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a) \(\frac{3}{2}.\frac{7}{2}+\frac{5}{3}.\frac{1}{2}=\frac{21}{2}+\frac{5}{6}=\frac{63}{6}+\frac{5}{6}=\frac{68}{6}=\frac{34}{3}\)
b) \(\frac{1}{9}.\frac{2}{145}-\frac{13}{3}.\frac{2}{145}+\frac{2}{145}=\frac{2}{145}\left(\frac{1}{9}-\frac{39}{9}+\frac{9}{9}\right)=\frac{2}{145}\left(-29\right)=-0.4\)
c) \(\left(-\frac{91}{12}\right):\frac{15}{7}-\frac{1}{18}:\frac{15}{7}+\frac{20}{9}:\frac{15}{7}=\frac{7}{15}\left(-\frac{91}{12}-\frac{1}{18}+\frac{20}{9}\right)=\frac{7}{15}\left(-\frac{65}{12}\right)=-\frac{91}{36}\)
1/ -7264 + (1543 + 7264)
=-7264 + 1543 + 7264=1543
2/ (144 – 97) – 144
=144-97-144=-97
3/ (-145) – (18 – 145)(Vì có dấu trừ ở trước ngoặc nên p đổi dấu)
=-145-18+145=-18
4/ 111 + (-11 + 27)
=111-11+27=137
1)-7264+(1543+7264)=-7264+1543+7264=1543
2)(144-97)-144=144-97-144=-97
3)(-145)-(18-145)=-145-18+145=-18
4)111+(-11+27)=111-11+27=100+27=127
5)(27+514)-(486-73)=27+514-486-73=541-486-73=55-73=-18
6)(36+79)+(145-79-36)=36+79+145-79-36=145
7)10-[12-(-9-1)]=10-[12+9+1]=10-12-9-1=-12
8)(38-29+43)-(43+38)=38-29+43-43-38=-29
9)271-[(-43)+271-(-17)]=271-[-43+271+17]=271+43-271-17=43-17=26
10)-144-[29-(+144)-(+144)]=-144-[29-144-144]=-144-29+144+144=-29+144=115
1; - 7264 + (1543 + 7264)
= - 7264 + 1543 + 7264
= (-7264 + 7264) + 1543
= 0 + 1543
= 1543
2; (14497) - 144
= 14497 - 144
= 14353
3; (-145).(18145)
= -145.18145
= -2631025
4; 111 + (-11 + 27)
= 111 + 16
= 127
1/ - 7264 + ( 1543 + 7264 )
= - 7264 + 1543 + 7264
= ( - 7264 + 7264 ) + 1543
= 0 + 1543
= 1543
2/ ( 144 - 97 ) - 144
= 144 - 97 - 144
= ( 144 - 144 ) - 97
= 0 - 97
= - 97
3/ ( - 145 ) - ( 18 - 145 )
= - 145 - 18 - 145
= ( - 145 - 145 ) - 18
= ( - 290 ) - 18
= - 308
Thế thôi nhé
1/ - 7264 + ( 1543 + 7264 )
= - 7264 + 1543 + 7264
= ( - 7264 + 7264 ) + 1543
= 0 + 1543
= 1543
K mk nha
1 bài nha
Làm hết chắc mk chết
a,\(\frac{3}{2}\cdot\frac{7}{3}+\frac{4}{3}\cdot\frac{1}{2}\)=\(\frac{7}{2}+\frac{2}{3}\)=\(\frac{25}{6}\)
b,\(\frac{2}{145}\cdot\left(\frac{1}{9}-\frac{13}{3}+1\right)\)=\(\frac{2}{145}.-\frac{29}{9}=-\frac{2}{45}\)
c.\(\frac{15}{7}:\left(-\frac{31}{12}-\frac{1}{18}-\frac{20}{9}\right)\)=\(\frac{15}{7}:\left(-\frac{175}{36}\right)=-\frac{108}{245}\)
\(1\frac{1}{2}.2\frac{1}{3}+1\frac{1}{3}.\frac{1}{2}\)
\(=\frac{3}{2}.\frac{7}{3}+\frac{4}{3}.\frac{1}{2}\)
\(=\frac{7}{2}+\frac{2}{3}\)
\(=\frac{25}{6}\)
\(\frac{1}{9}.\frac{2}{145}-4\frac{1}{3}.\frac{2}{145}+\frac{2}{145}\)
\(=\frac{2}{1305}-\frac{13}{3}.\frac{2}{145}+\frac{2}{145}\)
\(=\frac{2}{1305}-\frac{26}{435}+\frac{2}{145}\)
\(=\frac{-2}{45}\)
\(\left(-2\frac{7}{12}\right):2\frac{1}{7}-\frac{1}{18}:2\frac{1}{7}+2\frac{2}{9}:2\frac{1}{7}\)
\(=\frac{-17}{12}:\frac{15}{7}-\frac{1}{18}:\frac{15}{7}+\frac{20}{9}:\frac{15}{7}\)
\(=\left(\frac{-17}{2}-\frac{1}{18}+\frac{20}{9}\right):\frac{15}{7}\)
\(=\frac{-19}{3}.\frac{7}{15}\)
\(=\frac{-133}{45}\)
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