2}{6\times7}+\frac{2}{7\times8}+...+\frac{2}{x\times\left(x+1\right)}=\frac{2}{9}\)
\(\Rightarrow2\times\left(\frac{1}{6}+\frac{1}{7}-\frac{1}{7}+\frac{1}{8}-\frac{1}{8}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{2}{9}\)
\(\Rightarrow2\times\left(\frac{1}{6}-\frac{1}{x+1}\right)=\frac{2}{9}\)
\(\Rightarrow\left(\frac{1}{6}-\frac{1}{x+1}\right)=\frac{2}{9}\div2\)
\(\Rightarrow\frac{1}{6}-\frac{1}{x+1}=\frac{1}{9}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{18}\)
=> x = 18 - 1
=> x = 17
a)(2x-3):5=13
2x-3=13:5
2x-3=5
2x=5+3
2x=8
x=8:2
x=4
vậy x=4
b) 2|x|-1=2-(-30)
2x-1=2+30
2x-1=32
2x-1=25
x-1=5
x=5+1
x=6
vậy x=6
\(\left(2x-3\right):5=13\)
\(\left(2x-3\right)=13.5\)
\(\left(2x-3\right)=65\)
\(2x=65+3\)
\(2x=68\)
\(x=68:2\)
\(x=34\)
Lười câu b lắm \(sorry\)