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a, \(\dfrac{10}{17}\) + \(\dfrac{5}{-13}\) - \(\dfrac{11}{25}\) + \(\dfrac{7}{17}\) - \(\dfrac{8}{13}\)
= ( \(\dfrac{10}{17}\) + \(\dfrac{7}{17}\)) - ( \(\dfrac{5}{13}\) + \(\dfrac{8}{13}\)) - \(\dfrac{11}{25}\)
= \(\dfrac{17}{17}\) - \(\dfrac{13}{13}\) - \(\dfrac{11}{25}\)
= 1 - 1 - \(\dfrac{11}{25}\)
= - \(\dfrac{11}{25}\)
b, 0,3 - \(\dfrac{93}{7}\) - 70% - \(\dfrac{4}{7}\)
= 0,3 - 0,7 - ( \(\dfrac{93}{7}+\dfrac{4}{7}\))
= - 0,4 - \(\dfrac{97}{7}\)
= - \(\dfrac{2}{5}\) - \(\dfrac{97}{7}\)
= - \(\dfrac{499}{35}\)
1,
\(\dfrac{6}{7}\) + \(\dfrac{-5}{8}\) : (-5) -\(\dfrac{3}{16}\) . \(\left(-2\right)^2\)
= \(\dfrac{6}{7}\) + \(\dfrac{-5}{8}\) . \(\dfrac{-1}{5}\) - \(\dfrac{3}{16}\) . 4
= \(\dfrac{6}{7}\) + \(\dfrac{1}{8}\) - \(\dfrac{3}{4}\)
= \(\dfrac{48}{56}\) + \(\dfrac{7}{56}\) - \(\dfrac{42}{56}\)
= \(\dfrac{13}{56}\)
3,
a,\(\dfrac{3}{5}\)x - \(\dfrac{7}{10}\)x = \(\dfrac{-1}{2}\)
x.(\(\dfrac{3}{5}\) - \(\dfrac{7}{10}\)) = \(\dfrac{-1}{2}\)
x.\(\dfrac{-1}{10}\)= \(\dfrac{-1}{2}\)
x =\(\dfrac{-1}{2}\):\(\dfrac{-1}{10}\)
x = 5
c, (2,5x - 3,6) : \(\dfrac{15}{7}\) = -1
( \(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\)) : \(\dfrac{15}{7}\) = -1
\(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\) = -1 . \(\dfrac{15}{7}\)
\(\dfrac{5}{2}\)x - \(\dfrac{18}{5}\) = \(\dfrac{-15}{7}\)
\(\dfrac{5}{2}\)x = \(\dfrac{-15}{7}\) + \(\dfrac{18}{5}\)
\(\dfrac{5}{2}\)x = \(\dfrac{51}{35}\)
x =\(\dfrac{51}{35}\) : \(\dfrac{5}{2}\)
x = \(\dfrac{102}{175}\)
Mình không biết có chỗ nào sai không nữa.
Câu 2
a)
\(135-5\left(x-29\right)=60\)
\(\Leftrightarrow135-5x+145=60\)
\(\Leftrightarrow5x=210\)
\(\Leftrightarrow x=42\)
Vậy x = 42
b)
\(12x-33=3^2.3^3\)
\(\Leftrightarrow12x=3^5+33\)
\(\Leftrightarrow12x=276\)
\(\Leftrightarrow x=23\)
Vậy x = 23
d)
\(5.2^x-17=23\)
\(\Leftrightarrow5.2^x=40\)
\(\Leftrightarrow2^x=8\)
\(\Leftrightarrow x=3\)
Vậy x = 3
Bài 1:
\(5^4.5=5^5\)
Từ đó ta chọn phương án C.\(5^5\)
Bài 2:
a, 135 - 5( x - 29 ) = 60
\(\Rightarrow\) 5( x - 29 ) = 75
\(\Rightarrow\) x - 29 = 15
\(\Rightarrow\) x = 44
Vậy x = 44
b) 12 . x - 33 = \(3^2.3^3\)
\(\Rightarrow\) 12 . x - 33 = 243
\(\Rightarrow\) 12 . x = 276
\(\Rightarrow\) x = 23
Vậy x = 23
c) \(5.2^x-17=23\)
\(\Rightarrow5.2^x=40\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
đây là cách giải của mk:
a, 5(x + 35) = 515
=> x + 35 = 515 : 5
=> x + 35 = 103
=> x = 103 - 35
=> x = 68
b, 12x - 33 = 32 . 33
=> 12x - 33 = 32 + 3
=> 12x - 33 = 35
=> 12x - 33 = 243
=> 12x = 243 + 33
=> 12x = 276
=> x = 276 : 12
=> x = 23
c, 6 . x - 5 = 9
=> 6 . x = 9 + 5
=> 6 . x = 14
=> x = 14 : 6
=> x = \(\frac{2}{3}\)
d, 4(x - 12) + 9 = 17
=> 4(x - 12) = 17 - 9
=> 4(x - 12) = 8
=> 4 . x - 12 = 8
=> 4 . x = 8 + 12
=> 4 . x = 20
=> x = 20 : 4
=> x = 5
a, 5 ( x + 35 ) = 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
b, 12x - 33 = 32 . 33
12x - 33 = 35
12x - 33 = 243
12x = 243 + 33
12x = 276
x = 276 : 12
x = 23
c, 6.x - 5 = 9
6x = 9 + 5
6x = 14
x = 14 : 6
x = \(\frac{7}{3}\)
d, 4.( x - 12 ) + 9 = 17
4 . ( x - 12 ) = 17 - 9
4 . ( x - 12 ) = 8
x - 12 = 8 : 4
x - 12 = 2
x = 2 + 12
x = 14
a/=\(\dfrac{-17}{25}\).(\(\dfrac{20}{33}+\dfrac{13}{3}\))+\(\dfrac{-3}{25}\)
=\(\dfrac{-17}{25}\).\(\dfrac{163}{33}\)+\(\dfrac{-3}{25}\)
=\(\dfrac{-2771}{825}\)+\(\dfrac{-3}{25}\)
=\(\dfrac{-574}{165}\)
KHÔNG BIẾT CÓ ĐÚNG KHÔNG NGHE
a. 3 . 62 . 8 + 2 .17 . 12 + 4 . 6 . 21
= 186 . 8 + 34 . 12 + 24 . 21
= 1488 + 408 + 504
= 1896 + 504
=2400
Quy ước: \(x^0=1\)
Đề bài: \(\left(\dfrac{5}{17}-\dfrac{8}{33}\right)-\left(\dfrac{25}{33}-\dfrac{12}{17}\right)-2023^0\)
\(=\dfrac{5}{17}-\dfrac{8}{33}-\dfrac{25}{33}+\dfrac{12}{17}-1\)
\(=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)-\left(\dfrac{8}{33}+\dfrac{25}{33}\right)-1\)
\(=1-1-1\)
\(=-1\)
=(5/17-8/33)-(25/33-12/17)-2023^0
=5/17-8/33-25/33+12/17-1
=(5/17+12/17)+(-8/33-25/33)-1
=1+(-1)-1
=-1
Nhớ tick cho mình nha pls