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a. (2x-3)2 = 36
(2x-3)2 = 62
=> TH1: 2x - 3 = 6
2x = 9
x = 9/2
TH2: 2x - 3 = -6
2x = -6 + 3
2x = -3
x = -3/2
Vậy x \(\in\){ -3/2 ; 9/2)
Câu b tương tự
a.(2x-3)^2=36
\(\Rightarrow\left(2x-3\right)^2=6^2\)
\(\Rightarrow2x-3=6\)
\(\Rightarrow2x=9\)\(\Rightarrow x=9:2=\frac{9}{2}\)
\(\left(\frac{\frac{17}{24}.9\frac{1}{2}-3\frac{1}{4}.\frac{17}{24}}{3\frac{1}{2}.2\frac{13}{36}+2\frac{13}{36}.2\frac{3}{4}}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{\frac{17}{24}.\left(9\frac{1}{2}-3\frac{1}{4}\right)}{2\frac{13}{36}.\left(3\frac{1}{2}+2\frac{3}{4}\right)}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{\frac{17}{24}.\left(\frac{19}{2}-\frac{13}{4}\right)}{\frac{85}{36}.\left(\frac{7}{2}+\frac{11}{4}\right)}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{\frac{17}{24}.\frac{19.2-13}{4}}{\frac{85}{36}.\frac{7.2+11}{4}}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{\frac{17}{24}.\frac{25}{4}}{\frac{85}{36}.\frac{25}{4}}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{17}{24}:\frac{85}{36}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{17}{24}.\frac{36}{85}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{3}{10}-\frac{1}{2}\right)^{-2}\)
\(=\left(\frac{3-5}{10}\right)^{-2}\)
\(=\left(\frac{-1}{5}\right)^{-2}\)
\(=\frac{1}{\left(-\frac{1}{5}\right)^2}=\frac{1}{\frac{\left(-1\right)^2}{5^2}}=\frac{1}{\frac{1}{25}}=25\)
a) [(3x-39):7] .36 =7236
[ ( 3x - 39 ) : 7 ] = 7236 : 36
[ ( 3x - 39 ) :7 ] = 201
( 3x - 39 ) = 201 . 7
( 3x - 39 ) = 1407
3x = 1407 + 39
3x = 1446
x = 1446 :3
x = 482
\(\text{( 2x-3²)-13=36}\)
\(\text{=) 2x-9-13=36}\)
\(\text{=)2x=36+13+9}\)
\(\text{=)2x=58}\)
\(\text{=)x=29}\)
~ Are you ok , Học tốt ~
Giang ơi nó là 2 + 3 TẤT CẢ MŨ 2 cơ mà
( 2x - 3 )2 = 36 + 13
( 2x - 3 )2 = 49
( 2x - 3 )2 = 72
=> 2x - 3 = 7
2x = 7 + 3
2x = 10
x = 10 : 2
x = 5
HT