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\(240:\left(x-5\right)=22\cdot52-20\)
\(\Leftrightarrow240:\left(x-5\right)=1124\)
\(\Leftrightarrow x-5=\dfrac{60}{281}\)
hay \(x=\dfrac{1465}{281}\)
\(\Leftrightarrow240:\left(x-5\right)=1124\\ \Leftrightarrow x-5=\dfrac{60}{281}\Leftrightarrow x=\dfrac{1465}{281}\)
a, \(15:\left(x+2\right)=3\Leftrightarrow x+2=3\Leftrightarrow x=1\)
b, \(20:\left(x+1\right)=2\Leftrightarrow x+1=10\Leftrightarrow x=9\)
c, \(240:\left(x-5\right)=2^2.5^2-20=80\Leftrightarrow x-5=3\Leftrightarrow x=8\)
d, \(96-3\left(x+1\right)=42\Leftrightarrow3\left(x+1\right)=54\Leftrightarrow x+1=18\Leftrightarrow x=17\)
a) 15 : (x + 2) = 3
x + 2 = 15 : 3
x + 2 = 5
x = 5 – 2 = 3
b) 20 : (1 + x) = 2
1 + x = 20 : 2
1 + x = 10
x = 10 – 1 = 9
c) 240 : (x – 5) = 22.52 – 20
240 : (x – 5) = 4.25 – 20
240 : (x - 5) = 100 – 20
240 : (x - 5) = 80
x – 5 = 240 : 80
x – 5 = 3
x = 3 + 5 = 8
d) 96 - 3(x + 1) = 42
3(x + 1) = 96 – 42
3(x + 1) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 – 1
x = 17
a, Do UCLN là 5 nên a, b chia hết cho 5 => tận cùng là 0 hoặc 5
Ta có 20 = 15 + 5 = 18 + 2=19+1=17+3=16+4=14+6=13+7=12+8=11+9
=> 2 số a và b là 15 và 5 hoặc 5 và 15
Bài sau làm tương tự em nhé :)
\(240:\left(x-5\right)=2^2.5^2-20\)
\(240:\left(x-5\right)=80\)
\(x-5=240:80\)
\(x-5=3\)
\(x=8\)
\(240:\left(x-5\right)=2^2.5^2-20\)
\(240:\left(x-5\right)=4.25-20\)
\(240:\left(x-5\right)=100-20\)
\(240:\left(x-5\right)=80\)
\(x-5=240:80\)
\(x-5=3\)
\(x=3+5\)
\(x=8\)
Ta có: \(240:\left(x-5\right)=2^2\cdot5^2-20\)
\(\Leftrightarrow240:\left(x-5\right)=80\)
\(\Leftrightarrow x-5=3\)
hay x=8
a ) \(15:\left(x+2\right)=3\)
\(\left(x+2\right)=15:3\)
\(x+2=5\)
\(x=5-2\)
\(x=3\)
Vậy \(x=3\)
b) \(20:\left(1+x\right)=2\)
\(\left(1+x\right)=20:2\)
\(1+x=10\)
\(x=10-1\)
\(x=9\)
Vậy \(x=9\)
c) \(240:\left(x-5\right)=2^2.5^2=20\)
\(240:\left(x-5\right)=4.25=20\)
\(240:\left(x-5\right)=100=20\)
\(\Rightarrow\orbr{\begin{cases}240:\left(x-5\right)=100\\240:\left(x-5\right)=20\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\left(x-5\right)=240:100\\\left(x-5\right)=240:20\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x-5=2,4\\x-5=12\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2,4+5\\x=12+5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=7,4\\x=17\end{cases}}\)
Vậy \(x=7,4\)hoặc \(x=17\)
d) \(96-3\left(x+1\right)=12\)
\(3\left(x+1\right)=96-12\)
\(3\left(x+1\right)=84\)
\(\left(x+1\right)=84:3\)
\(x+1=28\)
\(x=28-1\)
\(x=27\)
Vậy \(x=27\)
Chúc bạn học tốt !!!
240.(x-5) = 22.5-20
\(\Rightarrow\)240.(x-5) = 4 . 5 - 20
\(\Rightarrow\)240.(x-5) = 20 - 20
\(\Rightarrow\)240.(x-5) = 0
\(\Rightarrow\)x-5 = 0 : 240
\(\Rightarrow\)x-5 = 0
\(\Rightarrow\)x = 0 + 5
\(\Rightarrow\)x = 5
\(\Rightarrow\)Vậy x = 5
\(\Rightarrow\)240.(x-5)=0
\(\Rightarrow\)x-5= -240
\(\Rightarrow\)x= -240/-5
\(\Rightarrow\)x=48
vậy x=48 k mik nha !
\(240-\left(x+5\right)=137\)
\(x+5=240-137\)
\(x+5=103\)
\(x=103-5=98\)
b) \(\left(2x-10\right)-20=110\)
\(2x-10=110+20\)
\(2x-10=130\)
\(2x=130+10\)
\(2x=140\)
\(x=140:2=70\)
\(a,240-\left(x+5\right)=137\\ x+5=103\\ x=98\\ b,\left(2x-10\right)-20=110\\ 2x-10=130\\ 2x=140\\ x=70\)
`240:(x–5)=22xx52–20`
`240:(x–5)=1144-20`
`240:(x-5)=1124`
`x-5=240:1124`
`x-5=60/281`
`x=60/281 + 5`
`x=1465/281`
240:(x - 5)=1144 - 20
240:(x - 5)=1124
x - 5 =240:1124
x - 5 = 60/281
x = 60/281 + 1405/281
x = 1465/281