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gì vậy bạn
bạn đang giải bài toán đấy
à , mà lâu như vậy rồi mà mình không thấy bạn nhắn cho mình
làm sao đấy ?
10 x 5 + 5 x 10
c1 : 10 x (5 + 5)
= 10 x 10
= 100
c2 : (10 + 10) x 5
= 20 x 5
= 100
50 + 10 + 90 + 50 + 30 + 60 + 10 + 70 + 50 + 50
c1 : (50 + 50) + (10 + 90) + (30 + 60 + 10) + (50 + 50) + 70
= 100 + 100 + 100 + 100 + 70
= 100 x 4 + 70
= 400 + 70
= 470
c2: 50 x 4 + (10 + 90) + (70 + 30) + (60 + 10)
= 200 + 100 + 100 + 70
= 200 + 100 x 2 + 70
= 200 + 200 + 70
= 200 x 2 + 70
= 400 + 70 = 470
a) \(\dfrac{6}{13}:\left(\dfrac{1}{2}-x\right)=\dfrac{15}{39}\)
\(\dfrac{1}{2}-x=\dfrac{6}{13}:\dfrac{15}{39}\)
\(\dfrac{1}{2}-x=\dfrac{6}{5}\)
\(x=\dfrac{1}{2}-\dfrac{6}{5}\)
\(x=-\dfrac{7}{10}\)
b) \(3\times\left(\dfrac{x}{4}+\dfrac{x}{28}+\dfrac{x}{70}+\dfrac{x}{130}\right)=\dfrac{60}{13}\)
\(3\times x\times\left(\dfrac{1}{4}+\dfrac{1}{28}+\dfrac{1}{70}+\dfrac{1}{130}\right)=\dfrac{60}{13}\)
\(x\times\left(\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+\dfrac{3}{7\times10}+\dfrac{3}{7\times13}\right)=\dfrac{60}{13}\)
\(x\times\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}\right)=\dfrac{60}{13}\)
\(x\times\left(1-\dfrac{1}{13}\right)=\dfrac{60}{13}\)
\(x\times\dfrac{12}{13}=\dfrac{60}{13}\)
\(x=\dfrac{60}{13}:\dfrac{12}{13}\)
\(x=5\)
a. (45-63+18) x (1+2+3+4+5+6+7+8+9)
= 0 x (1+2+3+4+5+6+7+8+9) = 0
b. 60-61+62-63+64-65+66-67+68-69+70
= 60 + (-61-69)+(62+68)+(-63-67)+(64+66)-65+70
= 60 + (-130)+130+(-130)+130-65-70
= 60 + (-130+130) + (-130+130)-65+70
= 60 - 65 + 70 = 65
\(\frac{1}{2}\)của 10 là 5.
\(\frac{1}{2}\)của 20 là 10.
\(\frac{1}{2}\)của 30 là 15.
\(\frac{1}{2}\)của 40 là 20.
\(\frac{1}{2}\)của 50 là 15.
\(\frac{1}{2}\)của 60 là 30.
\(\frac{1}{2}\)của 70 là 35.
\(\frac{1}{2}\)của 80 là 40.
Bạn lấy số đó chia cho 2 là được.
Tk nhé.
Bài 1:
a; (\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\)) x \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) : \(\dfrac{3}{4}\)
\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) x \(\dfrac{4}{3}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{3}\)
\(\dfrac{1}{4}x\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{8}\)
\(\dfrac{1}{4}\) \(x\)= \(\dfrac{8}{24}\) + \(\dfrac{11}{24}\)
\(\dfrac{1}{4}x=\dfrac{11}{24}\)
\(x=\dfrac{11}{24}:\dfrac{1}{4}\)
\(x=\dfrac{11}{24}\times4\)
\(x=\dfrac{11}{6}\)
b; \(\dfrac{12}{5}:x\) = \(\dfrac{14}{3}\) x \(\dfrac{4}{7}\)
\(\dfrac{12}{5}\) : \(x\) = \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) : \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) x \(\dfrac{3}{8}\)
\(x\) = \(\dfrac{9}{10}\)
1/10 + 2/20 + 3/30 + 4/40 + 5/50 + 6/60 + 7/70 + 8/80 + 9/90
= 1/10 + 1/10 + 1/10 +1/10 + 1/10 + 1/10 + 1/10 + 1/10 + 1/10
= 1/10 x 9
= 9/10
1 đúng nha, thks
a. = 267 + 864 - 263 - 860
= (267 - 263) + (864 - 860)
= 4 + 4
= 8
b. = [(257 + 37) x 35] : 60
= [294 x 35] : 60
= 10290 : 60
= 171,5
Bài làm:
Ta có: \(3\cdot\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{15}\)
\(\Leftrightarrow3x\cdot\left(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}\right)=4\)
\(\Leftrightarrow x\cdot\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}\right)=4\)
\(\Leftrightarrow x\cdot\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}\right)=4\)
\(\Leftrightarrow x\cdot\left(1-\frac{1}{13}\right)=4\)
\(\Leftrightarrow x\cdot\frac{12}{13}=4\)
\(\Rightarrow x=\frac{13}{3}\)
Ta có : \(3\times\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{15}\)
=> \(3\times x\times\left(\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+\frac{1}{130}\right)=4\)
=> \(x\times\left(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}\right)=4\)
=> \(x\times\left(\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+\frac{3}{10\times13}\right)=4\)
=> \(x\times\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}\right)=4\)
=> \(x\times\left(1-\frac{1}{13}\right)=4\)
=> \(x\times\frac{12}{13}=4\)
=> \(x=4:\frac{12}{13}\)
=> \(x=\frac{13}{3}\)
130 đúg O
60+70=130
k nha <3