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Ta có:
12 . 12 . 12 . 2. 6 = 12 . 12 . 12 . 12 = 124
25 . 5 . 4 . 2 . 10 = 25 . 4 . 2 . 10 . 5 = 100 . 100 = 1002
2. 10 . 10 . 3 . 5. 10 = 10 . 10 . 10 . 2 . 5 . 3 = 10 . 10 . 10 . 10 . 3 = 104 . 3
a,12.12.2.12.6=12.12.12.(2.6)=12.12.12.12=124
b,25.5.4.2.10=(25.4)(5.2.10)=100.100=1002
c,2.10.10.3.5.10=10.10.10.2.5.3=10.10.10.10.3=104.3
1) \(12\cdot12\cdot2\cdot12\cdot6=12\cdot12\cdot12\cdot12=12^4\)
2) \(25\cdot5\cdot4\cdot2\cdot10=\left(25\cdot4\right)\cdot\left(5\cdot2\cdot10\right)=100\cdot100=100^2=10^4\)
3) \(2\cdot10\cdot10\cdot3\cdot5\cdot10=3\cdot10\cdot10\cdot10\cdot10=3\cdot10^4\)
4) \(a\cdot a\cdot a+b\cdot b\cdot b\cdot b=a^3+b^4\)
Viết gọn các biểu thức sau bằng cách dùng lũy thừa
1) 12.12.2.12.6
=> 12 . 12 . 12 . (2 . 6)
= 12 . 12 . 12 . 12 . 12 = 125
2) 25.5.4.2.10
=> ( 25 . 4 ) . ( 2 . 5 . 10 )
= 100 . 100 = 1002
3) 2.10.10.3.5.10
=> ( 2 . 5 ) . 10 . 10 . 10 . 3
= 10 . 10 . 10 . 10 . 3 = 104 . 3
4) a.a.a cộng b.b.b.b
=> a3 + b4
a) \(...=10^5.10^2.10^2=10^9\)
b) \(...=\left(2^2.3\right).\left(2^2.3\right).\left(2^2.3\right).2.3=2^7.3^4\)
c) \(...=5^2.5.2^2.2.2.5=2^4.5^4\)
d) \(...=7.3.2.5.2.5.3.5.2.5=2^33^2.5^4.7\)
a/
\(100000.100.10.10=10^5.10^2.10.10=10^9=2^9.5^9\)
b/
\(12.12.12.6=2^2.3.2^2.3.2^2.3.2.3=2^7.3^4\)
c/
\(25.5.4.2.10=5^2.5.2^2.2.2.5=2^4.5^4\)
d/
\(210.10.3.5.10=21.10.10.3.5.10=3.7.2.5.2.5.3.5.2.5=2^3.3^2.5^4.7\)
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
Giải: (^ là mũ)
a) 3^8 : 3^4 + 2^2 . 2^3
= 6561 : 81 + 4 . 8
= 81 + 32
= 113
Mấy câu sau bn làm tương tự nhé!
b: \(=2^{12}\cdot3^4\cdot\dfrac{3^{10}}{3^{12}\cdot2^{12}}=3^2=9\)
c: \(=\dfrac{7^2\cdot3^2\cdot7\cdot2\cdot5^3}{5^3\cdot7^3\cdot2\cdot3}=\dfrac{3^2}{3}=3\)
d: \(=\dfrac{5^3\cdot3^6\cdot5^4\cdot2^8\cdot3^{16}\cdot2^2}{\left(2^2\cdot3^2\cdot5\right)^5}=\dfrac{5^{10}\cdot3^{22}\cdot2^{10}}{2^{10}\cdot3^{10}\cdot5^5}=3^{12}\cdot5^5\)