Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
98 . 28 - (184 - 1)(184 + 1)
=(9.2)8 - (184 )2 + 12
= 188 - 188 + 1
= 1
\(9^8.2^8-\left(18^4-1\right)\left(18^4+1\right)\)
\(=18^8-\left(18^8-1\right)\)
=1
Giải:
a) Sửa đề: 1272 + 146.127 + 732
\(127^2+146.127+73^2=\left(127+7\right)^2=200^2=40000\)
b) \(9^8.2^8-\left(18^4-1\right)\left(18^4+1\right)=18^8-\left(18^4-1\right)^2=18^8-18^8-1=-1\)
c) \(20^2+18^2+16^2+...+4^2+2^2-\left(19^2+17^2+...+3^2+1\right)\)
\(=20^2+18^2+16^2+...+4^2+2^2-19^2-17^2-...-3^2-1\)
\(=\left(20^2-19^2\right)+\left(18^2-17^2\right)+\left(16^2-15^2\right)+...+\left(4^2-3^2\right)+\left(2^2-1\right)\)
\(=20+19+18+17+16+15+...+4+3+2+1\)
\(=\dfrac{\left(20+1\right).20}{2}=210\)
Chúc bạn học tốt!
1) A=19952-1994.1996
=19952-(1995-1)(1995+1)
=19952-(19952-1)
=1
2) B=98.28-(184-1)(184+1)
=(9.2)8-[(184)2-1]
= 188-188+1
=1
3) C=1632+74.163+372
=1632+2.37.163+372
=1632+2.163.37+372
=(163+37)2.2
=80000
a) \(\left(x+y\right)^2-\left(x-y\right)^2=\left(x+y-x+y\right)\left(x+y+x-y\right)=2y\cdot2x=4xy\)
b) \(\left(a+b\right)^3+\left(a-b\right)^3-2a^3\)
\(=a^3+3a^2b+3ab^2+b^3+a^2-3a^2b+3ab^2-b^3-2a^3\)
\(=6ab^2\)
c) \(9^8\cdot2^8-\left(18^4-1\right)\left(18^4+1\right)\)
\(=18^8-\left(18^8-1\right)=1\)
a) \(\left(x+y\right)^2-\left(x-y\right)^2=x^2+2xy+y^2-\left(x^2-2xy+y^2\right)\)
\(=x^2+2xy+y^2-x^2+2xy-y^2\)
\(=\left(x^2-x^2\right)+\left(y^2-y^2\right)+\left(2xy+2xy\right)\)
\(=4xy\)
\(B=9^8.2^8-\left(18^4-1\right).\left(18^4+1\right)\)
\(=18^8-\left(18^8-1\right)\)
\(=18^8-18^8+1=1\)
\(9^8.2^8-\left(18^4-1\right)\left(18^4+1\right)\)
\(=18^8-\left(18^{4.2}-1\right)=18^8-18^8+1=1\)
Chúc bạn học tốt!!!